A, Theo đề ta có 108/12 = 9 ; 91/7 = 13

Vì \(9\le x\le13\) nên \(x\in\left\{9;10;11;12;13\right\}\)

Vậy \(A=\left\{9;10;11;12;13\right\}\)

B, Theo đề ta có -28/4 = -7 ; -21/7 = -3

Vì \(-7\le x\le-3\) nên \(x\in\left\{-7;-6;-5;-4;-3\right\}\)

Vậy E = {-7 ; -6 ; -5 ; -4 ; -3}

a) \(y=\frac{108}{12}\le x\le\frac{91}{7}\Rightarrow9\le x\le13\)=> E = {x\(\in N ; 9\le x\le13\)} => E = {9;10;11;12;13}

b) \(y=\frac{-28}{4}\le x\le\frac{-21}{7}\Rightarrow-7\le x\le-3\)=> Không có số tự nhiên nào thỏa mãn nên E là tập hợp rỗng

\(\Leftrightarrow\dfrac{46}{7}+\dfrac{81}{35}< =x< =\dfrac{49}{36}\)

\(\Leftrightarrow\dfrac{311}{35}< =x< =\dfrac{49}{36}\)

\(\Leftrightarrow x\in\varnothing\)

\(a,\frac{7}{8}-\frac{1}{4}.\frac{5}{2}=\frac{x}{16}\)

    \(\frac{7}{8}-\frac{5}{8}=\frac{x}{16}\)

    \(\frac{2}{8}=\frac{x}{16}\)

    \(\frac{4}{16}=\frac{x}{16}\)

=> X=4

k nha 

mình cần gấp nhé

\(\left(\frac{-2}{3}-\frac{1}{2}\right):\frac{-1}{4}\le x\le\left(\frac{-5}{6}+\frac{2}{\frac{1}{4}}:\frac{-3}{2}\right)\cdot\left(\frac{-7}{\frac{1}{2}}\right)\)

\(taco:\left(\frac{-2}{3}-\frac{1}{2}\right):\frac{-1}{4}=\frac{-7}{6}:\frac{-1}{4}=\frac{14}{3}\)

\(\left(\frac{-5}{6}+\frac{2}{\frac{1}{4}}:\frac{-3}{2}\right)\cdot\left(\frac{-7}{\frac{1}{2}}\right)=\left(\frac{-5}{6}+\frac{-16}{3}\right)\cdot\left(-14\right)=\frac{-37}{6}\cdot\left(-14\right)=\frac{259}{3}\)

TU DO \(=>X=\frac{14}{3};\frac{15}{3};,,,;\frac{259}{3}\)

CHUC BAN HOC TOT :))

\(\frac{3}{7}\cdot15\cdot\frac{1}{3}+\frac{3}{7}\cdot5\cdot\frac{2}{5}\le x\le\left(3\frac{1}{2}:7-6\frac{1}{2}\right)\cdot\left(-2\frac{1}{3}\right)\)

\(\Leftrightarrow\frac{15}{7}+\frac{6}{7}\le x\le-6\cdot\frac{-5}{3}\)

\(\Leftrightarrow3\le x\le10\)

Mà \(x\in Z\)

\(\Rightarrow x\in\left\{4;5;6;7;8;9\right\}\)

bn Quân sai rồi, hỗn số \(15\frac{1}{3}\)chứ có phải \(15.\frac{1}{3}\)đâu???

\(\frac{3}{7}\cdot15\frac{1}{3}+\frac{3}{7}\cdot5\frac{2}{5}\le x\le\left(3\frac{1}{2}:7-6\frac{1}{2}\right)\cdot\left(-2\frac{1}{3}\right)\)

\(\Rightarrow\frac{3}{7}\left(15\frac{1}{3}+5\frac{2}{5}\right)\le x\le\left(\frac{7}{2}:7-\frac{13}{2}\right)\cdot\left(-\frac{7}{3}\right)\)

\(\Rightarrow\frac{3}{7}\left(\frac{46}{3}+\frac{27}{5}\right)\le x\le\left(\frac{7}{14}-\frac{13}{2}\right)\cdot\left(-\frac{7}{3}\right)\)

\(\Rightarrow\frac{311}{35}\le x\le14\)

\(\Rightarrow8,8...\le x\le14\)

Đến đây là tìm x :))