1+2=
1+3=
1+4=
1+5=
1x1 tỷ=
(1/1x1/2) + (1/2x1/3) + (1/3x1/4) + (1/4x1/5) +....+ (1/72x1/73) =
`@Fù`
`=1/(1×2)+1/(2×3)+1/(3×4)+...+1/(72×73)`
`=1/1-1/2+1/2-1/3+...+1/72-1/73`
`=1-1/73`
`=72/73`
60x(7/12+4/15)
(1-1/2)x(1-1/3)x(1x1/4)x(1/5)
a: \(=60\cdot\dfrac{17}{20}=51\)
b: \(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot\dfrac{4}{5}=\dfrac{1}{5}\)
1/1x1/2+1/2x1/3+1/3x1/4+1/4x1/5+1/5x1/6
= 1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 + 1/5 x 6
= (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + (1/4 - 1/5) + (1/5 - 1/6)
= 1 - 1/6
= 5/6
nha,mơn nhìu
\(\frac{1}{1}x\frac{1}{2}+\frac{1}{2}x\frac{1}{3}+\frac{1}{3}x\frac{1}{4}+\frac{1}{4}x\frac{1}{5}+\frac{1}{5}x\frac{1}{6}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}\)
\(=1-\frac{1}{6}=\frac{5}{6}\)
1+1x1+1
2+2x2+2
3+3-3+3
4-4+4-4
5x5-5x5
1+1+2+3+4+5
1x1x2x3x4x5
*Nhân chia trước,cộng trừ sau.
1 + 1 x 1 +1 = 1 + 1 +1 = 3
2 + 2 x 2 +2 = 2 + 4 + 2 = 8
3 + 3 - 3 + 3 = 6 - 3 + 3 = 6
4 - 4 + 4 - 4 = 0 + 4 - 4 = 0
5 x 5 - 5 x 5 = 25 - 25 =0
1 + 1 + 2 + 3 + 4 + 5 = 16
1 x 1 x 2 x 3 x 4 x 5 = 120
1 + 1 x 1 + 1 = 3
2 + 2 x 2 + 2 = 8
3 + 3 x 3 + 3 = 15
4 - 4 + 4 - 4 = 0
5 x 5 - 5 x 5 = 0
1 + 1 + 2 + 3 + 4 + 5 =16
1 x 1 x 2 x 3 x 4 x 5 = 120
k nh
1 + 1 * 1 + 1 = 1 + 1 + 1 = 3
2 + 2 * 2 + 2 = 2 + 4 + 2 = 8
3 + 3 - 3 + 3 = 6 - 3 + 3 = 3 + 3 = 6
4 - 4 + 4 - 4 = 0 + 4 - 4 = 4 -4 = 0
5 * 5 - 5 * 5 = 25 - 25 = 0
1 + 1 + 2 + 3 + 4 + 5 = 2 + 2 + 3 + 4 + 5 = 4 + 3 + 4 + 5 = 7 + 4 + 5 =11 + 5 = 16
1 * 1 * 2 * 3 * 4 * 5 = 120
Nhớ k cho mk nha !!
1/1x1/2+1/2x1/3+1/3x1/4+...+1/79x1/80
\(\frac{1}{1}\cdot\frac{1}{2}+\frac{1}{2}\cdot\frac{1}{3}+\frac{1}{3}\cdot\frac{1}{4}+...+\frac{1}{79}\cdot\frac{1}{80}\)
\(=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{79\cdot80}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}+...+\frac{1}{79}-\frac{1}{80}\)
\(=1-\frac{1}{80}\)
\(=\frac{79}{80}\)
[1+1/2]x[1+1/3]x[1+1/4]x..................x[1x1/2010]
\(\left(1+\frac{1}{2}\right)\cdot\left(1+\frac{1}{3}\right)\cdot...\cdot\left(1+\frac{1}{2010}\right)\)
\(=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot...\cdot\frac{2011}{2010}\)
\(=\frac{2011}{2}\)
\(=1005,5\)
bài dành cho bạn
lớp 1 : 4+4+? , 8+8=? , 10-5+7=?
lớp 2 : 1+1+1x1=? , ( 1+2+3+...+100)x5=???
lớp 3 : 9365+472+5630-3547=???, 2749x8=??
lớp 4 : 467x474=??? , 1837+286x737=???
lớp 5 : ( 1/2x3+1/3x4+1/4x5...1/28x29)x1 =???
Bài 1:Chứng tỏ:
a)1x1/2+1/2x1/3+1/3x1/4+...+1/99x1/100<1
Tìm y biết 3 x y x (1/1 x 1/2 + 1/2 x 1/3 + 1/3 x 1/4 + 1/4 x 1/5 + 1/5 x 1/6) = 3/4
Ta thấy: 1/1x1/2 = 1/1-1/2 ; 1/2x1/3 = ½-1/3 ; 1/3x1/4=1/3-1/4 ; 1/4x1/5=1/4-1/5 ; 1/5x1/6=1/5-1/6
Nên
1/1 x 1/2 + 1/2 x 1/3 + 1/3 x 1/4 + 1/4 x 1/5 + 1/5 x 1/6 =
1/1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6 = 1/1-1/6= 5/6
Hay 3 x y x 5/6 = 3/4
y x 15/6 = 3/4
y= 3/4 : 15/6
y = 3/10
sợ sai lắm
tinh 1/3-1 x 1/5-1x1/7-1x.......x1/2017-1