Tính\(\frac{10^3+5.10+5^3}{6^33.6+3^3}\)
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tính
\(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
CHỨNG MINH:
\(\frac{10^2+5.10^2+5^3}{6^3+3.6^2+3^3}=\frac{125}{27}\)
(10^2 + 5.10^2 + 5^3):(6^3 + 3. 6^2 + 3^3) = (100 + 500 + 125):(216 + 108 + 27) = 725 : 351 = ... chet cha lon de :D
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1.thực hiện phép tính:
a, 24-{12-[(-10)-(-2)]}
b,2/3+1/3.(-2/3+5/6):2/3
2.tính nhanh:
a,\(-\frac{2}{5}+\left(-\frac{5}{9}+\frac{2}{5}\right)\)
b, 17/13-(4/13 - 11)
c,3/5.18/17+3/5.9/17-3/5.10/17
GIÚP IK GIÚP TUI VỚI! PLEASE
1/
a, 24 - {12 -[(-10)-(-2)]}
=24-{12-(-8)}
=24-20
=4
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b,\(\frac{2}{3}\)+\(\frac{1}{3}\).(\(\frac{-2}{3}\)+\(\frac{5}{6}\)):\(\frac{2}{3}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\).(\(\frac{-4}{6}\)+\(\frac{5}{6}\)):\(\frac{2}{3}\)
=\(\frac{2}{3}\)+\(\frac{1}{3}\).\(\frac{1}{6}\).\(\frac{3}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{18}\).\(\frac{3}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{6}\).\(\frac{1}{2}\)
=\(\frac{2}{3}\)+\(\frac{1}{12}\)
=\(\frac{8}{12}\)+\(\frac{1}{12}\)
=\(\frac{9}{12}\)=\(\frac{3}{4}\)
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2/
a,\(\frac{-2}{5}\)+(\(\frac{-5}{9}\)+\(\frac{2}{5}\))
=\(\frac{-2}{5}\)+\(\frac{-5}{9}\)+\(\frac{2}{5}\)
=(\(\frac{-2}{5}\)+\(\frac{2}{5}\))+\(\frac{-5}{9}\)
= 0+\(\frac{-5}{9}\)
= \(\frac{-5}{9}\)
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Xem thêm câu trả lời
B1: Tính
a) (1/4)44. (1/2)12
b) \(\frac{3^{17}.81^{11}}{27^{10}.9^{15}}
\)
c)\(\frac{14^{16}.21^{32}.35^{48}}{10^{16}.15^{32}.7^{96}}\)
d)\(\frac{\left(5^4-5^3\right)^3}{125^4}\)
e)\(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^3}\)
Tính:
\(a.\frac{8^5.\left(-5\right)^8+\left(-2\right)^5.10^9}{2^{16}.5^7+20^8}\)
\(b.\frac{\left(-0,25\right)^{-5}.9^4.\left(-2\right)^{-3}-2^{-2}.6^9}{2^9.3^6+6^6.40}\)
\(c.\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)^6+8^4.3^5}-\frac{5^{10}.7^3-25^5.49^2}{\left(125.7\right)^3+5^9.14^3}\)
1.Tính lũy thừa sau
\(a.\frac{15^5.10^5}{6^6.25^6}\)
\(b.\frac{\left(5^4-5^3\right)^3}{125^4}\)
a) \(\frac{15^5.10^5}{6^6.25^6}\)= (15.10)^5/(6.25)^6=150^5/150^6=1/150
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\(^{\frac{\left(5^4-5^3\right)^3}{125^4}=\frac{\left[5^3\cdot\left(5-1\right)\right]^3}{\left(5^3\right)^4}=\frac{\left[5^3\cdot4\right]^3}{5^3\cdot4}=\frac{\left(5^3\right)^3\cdot4^3}{5^{12}}=\frac{5^9\cdot4^3}{5^9\cdot5^3}=\frac{4^3}{5^3}}\)
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Rút gọn biểu thức:
1) \(\frac{10^3+5.10^2+5^3}{6^3+3.6^2+3^2}\)
2) \(\frac{5^3+5.5^2}{-8}\)
Giúp mik nhé!!!
1) Sửa đề :
\(\frac{10^3+5\cdot10^2+5^3}{6^3+3\cdot6^2+3^3}=\frac{10^3+5\cdot5^2\cdot2^2+5^3}{6^3+3\cdot2^2\cdot3^2+3^3}=\frac{5^3\cdot\left(2^3+2^2+1\right)}{3^3\cdot\left(2^3+2^2+1\right)}=\frac{5^3}{3^3}\)
2) Sửa đề :
\(\frac{5^3+3\cdot5^2}{-8}=\frac{5^2\cdot\left(5+3\right)}{-8}=\frac{-5^2\cdot8}{8}=-5^2=-25\)
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1. thực hiện phép tính:
a,\(\left(\frac{-1}{6}+\frac{5}{12}\right)+\frac{7}{12}\)
b,7/36-8/-9+-2/3
c,3/5-2/5.10/12
d,2/(-3)^2+5/-12- -3/4
thực hiện phép tính
A=\(\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
B=\(\frac{8^5.5^8-2^5.10^9}{2^{16}.5^7+20^8}\)
C=\(\frac{4^5.9^4-2.6^4}{2^{10}.3^8+6^8.2^0}\)
ban nao co chuyen shin ko cho minh muon minh giai cho 10 bai nhu the i love pac pac
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\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)
\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)
\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)
\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)
\(A=\frac{4-1}{36+12}\)
\(A=\frac{3}{48}=\frac{1}{16}\)
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