a. \(25.5^3.\frac{1}{625}.5^2=5^2.5^3.\frac{1}{5^4}.5^2=\frac{5^7}{5^4}=5^3\)

b. \(4.32:\left(2^3.\frac{1}{16}\right)=2^2.2^5:2^3:\frac{1}{2^4}=\frac{2^4}{2^4}=1\)

c. \(5^2.3^5.\left(\frac{3}{5}\right)^2=5^2.3^5.3^2.\frac{1}{5^2}==\frac{5^2}{5^2}.3^7=3^7\)

d. \(\left(\frac{1}{7}\right)^2.\frac{1}{7}.49^2=\frac{1}{7^3}.7^4=\frac{7^4}{7^3}=7\)

lười quá, thầy cũng cho mấy dạng này lười đánh máy quá

Bài 1:

a: \(4\cdot64\cdot2^8\)

\(=2^2\cdot2^6\cdot2^8\)

\(=2^{2+6+8}=2^{16}\)

b: \(128\cdot27=2^7\cdot3^3\)

c: \(4\cdot27:\left(3^{11}\cdot\frac19\right)=4\cdot27:3^9=4\cdot\frac{3^3}{3^9}=\frac{4}{3^6}=\left(\frac{2}{3^3}\right)^2\)

Bài 2:

a: \(\left(\frac12\right)^3\cdot4+\frac34\)

\(=4\cdot\frac18+\frac34\)

\(=\frac48+\frac34=\frac48+\frac68=\frac{10}{8}=\frac54\)

b: Sửa đề: \(4^6\cdot\left(\frac12\right)^{12}\)

Ta có: \(4^6\cdot\left(\frac12\right)^{12}\)

\(=\left(2^2\right)^6\cdot\frac{1}{2^{12}}\)

\(=\frac{2^{12}}{2^{12}}=1\)

c: Ta có: \(\left(\frac12\right)^5-1,5^2\)

\(=\frac{1}{32}-\frac94\)

\(=\frac{1}{32}-\frac{72}{32}=\frac{-71}{32}\)

d: \(\frac{14^{16}\cdot35^7}{10^9\cdot7^{22}}\)

\(=\frac{7^{16}\cdot2^{16}\cdot7^7\cdot5^7}{2^9\cdot5^9\cdot7^{22}}\)

\(=\frac{7^{23}}{7^{22}}\cdot\frac{2^{16}}{2^9}\cdot\frac{5^7}{5^9}=7\cdot\frac{2^7}{5^2}=7\cdot\frac{128}{25}=\frac{896}{25}\)

a/

\(9.3^2.\frac{1}{81}.27=\frac{9.3^2.27}{81}=\frac{3^2.3^2.3^3}{3^4}=\frac{3^7}{3^4}=3^3\)

b/

\(4.32:\left(2^3.\frac{1}{16}\right)=4.32:\left(\frac{2^3}{16}\right)=4.32:\left(\frac{2^3}{2^4}\right)=4.32:\frac{1}{2}=4.32.2=4.64=4.4^3=4^4\)

c/

\(3^4.3^5:\frac{1}{27}=3^4.3^5.27=3^4.3^5.3^3=3^{12}\)

d/(ý bạn là (-2)^2 hay -2^2 , mình làm theo cách (-2)^2 nhé!)

\(2^2.4.\frac{32}{\left(-2\right)^2}.2^5=2^2.2^2.\frac{2^5}{2^2}.2^5=2^2.2^2.2^3.2^5=2^{12}\)

giúp minh vớ các bạn

thanks bạn thao minh donna