Trả lời giùm mk vs các bn ạ

(x+3)(x²-16)(x³-8)(x⁴-9)=0

<=>có 4 TH

TH1:x+3=0=>x=-3

TH2:x²-16=0=>x²=16=>x E {-4;4}

TH3:x³-8=0=>x³=8=>x=2

TH4:x⁴-9=0=>x⁴=9(loại)

Tổng các giá trĩ của x là:(-4)+4+2+(3)=0+2+(-3)=2+(-3)=-1

\(\left(x-2\right)\left(x-1\right)\left(x^2+2\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-2=0\\x-1=0\\x^2+2=0\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=2\\x=1\\x^2=-2\left(KTM\right)\end{array}\right.\)

Vậy \(S=\left(1;2\right)\)

a/ \(\Leftrightarrow9x^2=36\)

\(\Leftrightarrow\left[{}\begin{matrix}3x=6\\3x=-6\end{matrix}\right.\)

\(\Leftrightarrow x=\pm2\)

b/ \(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\x+1=0\end{matrix}\right.\) (do \(x^2+\dfrac{1}{2}>0\))

\(\Leftrightarrow x=\pm1\)

c/ Có \(\left|x+4\right|\ge0\forall x\)

=> \(\left|x+4\right|+5\ge5>0\forall x\)

\(\Rightarrow\left|x+4\right|+5=0\left(vô-lí\right)\)

\(\Rightarrow x\in\varnothing\)

d/ \(\sqrt{2x}-3-1=0\)

\(\Leftrightarrow\sqrt{2x}=4\)

\(\Leftrightarrow2x=16\)

\(\Leftrightarrow x=8\)

+) 2x+1=0

=> 2x=-1

=> x=\(-\frac{1}{2}\).

+) 3x-9/2=0

=> 3x=9/2

=> x=9/2 : 3

=> x=\(\frac{3}{2}\).

\(x\in\left\{-\frac{1}{2};\frac{3}{2}\right\}\).

\(\left(x+2\right)^4-4.\left(x+2\right)^2=0\)

\(\left(x+2\right)^2.\left[\left(x+2\right)^2-4\right]=0\)

\(\Rightarrow\left(x+2\right)^2=0\)hoặc    \(\left(x+2\right)^2-4=0\)

\(x+2=0\)hoặc \(\left(x+2\right)^2=4\)

\(x=-2\)hoặc   \(x+2=2\)hoặc   \(x+2=-2\)

\(x=-2\)hoặc    \(x=0\) hoặc \(x=-4\)

(x + 2)⁴ - 4.(x + 2)² = 0

=> (x + 2)² [(x + 2)² - 4] = 0

=> (x + 2)² . (x² + 4x + 4 - 4) = 0

=> (x + 2)² .(x² + 4x) = 0

=> (x + 2)² . x.(x + 4) = 0

=> (x + 2)² = 0 => x + 2 = 0 => x = -2

hoặc x = 0

hoặc x + 4 = 0 => x = -4

                                              Vậy x = {-4;-2;0}