Tính bằng cách hợp lí nhất : \(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right)\div18\frac{1}{6}}{0,002}\)
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Bài: Tính
a) \(1-2-3+4+5-6-7+...+601-602-603+604\)
b) \(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
1 - 2 - 3 + 4 + 5- 6 - 7 + .... + 601 - 602 - 603 + 604
= (1 - 2 - 3 + 4) + (5 - 6 - 7 + 8) + ... + (601 -602 - 603 + 604)
= 0 + 0 + ... + 0
= 0
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Tính:
\(A=\frac{\left(140\frac{7}{30}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
\(B=\frac{155-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{23}}\)
\(A=\frac{\left(140\frac{7}{30}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
\(A=\frac{\left(\frac{4207}{30}-\frac{1661}{12}\right):\frac{109}{6}}{\frac{1}{500}}\)
\(A=\frac{\left(\frac{4207}{30}-\frac{1661}{12}\right)\times\frac{6}{109}}{\frac{1}{500}}\)
\(A=\left(\frac{4207}{30}-\frac{1661}{12}\right)\times\frac{6}{109}\times500\)
\(A=\frac{109}{60}\times\frac{6}{109}\times500\)
\(A=\frac{1}{10}\times500\)
\(A=50\)
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\(B=\frac{155-\frac{10}{7}-\frac{5}{11}+\frac{5}{23}}{403-\frac{26}{7}-\frac{13}{11}+\frac{13}{23}}\)
\(B=\frac{5\left(31-\frac{2}{7}-\frac{1}{11}+\frac{1}{23}\right)}{13\left(31-\frac{2}{7}-\frac{1}{11}+\frac{1}{23}\right)}\)
\(B=\frac{5}{13}\)
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Bài: Tính
a) \(1-2-3+4+5-6-7+...+601-602-603+604\)
b) \(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
a) 1−2−3+4+5−6−7+...+601−602−603+604
<=>(1-2-3+4)+(5-6-7+8)+....+(601-602-603+604)=0+0+...+0
=0
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\(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right):18\frac{1}{6}}{0.002}\)
\(\frac{\left(140\frac{7}{3}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
\(=\frac{\left(\frac{427}{3}-\frac{1661}{12}\right):\frac{109}{6}}{0,002}\)
\(=\frac{\frac{47}{12}:\frac{109}{6}}{0,002}\)
\(=\frac{\frac{47}{218}}{0,002}\)
\(=\frac{11750}{109}\)
Ủng hộ !
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Tìm x, biết:a) 60%x + 0,4x + x :3 2 b)1-left(5frac{3}{8}+x-7frac{5}{24}right):left(-16frac{2}{3}right)c)3frac{1}{4}x-frac{7}{6}xfrac{-5}{12}+1frac{2}{3}Bài 2: Tính:a) A frac{-45.58-45.42}{2+4+6+...+16+18}b)1-2-3+4+5-6-7+...+601-602-603+604b) frac{left(140frac{3}{7}-138frac{5}{12}right):18frac{1}{6}}{0,002}Bài 3: Cho A và B, biết:Afrac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}} và B frac{4}{35}+frac{4}{63}+frac{4}{99}+frac{4}{143}+frac{4}{195}Hãy so sánh A & B
Đọc tiếp
Tìm x, biết:
a) 60%x + 0,4x + x :3 =2
b)1-\(\left(5\frac{3}{8}+x-7\frac{5}{24}\right):\left(-16\frac{2}{3}\right)\)
c)\(3\frac{1}{4}x-\frac{7}{6}x=\frac{-5}{12}+1\frac{2}{3}\)
Bài 2: Tính:
a) A= \(\frac{-45.58-45.42}{2+4+6+...+16+18}\)
b)1-2-3+4+5-6-7+...+601-602-603+604
b) \(\frac{\left(140\frac{3}{7}-138\frac{5}{12}\right):18\frac{1}{6}}{0,002}\)
Bài 3: Cho A và B, biết:
A=\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\) và B= \(\frac{4}{35}+\frac{4}{63}+\frac{4}{99}+\frac{4}{143}+\frac{4}{195}\)
Hãy so sánh A & B
tính bằng cách hợp lí :
\(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(\left(6-\frac{2}{3}+\frac{1}{2}\right)-\left(5+\frac{5}{3}-\frac{3}{2}\right)-\left(3-\frac{7}{3}+\frac{5}{2}\right)\)
\(=6-\frac{2}{3}+\frac{1}{2}-5-\frac{5}{3}+\frac{3}{2}-3+\frac{7}{3}-\frac{5}{2}\)
\(=\left(6-5-3\right)-\left(\frac{2}{3}+\frac{5}{3}-\frac{7}{3}\right)+\left(\frac{1}{2}-\frac{3}{2}+\frac{5}{2}\right)\)
\(=-2-1+\frac{3}{2}\)
= \(-3+\frac{3}{2}\)
\(=-\frac{3}{2}\)
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Tính bằng cách hợp lí:
a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}\) ( Phép này tính bằng 1 nhưng lại sai mất)
b) \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
c) \(\left(\frac{1}{2}-\frac{2}{3}\right)-\left(\frac{5}{3}-\frac{3}{2}\right)+\left(\frac{7}{3}-\frac{5}{2}\right)\)
Help me!!!!! Nhanh nhé, 15' thui
\(a,=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+-1\)
\(=0\)
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Thực hiện các phép tính bằng cách hợp lí nhất
a) \(\frac{5}{3}+\left\{\frac{-2}{7}\right\}-\left(-1,2\right)\)
b) \(\frac{-4}{9}+\left\{\frac{-5}{6}\right\}-\frac{17}{4}\)
Tính hợp lí:
a) \(A=\left(\frac{3}{4}-\frac{4}{7}-\frac{5}{6}\right):\left(-\frac{3}{10}+\frac{4}{14}-\frac{-5}{12}\right)\left(\frac{1}{12}-\frac{7}{6}\right)\)
b) 123.(-234+4356-2312)+234.(123-2312)-2312.(-234-123)
a: \(A=\dfrac{63-48-70}{84}:\dfrac{-3\cdot84+4\cdot60+5\cdot70}{840}\cdot\dfrac{1-14}{12}\)
\(=\dfrac{-55}{84}\cdot\dfrac{840}{338}\cdot\dfrac{-13}{12}=\dfrac{55}{1}\cdot\dfrac{10}{338}\cdot\dfrac{13}{12}=\dfrac{275}{156}\)
b: \(=-234\cdot123+123\cdot4356-123\cdot2312+234\cdot123-234\cdot2312+2312\cdot234+2312\cdot123\)
\(=123\cdot4356-123\cdot2312+123\cdot2312=123\cdot4356=535788\)
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