dễ

Gọi A là biểu thức 1 + 2 + ...... + 100 ta được:

= A x ( 13 x 5 x 3 x 37 - 13 x 15 x 37 )

= A x ( 13 x 15 x 37 - 13 x 15 x 37 )

= A x 0

= 0

Vậy ( 1 + 2 + ...... + 100 ) x ( 65 x 111 - 13 x 15 x 37 ) = 0

Nhớ k cho mình nhé! Thank you!!!

mọi người giúp mk vs ngày mai mk phải nộp bài rồi

( 1 + 2 + 3 + ... + 100 ) x ( 65 x 111 - 13 x 15 x 37 ) = ( 1 + 2 + 3 + ... + 100 ) x 0

                                                                            = 0

Ta có:

65 × 111 - 13 × 15 × 37

= 5 × 13 × 3 × 37 - 13 × 3 × 5 × 37

= 0

Vì 0 nhân với bất kì số nào cũng = 0 nên biểu thức trên = 0

\(\left(1+2+3+...+100\right).\left(1^2+2^2+3^3+...+100^2\right).\left(65.111-13.15.37\right)\)

\(=\left(1+2+3+...+100\right).\left(1^2+2^2+3^3+...+100^2\right).\left(7215-7215\right)\)

\(=\left(1+2+3+...+100\right).\left(1^2+2^2+3^3+...+100^2\right).0\)

\(=0\)

\(1999.1999.1998-1998.1998.1999\)

\(=1999.1998.\left(1999-1998\right)\)

\(=1999.1998.1\)

Tham khảo nhé~

13453 nhe

bn oi viet cach lm ra giup mk voi

65*111-13*15*37=0

Suy ra phép tính trên =0

A, 2^10x13+2^10x65/2⁸x104

=2^10x(13+65)/2⁸x4x26

=2¹⁰x78/2⁸x2²x26

=2¹⁰x78/2¹⁰x26

=78/26

=3

b, (1+2+3+...+100)x(1²+2²+3²+...+10²)x(65x111-13.15.37)

=(1+2+3+...+100)x(1²+2²+..+10²)x(7215-7215)

=(1+2+..+100)x(1²+2²+..+10²)x0

=0

Thank you very much!!!

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}=\frac{2^{10}.13+2^{10}.13.5}{2^8.2^2.13.2}\) 

 \(=\frac{2^{10}.13\left(1+5\right)}{2^{10}.13.2}=\frac{2^{10}.13.6}{2^{10}.13.2}=\frac{6}{2}=3\)

\(B=\left(1+2+3+...+100\right)\left(1^2+2^2+3^2+...+100^2\right)\left(65.111-13.15.37\right)\)

\(=\left(1+2+3+...+100\right)\left(1^2+2^2+...+100^2\right)\left(65.111-13.5.3.37\right)\)

\(=\left(1+2+...+100\right)\left(1^2+2^2+...+100^2\right)\left(65.111-65.111\right)\)

\(=\left(1+2+...+100\right)\left(1^2+2^2+...+100^2\right).0\)

\(=0\)

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+100\right)=5750\) 

\(x+1+x+2+x+3+...+x+100=5750\)

\(x+x+x+...+x+1+2+3+...+100=5750\)

\(100x+5050=5750\)

\(100x=5750-5050\)

\(100x=700\)

\(x=700:100\)

\(x=7\)

t_i_c_k cho mình nha ^^

ban kia lam dung roi do 

k tui nha

thanks

2.

\(\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left(65\cdot111-13\cdot15\cdot37\right)\\ =\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left(65\cdot111-13\cdot5\cdot3\cdot37\right)\\=\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left[65\cdot111-\left(13\cdot5\right)\cdot\left(3\cdot37\right)\right]\\ =\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot\left[65\cdot111-65\cdot111\right]\\ =\left(1+2+3+...+100\right)\cdot\left(1^2+2^2+3^2+...+10^2\right)\cdot0\\ =0\)