1089.24350205

65+891+135+909 phần 731-47+69-253 = 2000 phần 500 =4

a)\(48x19+48x115+134x52\)

\(=48x\left(19+115\right)+134x52\)

\(=48x132+132x52\)

\(=132x\left(48+52\right)\)

\(=132x100=13200\)

b)\(27x121-87x27+73x34\)

\(=27x\left(121-87\right)+73x34\)

\(=27x34+73x34\)

\(=34x\left(27+73\right)\)

\(=34x100=3400\)

c)\(125x98-125x46-52x25\)

\(=125x\left(98-46\right)-52x25\)

\(=125x52-52x25\)

\(=52x\left(125-25\right)\)

\(=52x100=5200\)

d)\(136x23+136x17-40x36\)

\(=136x\left(23+17\right)-40x36\)

\(=136x40-40x36\)

\(=40x\left(136-36\right)\)

\(=40x100=4000\)

e)\(17x93+116x83+17x23\)

\(=17x\left(93+23\right)+116x83\)

\(=17x116+116x83\)

\(=116x\left(17+83\right)\)

\(=116x100=11600\)

g)\(19x27+47x81+19x20\)

\(=19x\left(27+20\right)+47x81\)

\(=19x47+47x81\)

\(=47x\left(19+81\right)\)

\(=47x100=4700\)

h)\(87x23+13x93+70x87\)

\(=87x\left(23+70\right)+13x93\)

\(=87x93+13x93\)

\(=93x\left(87+13\right)\)

\(=93x100=9300\)

Mk đã mất công zậy rùi nên mong mọi người k mk nhé

a) = 13400

b) = 4714

c) = 5200

d) = 4000

e) = 11600

g) = 4700

h) = 9300

ban oi giai ra chu

\(C=\frac{65+891+135+909}{731-47+69-253}\)

\(C=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)

\(C=\frac{200+1800}{800-300}\)

\(C=\frac{2000}{500}=4\)

Ta có:

\(C=\frac{65+891+135+909}{731-47+69-253}\)

\(\Leftrightarrow C=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)

\(\Leftrightarrow C=\frac{200+1800}{800-300}\)

\(\Leftrightarrow C=\frac{2000}{500}=4\)

\(A=\frac{65+891+135+909}{731-47+69-253}\)

\(A=\frac{65+135+891+909}{731+69-47-253}\)

\(A=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)

\(A=\frac{200+1800}{800-300}\)

\(A=\frac{2000}{500}=4\)

A = \(\frac{65+891+135+909}{731-47+69-253}\)

A = \(\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)

A = \(\frac{200+1800}{800-300}\)

A = \(\frac{2000}{500}\)

A = 4

\(A=\frac{65+891+135+909}{731-47+69-253}\)

\(A=\frac{5\times13+9\times9\times11+5\times27+9\times101}{17\times43-47+23\times3-11\times23}\)

\(A=\frac{5\times13+5\times27+9\times99+9\times101}{17\times43-47-11\times23+23\times3}\)

\(A=\frac{5\times\left(13+27\right)+9\times\left(99+101\right)}{17\times43-47-23\times\left(11-3\right)}\)

\(A=\frac{5\times40+9\times200}{17\times43-47-23\times8}\)

\(A=\frac{2000}{500}\)

\(A=4\)

no tính nhanh đc rùi! cho mk xin lỗi bn nhiều nha!!!!

\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\)

\(A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\)

\(A=\frac{59}{45}-\frac{14}{15}\)

\(A=\frac{59}{45}-\frac{42}{45}=\frac{17}{45}\)

\(B=\frac{65+891+135+909}{731-47+69-253}\)

\(B=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47+253\right)}\)

\(B=\frac{200+1800}{800-300}=\frac{2000}{500}=4\)

Giải theo cách lớp 5

\(A=\frac{595959}{454545}-\frac{14141414}{15151515}\\ A=\frac{595959:10101}{454545:10101}-\frac{14141414:1010101}{15151515:1010101}\\ A=\frac{59}{45}-\frac{14}{15}=\frac{17}{45}\)

\(B=\frac{65+891+135+909}{731-47+69-253}=\frac{\left(65+135\right)+\left(891+909\right)}{\left(731+69\right)-\left(47-253\right)}=\frac{200+1800}{731+69-47+253}=\frac{200+1800}{500}=\frac{2000}{500}=4\)