tìm x
a ,x-7/4+x-6/3+x-5/3+x+81/7=0
b,x-1/2013+x-2/2012+x+3/2011+...+x-2012/2=2012
c(1/1x101=1/2x102+1/3x103+1/4x164+1/10x110)x X =(1/1x11+1/2x12+...+1/100x110)
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Những câu hỏi liên quan
Tìm X biết (1/1x101+1/2x102+...+1/10x110)xX=1/1x11+1/2x12+...+1/100x110)
a) Tính hợp lí các tổng sau:
S1: 1/14+1/35+1/65+.....+1/350
S2: 1/3+1/32+1/33+1/34+.....+1/3300
S3:1/1x3x5+1/3x5x7+1/5x7x9+....+1/25x27x29
S4:1+1/2+1/4+1/8+....+1/1024
b) Tìm x biết
(1/1x101+1/2x102+....+1/10x110)x=1/1x11+1/2x12+...+1/100x110
Câu1
( x-7/4)+( x-6/3)+( x-5/2)+( x+81/7)=0
Câu2
( 1/1×101)+( 1/2×102)+( 1/3×103)+(1/10×11×X=(1/1×11)+(1/2×12)+...+(1/100×110)
Câu3
( x-1/2013)+( x-2/2012)+( x-3/2011)+...+( x-2012/2) =2012
tìm số tự nhiên x , bt 1 ) 65 - 5( 2x+6)= 25 2) 265 :[12-(x+3)] = 64 3) ( 2x - 1 )^4 = 81 4) 3^x+2013 : 27 = 3 ^ 2012 5) 28 x 2 ^ x+1 - 22.2^x+1 = 96 6) 2^3.(x-1)^3 = 512 7) 20 chia hết ( x-3) và 42 chia hết cho ( x-3) 8) (x-5) chia hết cho 6 ,( x-5) chia hết cho 8 , (x+5) chia hết cho 20 và 0 x 150 9) ( x+ 2) + (x+12) + ( x + 42 ) + ( x + 47) =655 10 ) x+ ( x+1) +(x+2) +...+ ( x+2008) = 2008.2009 11) 1+2+3+...+x=820
Xem chi tiết
1: =>5(2x+6)=40
=>2x+6=8
=>2x=2
=>x=1
2: =>12-(x+3)=256:64=4
=>(x+3)=8
=>x=5
3: =>2x-1=3 hoặc 2x-1=-3
=>x=2 hoặc x=-1
4: \(\Leftrightarrow3^{x+2017}=3^{2015}\)
=>x+2017=2015
=>x=-2
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1: =>5(2x+6)=40
=>2x+6=8
=>2x=2
=>x=1
2: =>12-(x+3)=256:64=4
=>(x+3)=8
=>x=5
3: =>2x-1=3 hoặc 2x-1=-3
=>x=2 hoặc x=-1
4:
=>x+2017=2015
=>x=-2
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a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
a) x+2/x-2-1/x=2/x*(x-2)
b)2/2x-6+2/2x+2+2x/(x+1)*(3-x)=0
c) x+1/2017+x+2/2016=x+3/2015+x+4/2014
d) x-45/5+x-44/6+x-43/7+x-42/8=4
e) x-3/2011+x+2/2012=x-2012/2+x-2011/3
a) ĐKXĐ: \(x\notin\left\{0;2\right\}\)
Ta có: \(\dfrac{x+2}{x-2}-\dfrac{1}{x}=\dfrac{2}{x\left(x-2\right)}\)
\(\Leftrightarrow\dfrac{x\left(x+2\right)}{x\left(x-2\right)}-\dfrac{x-2}{x\left(x-2\right)}=\dfrac{2}{x\left(x-2\right)}\)
Suy ra: \(x^2+2x-x+2-2=0\)
\(\Leftrightarrow x^2+x=0\)
\(\Leftrightarrow x\left(x+1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x+1=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\left(loại\right)\\x=-1\left(nhận\right)\end{matrix}\right.\)
Vậy: S={-1}
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tìm x,biet(1/2+1/3+.............+1/2012+1/2013).x=2012/1+2011/2+2010/3+......+2/2011+1/2012
Tìm x biết (1/2+1/3+...+1/2012+1/2013).x = 2012/1+2011/2+2010/3+...+2/2011+1/2012
a) 2x-1/11+2x-2/12+2x-3/13=2x+5/5+2x+6/4+2x+7/3
b) x-1/2016+x-2/2015+x-3/2014+x-4/2013+x-5/2012 -5=0
c) x+2017/2+x+2015/3+x+2013/4+x+2011/5+8=0
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