1: ĐKXĐ:  \(x\notin\left\{0;3\right\}\)

\(\dfrac{x+3}{x}-\dfrac{x}{x-3}+\dfrac{9}{x^2-3x}\)

\(=\dfrac{x+3}{x}-\dfrac{x}{x-3}+\dfrac{9}{x\left(x-3\right)}\)

\(=\dfrac{\left(x+3\right)\left(x-3\right)-x^2+9}{x\left(x-3\right)}\)

\(=\dfrac{x^2-9-x^2+9}{x\left(x-3\right)}\)

=0

2: ĐKXĐ: \(x\notin\left\{0;1\right\}\)

\(\dfrac{3}{x}-\dfrac{5}{x-1}+\dfrac{3x+2}{x^2-x}\)

\(=\dfrac{3}{x}-\dfrac{5}{x-1}+\dfrac{3x+2}{x\left(x-1\right)}\)

\(=\dfrac{3x-3-5x+3x+2}{x\left(x-1\right)}\)

\(=\dfrac{x-1}{x\left(x-1\right)}=\dfrac{1}{x}\)

1 (  131,4 - 80,8 ) : 2,3 + 21,84 x 2 = 50,6 : 2,3 + 43,68 = 22 + 43,68= 65,68  

65,68 nha 

( 131,4 - 80,8 ) : 2,3 + 21,84 x 2

       50,6         : 2,3 + 21,84 x 2

                22          + 21,84 x 2

                22          + 43,86

                        65,68

\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)\cdot....\cdot\left(1-\frac{1}{2003}\right)\cdot\left(1-\frac{1}{2004}\right)\)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot....\cdot\frac{2002}{2003}\cdot\frac{2003}{2004}\)

\(=\frac{1\cdot2\cdot3\cdot4\cdot....\cdot2002\cdot2003}{2\cdot3\cdot4\cdot5\cdot....\cdot2003\cdot2004}\)

\(=\frac{1}{2004}\)

phân số thứ nhất bằng 0/2 =0

vậy tích đó chắc chắn bằng 0

chuẩn ko mn?

\(\dfrac{5x+5y}{3x-3y}:\dfrac{5x}{x^2-y^2}.\)

\(=\dfrac{5\left(x+y\right)}{3\left(x-y\right)}.\dfrac{\left(x-y\right)\left(x+y\right)}{5x}.\)

\(=\dfrac{x+y}{3}.\dfrac{x+y}{x}.\)

\(=\dfrac{\left(x+y\right)^2}{3x}.\)

ko hiểu

Bài làm

1) 29( 85 - 47 ) + 85( 47 - 29 )

= 29 . 85 - 29 . 47 + 85 . 47 - 29 . 85

= 29 . 85 . ( -29 . 47 + 85 . 47 )

= 29 . 85 . [ 47( -29 + 82 ) ]

= 29 . 85 . ( 47 . 53 )

= 6140315

2) 3 - | x - 7 | = -12

=> | x - 7 | = 3 - ( -12 )

=> | x - 7 | = 15 

=> \(\orbr{\begin{cases}x-7=15\\x-7=-15\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-8\end{cases}}}\)

Vậy x = { 22; -8 } 

Trả lời :

Câu 1.

29 . (85 - 47) + 85 . (47 - 29)

= 29 . 85 - 29 . 47 + 85 . 47 - 85 . 29

= (29 . 85 - 85 . 29) + (85 . 47 - 29 . 47)

= 0 + 2632 

= 2632

Câu 2.

3 - |x - 7| = - 12

=> |x - 7| = 3 - (- 12)

=> |x - 7| = 3 + 12

=> |x - 7| = 15

=> x - 7 = \(\pm15\)

\(\Rightarrow\orbr{\begin{cases}x-7=15\\x-7=-15\end{cases}\Rightarrow\orbr{\begin{cases}x=22\\x=-8\end{cases}}}\)