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Nguyễn Thanh Hiền
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Võ Đông Anh Tuấn
2 tháng 12 2016 lúc 9:39

a ) \(x^3-7x-6=x^3-x-6x-6=x^3-x-6\left(x+1\right)\)

\(=x\left(x^2-1\right)-6\left(x+1\right)=\left(x+1\right)\left[x\left(x-1\right)-6\right]\)

\(=\left(x+1\right)\left[\left(x^2-x-6\right)\right]=\left(x+1\right)\left[\left(x^2+2x-3x-6\right)\right]\)

\(=\left(x+1\right)\left[x\left(x+2\right)-3\left(x+2\right)\right]=\left(x+1\right)\left(x+2\right)\left(x+3\right)\)

b )

\(x^3-19x-30=\left(x^3-9x\right)-\left(10x+30\right)=x\left(x^2-9\right)-10\left(x+3\right)\)

\(=\left(x+3\right)\left(x^2-3x-10\right)=\left(x+2\right)\left(x+3\right)\left(x-5\right)\)

c )

\(a^3-6a^2+11a-6=\left(a-3\right)\left(a-2\right)\left(a-1\right).\)

 

Thu Thủy vũ
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Dương Lam Hàng
22 tháng 9 2018 lúc 16:13

\(x^3-5x^2-14x\)

\(=x^3+2x^2-7x^2-14x\)

\(=x^2\left(x+2\right)-7x\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2-7x\right)\)

\(=x\left(x+2\right)\left(x-7\right)\)

\(x^3-7x-6\)

\(=x^3+x^2-x^2-x-6x-6\)

\(=x^2\left(x+1\right)-x\left(x+1\right)-6\left(x+1\right)\)

\(=\left(x+1\right)\left(x^2-x-6\right)\)

\(=\left(x+1\right)\left(x^2+2x-3x-6\right)\)

\(=\left(x+1\right)\left[x\left(x+2\right)-3\left(x+2\right)\right]\)

\(=\left(x+1\right)\left(x+2\right)\left(x-3\right)\)

\(x^3-19x-30\)

\(=x^3-5x^2+5x^2-25x+6x-30\)

\(=x^2\left(x-5\right)+5x\left(x-5\right)+6\left(x-5\right)\)

\(=\left(x-5\right)\left(x^2+5x+6\right)\)

\(=\left(x-5\right)\left(x^2+2x+3x+6\right)\)

\(=\left(x-5\right)\left[x\left(x+2\right)+3\left(x+2\right)\right]\)

\(=\left(x-5\right)\left(x+3\right)\left(x+2\right)\)

Phạm Ngọc Diệp
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Ngọc Nguyễn
2 tháng 7 2019 lúc 20:24

a) a4 + a2 - 2

a4 + 2a2 - a2 - 2

a2.( a2 + 2 ) - ( a2 + 2 )

( a2 - 1 ).( a2 + 2 )

( a + 1 ).( a - 1 ).( a2 +2 )

b) x4 + 4x2 - 5

x4 + 5x2 - x2 - 5

x2.( x2 + 5 ) - ( x2 + 5 )

( x2 - 1 ).( x2 + 5 )

( x + 1 ).( x - 1 ).( x2 + 5 )

c) x3 - 19x - 30

x3 + 2x2 - 2x2 + 4x - 15x - 30

x2( x + 2 ) - 2x.( x + 2 ) - 15.( x + 2 )

( x + 2 ).( x2 - 2x - 15 )

d) x3 - 7x - 6

x3 - 3x2 + 3x2 - 9x + 2x - 6

x2.( x - 3 ) + 3x.( x - 3 ) + 2.( x - 3 )

( x - 3 ).( x2 + 3x +2 )

( x - 3 ).( x2 + 2x + x + 2 )

( x - 3 ).( x.( x + 2 ) + ( x + 2 )

( x + 1 ).( x + 2 ).( x - 3 )

e) x3 - 5x2 - 14x

x3 - 7x2 + 2x2 - 14x

x2.( x - 7 ) + 2x.( x - 7 )

( x - 7 ).( x2 + 2x )

x.( x + 2 ).( x - 7 )

Angel
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shitbo
10 tháng 12 2018 lúc 20:53

\(x^2-x-6=x^2+2x-3x-6=x\left(x+2\right)-3\left(x+2\right)=\left(x-3\right)\left(x+2\right)\)

\(x^3-19x-30=x^3+6x-25x-30=x\left(x^2-25\right)+6x-30=x\left(x^2-25\right)+6\left(x-5\right)\)

\(=x\left(x-5\right)\left(x+5\right)+6\left(x-5\right)=\left(x-5\right)\left[\left(x\right)\left(x+5\right)+6\right]\)

Nguyen Thi Thu Trang
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ran mori
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Ben 10
23 tháng 8 2017 lúc 21:58

x^3-19x-30 
=x^3-25x+6x-30 
=x(x^2-25)+6(x-5) 
=x(x+5)(x-5)+6(x-5) 
=(x-5)(x^2+5x+6) 
=(x-5)(x^2+2x+3x+6) 
=(x-5)[x(x+2)+3(x+2)] 
=(x-5)(x+2)(x+3)

Lê Anh Tú
23 tháng 8 2017 lúc 21:56

\(x^3-19x-30=x^3+2x^2-2x^2-4x-15x-30\)

\(\Rightarrow x^2\left(x+2\right)-2x\left(x+2\right)-15\left(x+2\right)\)

\(\Rightarrow\left(x+2\right)\left(x^2-2x-15\right)\)

\(\Rightarrow\left(x+2\right)\left(x+3\right)\left(x-5\right)\)

uzumaki naruto
23 tháng 8 2017 lúc 21:58

x^3 + 3x^2 - 3x^2 - 9x - 10x - 30

= x^2 ( x+3) - 3x ( x +3) -10(x+3)

=(x^2 -3x - 10)(x+3) 

=(x^2 - 5x + 2x -10)(x+3)

 =[x(x-5)+2(x-5)](x+3)

=(x-5)(x+2)(x+3)

trần thảo ly
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Minh Triều
25 tháng 7 2015 lúc 18:17

\(a,x^2-5=x^2-\left(\sqrt{5}\right)^2=\left(x-\sqrt{5}\right)\left(x+\sqrt{5}\right)\)

\(b,x^4+x^3+x+1=x^3.\left(x+1\right)+\left(x+1\right)\)

\(=\left(x+1\right).\left(x^3+1\right)=\left(x+1\right)\left(x+1\right)\left(x^2-x+1\right)\)

\(=\left(x+1\right)^2\left(x^2-x+1\right)\)

\(c,x^3-19x-30=x^3-25x+6x-30\)

\(=x.\left(x^2-25\right)+6.\left(x-5\right)\)

\(=x.\left(x-5\right)\left(x+5\right)+6.\left(x-5\right)\)

\(=\left(x-5\right).\left[x\left(x+5\right)+6\right]\)

\(=\left(x-5\right).\left(x^2+5x+6\right)\)

\(=\left(x-5\right).\left(x^2+2x+3x+6\right)\)

\(=\left(x-5\right)\left[x.\left(x+2\right)+3.\left(x+2\right)\right]\)

\(=\left(x-5\right)\left(x+2\right)\left(x+3\right)\)

le vi dai
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Nguyễn Như Nam
1 tháng 8 2016 lúc 12:46

Đề sai rồi nhé .... Bấm máy tính là biết.

Tiffany Hwang
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o0o I am a studious pers...
19 tháng 6 2016 lúc 20:25

a) \(x^2-x-2=x^2+x-2x-2=x\left(x+1\right)-2\left(x+1\right)\)

\(=\left(x+1\right)\left(x-2\right)\)

Nguyễn Hoàng Tiến
19 tháng 6 2016 lúc 20:25

a) \(x^2-x-2=x^2-2x+x-2=x\left(x-2\right)+\left(x-2\right)=\left(x-2\right)\left(x+1\right)\)

b) \(x^3-19x-30==x^3+2x^2-2x^2-4x-15x-30=x^2\left(x+2\right)-2x\left(x+2\right)-15\left(x+2\right)\)

\(=\left(x+2\right)\left(x^2+2x-15\right)=\left(x+2\right)\left(x-3\right)\left(x+5\right)\)

c) \(x^3-6x^2+11x-6=x^3-x^2-5x^2+5x+6x-6=x^2\left(x-1\right)-5x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x-2\right)\left(x-3\right)\)

Trà My
19 tháng 6 2016 lúc 20:42

a)x2-x-2=x2-2x+x-2=x(x-2)+(x-2)=(x-2)(x+1)

b)x3-19x-30=x3+2x2-2x2-4x-15x-30=x2(x+2)-2x(x+2)-15(x+2)=(x2-2x-15)(x+2)=(x2+3x-5x-15)(x+2)=[x(x+3)-5(x+3)](x+2)=(x-5)(x+3)(x+2)=(x-5)(x+2)(x+3)

c)x3-6x2+11x-6=x3-x2-5x2+5x+6x-6=x2(x-1)-5x(x-1)+6(x-1)=(x2-5x+6)(x-1)=(x2+x-6x+6)(x-1)=[x(x+1)-6(x+1)](x-1)=(x-6)(x+1)(x-1)=(x-6)(x-1)(x+1)