c = \(\frac{3}{4.6}+\frac{3}{6.8}+\frac{3}{8.10}+\frac{3}{10.12}+\frac{3}{12.14}\)= ?
Tính \(B=\frac{3}{2.4}-\frac{5}{4.6}+\frac{7}{6.8}-\frac{9}{8.10}+\frac{11}{10.12}-...+\frac{2019}{2018.2020}\)
\(B=\frac{3}{2.4}-\frac{5}{4.6}+\frac{7}{6.8}-\frac{9}{8.10}+...+\frac{2019}{2018.2020}\)
\(B=\frac{3}{2.1.2.2}-\frac{5}{2.2.2.3}+\frac{7}{2.3.2.4}-\frac{9}{2.4.2.5}+...+\frac{2019}{2.1009.2.1010}\)
\(B=\frac{1}{4.}.\left(\frac{3}{1.2}-\frac{5}{2.3}+\frac{7}{3.4}-\frac{9}{4.5}+...+\frac{2019}{1009.1010}\right)\)
\(B=\frac{1}{4.}.\left(\frac{3}{1}-\frac{3}{2}-\frac{5}{2}+\frac{5}{3}+\frac{7}{3}-\frac{7}{4}-\frac{9}{4}+\frac{9}{5}+...+\frac{2019}{1009}-\frac{2019}{1010}\right)\)
\(B=\frac{1}{4.}.\left(\frac{3}{1}-4+4-4+4-...+4-\frac{2019}{1010}\right)\)
\(B=\frac{1}{4.}.\left(\frac{3}{1}-\frac{2019}{1010}\right)=\frac{1011}{4040}\)
tính nhanh:\(\frac{2}{2.4}\)+ \(\frac{2}{4.6}\)+\(\frac{2}{6.8}\)+\(\frac{2}{8.10}\)+\(\frac{2}{10.12}\)+\(\frac{2}{12.14}\)
mn giải cách lớp 5 đc ko ạ
\(A=\frac{1}{2.4}\)+\(\frac{1}{4.6}\)\(+\)\(\frac{1}{6.8}\)\(+\)\(\frac{1}{8.10}\)\(+\)\(\frac{1}{10.12}\)\(+\)\(\frac{1}{12.14}\)
=>2A=2(1/2x4+1/4.6+1/6.8+1/8.10+1/10.12+1/12.14)
=> 2A=2/2.4 + 2/4.6 + 2/6.8 + 2/8.10 + 2/10.12 + 2/12.14
=> 2a =1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 + 1/6 - 1/7
=> 2A =1-1/7
=>2A=16/17
=> A= 8/17
Mình chắc chắn . Chúc bạn học tốt
\(A=\frac{1}{2.4}\)\(+\frac{1}{4.6}\)\(+\frac{1}{6.8}\)\(+\frac{1}{8.10}\)\(+\frac{1}{10.12}\)\(+\frac{1}{12.14}\)
\(\Rightarrow2A=2.\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}+\frac{1}{10.12}+\frac{1}{12.14}\right)\)
\(\Rightarrow2A=\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}+\frac{2}{10.12}+\frac{2}{12.14}\)
\(\Rightarrow2A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}+\frac{1}{10}-\frac{1}{12}+\frac{1}{12}-\frac{1}{14}\)
\(\Rightarrow2A=\frac{1}{2}-\frac{1}{14}=\frac{7}{14}-\frac{1}{14}=\frac{6}{14}\)
\(\Rightarrow2A=\frac{6}{14}\)
\(\Rightarrow A=\frac{3}{14}\)
Tính
\(\frac{5}{4.6}\)+\(\frac{5}{6.8}+\frac{5}{8.10}+\frac{5}{10.12}+...+\frac{5}{298.300}\)
\(\frac{5}{4.6}+\frac{5}{6.8}+\frac{5}{8.10}+...+\frac{5}{298.300}\)
\(=\frac{5}{2}\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+....+\frac{1}{298}-\frac{1}{300}\right)\)
\(=\frac{5}{2}\left(\frac{1}{4}-\frac{1}{300}\right)=\frac{5}{2}.\frac{37}{150}=\frac{37}{60}\)
Tìm x biết \(\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}+\frac{1}{10.12}\right)x=1\)
Gọi biều thức trên là A, ta có:
A=(1/2.4+1/4.6+1/6.8+1/8.10+1/10.12)x=2
2A=(2/2.4+2/4.6+2/6.8+2/8.10+2/10.12)x=2
2A=(1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10+1/10-1/12)x=2
2A=(1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10+1/10-1/12)x=2
2A=(1/2-1/12)x=2
2A=5/12x=2
=>A=5/24x=1
=>x=1:5/24=24/5
=>1/2.(5/12).x=1
5/24.x=1
x=1:5/24
x=24/5
lưu ý, 1/2.5/12 là tính xong phần 1/2.4 +...+1/10.12 rùi nhé
giải thj` giải luôn đi, đừng có chần chừ làm j`
Tính:
A=\(\frac{1}{2}.1111-\frac{1}{3}.1111-\frac{1}{6}.1111\)
B=\(\frac{3}{4.6}+\frac{3}{6.8}+\frac{3}{8.10}+.....+\frac{3}{20.22}\)
\(B=\frac{3}{4.6}+\frac{3}{6.8}+\frac{3}{8.10}+...+\frac{3}{20.22}\)
\(=\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}+...+\frac{1}{20.22}\)
\(=\left(\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{20}-\frac{1}{22}\right)\)
\(=\frac{1}{4}-\frac{1}{22}\)
\(=\frac{9}{44}\)
A = 1111 x ( 1/2 - 1/3 - 1/6 )
A = 1111 x 0 = 0
B = 3/4 x 6 + 3/6 x 8 + 3/8 x 10 + ... + 3/20 x 22
B = 3/2 ( 1/4 - 1/6 + 1/6 - 1/8 + ... + 1/20 - 1/22 )
B = 3/2 x ( 1/4 - 1/22 )
B = 3/2 x 9/44 = 27/88
\(A=\frac{1}{2}.1111-\frac{1}{3}.1111-\frac{1}{6}.1111\)
\(A=1111.\left(\frac{1}{2}-\frac{1}{3}-\frac{1}{6}\right)\)=
Cho đa thức N(x) = \(\frac{1}{2.4}x^0+\frac{1}{4.6}x^1+\frac{1}{6.8}x^2+\frac{1}{8.10}x^3+...+\frac{1}{2016.2018}x^n\)
a) Tìm n
b) Tính N(a); N(1)
\(\frac{1.4}{4.6}+\frac{2.5}{6.8}+\frac{3.6}{8.10}+.........+\frac{48.51}{98.100}\)
\(\frac{1.4}{4.6}+\frac{2.5}{6.8}+...+\frac{48.51}{98.100}\)
=> \(\frac{1}{4}.\left(\frac{1.4}{2.3}+\frac{2.5}{3.4}+...+\frac{48.52}{49.50}\right)\)
=> \(\frac{1}{4}.\left(\frac{2.3-2}{2.3}+\frac{3.4-2}{3.4}+...+\frac{49.50-2}{49.50}\right)\)
=> \(\frac{1}{4}.\left(1-\frac{2}{2.3}+1-\frac{2}{3.4}+...+1-\frac{2}{49.50}\right)\)
=> \(\frac{1}{4}.\left[48-2.\left(\frac{1}{2.3}-\frac{1}{3.4}-\frac{1}{49.50}\right)\right]\)
=> \(\frac{1}{4}.\left[48-2.\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{49}-\frac{1}{50}\right)\right]\)
=> \(\frac{1}{4}.\left[48-2.\left(\frac{1}{2}-\frac{1}{50}\right)\right]\)
=> \(\frac{1}{4}.\left[48-2.\frac{12}{25}\right]\)
=> \(\frac{1}{4}.\frac{1176}{25}=\frac{249}{25}\)
Tính
a, 2.4+4.6+6.8+......+100.102
b, 8.10+10.12+12.14+.....+98.100
c, 1.2.3+2.3.4+4.5.6+5.6.7
Đặt A = 8.10 + 10.12 + 12.14 + ....... + 98.100
=> 6A = 8.10.12 - 8.10.12 + 10.12.14 - 10.12.14 + ...... + 98.100.102
=> 6A = 98.100.102
=> A = 98.100.102/6
=> A = 166600
c.1.2.3+2.3.4+4.5.6+5.6.7=6+24+120+210
=30+120+210
=150+210
=360