2010^2 và 2009.2011 
<=> (2009+1).2010 và 2009.(2010+1) 
<=> 2009.2010+2010 > 2009.2010+2009 
b) phân tích 2^16 - 1 ta được 
2^16-1=(2^8+1)(2^4+1)(2^2+1)(2^2-1)=A 
Vậy B>A 

   tick mik đi rùi mik làm típ câu b cho !!!

b,<

a,>

             Tíck mình nha~~~

a, so sánh: A=2009.2011 và B=2010²

Ta có :

B=2010²

   = 2010 . 2010

  = 2010 . ( 2009 + 1 )

  = 2010 . 2009 + 2010

A = 2009 . 2011

   = 2009 . ( 2010 + 1 )

   = 2009 . 2010 + 2009

Vì 2010 > 2009

= > 2010 . 2009 + 2010 > 2009 . 2010 + 2009

= > B > A

b, so sánh: A=3^450 và B=5^300

Ta có :

A = 3 ⁴⁵⁰

     = 3^3.150

     ⁼ 27 ¹⁵⁰

B = 5³⁰⁰

    =5^2.150

    = 25 ¹⁵⁰

Vì 27 ¹⁵⁰ > 25 ¹⁵⁰

Nên A > B

giải:

A:2009.2011=4040099

B:2010^2=4040100

=>:A<B(mình chắc chắn luôn)

Ta có : A=2009.2011=2009.(2010+1)=2009.2010+2009

           B=2010^2=2010.2010=(2009+1).2010=2009.2010+2010

Vì 2009<2010 => A<B. 

Hoang mai anh làm cách đó ko dc vì nếu số to hơn ko tính dc

A=2009.2011

=2009.(2010+1)

=2009.2010+2009

B=2010²

=2010.2010

=(2009+1).2010

=2009.2010+2010

Vì 2009.2010+2009 < 2009.2010+2010 nên 2009.2011 < 2010² hay A < B

a/ \(2A=2+2^2+2^3+2^4+...+2^{2011}\)

\(A=2A-A=2^{2011}-2^0=2^{2011}-1=B\)

b/ \(A=2009.2011=\left(2010-1\right)\left(2010+1\right)=2010^2-1< B=2010^2\)

c/ 

\(5^{36}=\left(5^3\right)^{12}=125^{12}\)

\(11^{24}=\left(11^2\right)^{12}=121^{12}\)

\(\Rightarrow11^{24}=121^{12}< 125^{12}=5^{36}\)

d/ 

\(625^5=\left(5^4\right)^5=5^{20}\)

\(125^7=\left(5^3\right)^7=5^{21}>5^{20}=625^5\)

e/

\(3^{2n}=\left(3^2\right)^n=9^n\)

\(2^{3n}=\left(2^3\right)^n=8^n< 9^n=3^{2n}\)

f/

\(6.5^{22}>5.5^{22}=5^{23}\)

g/

\(333^{444}=\left(3.111\right)^{444}=3^{444}.111^{444}=\left(3^4\right)^{111}.111^{444}=81^{111}.111^{444}\)

\(444^{333}=\left(4.111\right)^{333}=4^{333}.111^{333}=\left(4^3\right)^{111}.111^{333}=64^{111}.111^{333}\)

\(\Rightarrow333^{444}>444^{333}\)

A = 2009.2011 = (2010-1)(2010 + 1) = 2010² - 1² = 2010² - 1

B = 2010 . 2010 = 2010²

Do 2010²  - 1 < 2010²

< = > A < B 

ta có : 2009.2011=(2009+1).(2011-1)==>>> 2010.2010===>>> 2010.2010=2010.2010=>> 2009.2011=2010.2010

A = 2009 . 2011

= 2009 . (2010 + 1)

= 2009 . 2010 + 2009 . 1

B = 2010 . 2010

= 2010 . (2009 + 1)

= 2010 . 2009 + 2010 . 1

Vì 2009 . 2010 = 2010 . 2009 và 2009 . 1 < 2010 . 1

=> 2009 . 2010 + 2009 . 1 < 2010 . 2009 + 2010 . 1

=> A < B.

a)Ta có :

A=2009.2011=2009.(2010+1)

                     =2009.2010+2009

B=2010^2=2010.2010

                =(2009+1).2010

                =2009.2010+2010

Vì 2009<2010

=> A<B.

b) tương tự 

\(b,A=2015.2017\)

\(=2015.\left(2016+1\right)\)

\(=2015.2016+2015\)

\(B=2016.2016\)

\(=2016.\left(2015+1\right)\)

\(=2016.2015+2016\)

Vì \(2015.2016+2015< 2016.2015+2016\)

\(\Rightarrow A< B\left(đpcm\right)\)

A=2009.2011=2009.(2010+1)=2009.2010+2009

B=2010²=(2009+1).2010=2009.2010+2010

Vì 2009<2010 nên: A<B

<,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,

A nhỏ hơn B

Tick nhé