[ (  6x - 39) : 3 ] . 28  = 5628

[ ( 6x - 39) : 3 ]            = 5628 :28 

( 6x - 39) : 3             = 201

( 6x - 39)                   = 201 .3

6x  - 39                  = 603

6x                         = 603 + 39

6x                         = 642

x                           = 642 :6

x                          = 107 

  Đúng cho tớ với nhé, cảm ơn cậu nhiều !

[ (  6x - 39) : 3 ] . 28  = 5628

[ ( 6x - 39) : 3 ]            = 5628 :28 

( 6x - 39)                   = 201 .3

6x                         = 603 + 39

x                           = 642 :6

x                          = 107 

\(6x-39=5628:28\)

\(6x-39=201\)

\(6x=201+39\)

\(6x=240\)

\(\Rightarrow x=40\)

\(6x-39=5628:28\)

\(6x-39=201\)

\(6x=201+39\)

\(6x=240\)

\(x=240:6\)

\(x=40\)

6x-39=5628:28

6x-39=201

6x=201+39

6x=240

x=240:6

x=40

Vậy x=40

6x - 39 = \(\frac{5628}{28}\)

6x - 39 = 201

6x = 201 + 39

6x = 240

x = 240 : 6

x = 40

\(\left[\left(6x-39\right):3\right]\cdot28=5628\)

\(\left(6x-39\right):3=5628:28=201\)

\(6x-39=201\cdot3=603\)

\(6x=603+39=642\)

\(x=642:3=214\)

Vậy \(x=214\)

\(\left[\left(6x-39\right):3\right]\cdot28=5628\)

\(\Rightarrow\left(6x-36\right):3=5628:28=201\)

\(\Rightarrow\left(6x-36\right)=21\cdot3\)

\(\Rightarrow6x-36=63\)

\(\Rightarrow6x=63+36\)

\(\Rightarrow6x=99\)

\(\Rightarrow x=16,5\)

mk giải luôn ạ

(6x-39):3=5628:28

(6x-39):3=201

6x-39=201.3

6x-39=603

6x=603+39

6x=642

=>x=107

vậy x=107

Từ biểu thức, suy ra:

[(6x-39)÷3]÷28=5628

<=>(2x-13):28=5628

<=>2x-13=158584

<=>2x=157597

<=>x=78798,5

Vậy x=78798,5

[(6x-39)÷3]÷28=5628

=> [(6x-39):3]= 157584

=> 6x-39=472752

=> 6x=472791

=>x=78798,5

Vậy x= 78798,5

[(6x-39)÷3]÷28=5628

[(6x-39)÷3]=5628\(\times\)28

(6x-39)÷3=157584

(6x-39)=157584\(\times\)3

6x-39= 4727252

6x=472752

x= 472752:6

x=78792

6x - 39 = 201

6x = 201 + 39

6x = 240

x = 240 : 6

x = 40

Vậy x = 40

Chúc bạn học tốt !

a, (2x - 7) - 135 = 0

2x - 7 = 135

2x = 142

x = 71

b, [(6x - 39) : 3] . 28 = 5628

(6x - 39) : 3 = 201

6x - 39 = 603

6x = 642

x = 107

(2x-7) - 135 = 0

=> 2x - 7 = 135

=> 2x = 142

=> x = 71

[(6x - 39) : 3] . 28 = 5628

=> (6x - 39)  : 3 = 201

=> 6x - 39 = 603

=> 6x = 642

=> x = 107 

a, ( 2x - 7 ) - 135 = 0

=> ( 2x - 7 ) = 135

 2x = 135 + 7 = 142

  x = 142 : 2 = 71

b,[ ( 6x - 39 ) : 3 ] . 28 = 5628

             ( 6x - 39 ) : 3 = 5628 : 28 = 201

              6x - 39         = 201 . 3 = 603

                   6x          = 603 + 39 = 642

                      x         = 642 : 6 = 107

a: Ta có: \(\left[\left(6x-39\right):3\right]\cdot28=5628\)

\(\Leftrightarrow\left(6x-39\right):3=201\)

\(\Leftrightarrow6x-39=603\)

\(\Leftrightarrow6x=642\)

hay x=107

b: Ta có: \(4x^3+12=120\)

\(\Leftrightarrow4x^3=108\)

\(\Leftrightarrow x^3=27\)

hay x=3

c: Ta có: \(1500:\left[\left(30x+40\right):x\right]=30\)

\(\Leftrightarrow\left(30x+40\right):x=50\)

\(\Leftrightarrow30x+40=50x\)

hay x=-2