\(\frac{23^{10}-23^{11}}{23^{11}+21.23^{10}}\)
NHANH MK TICK CHO
\(\frac{23^{10}-23^{11}}{23^{11}+21.23^{10}}\)
\(=\frac{23^{10}\left(1-23\right)}{23^{10}\left(23+21\right)}=\frac{-22}{44}=\frac{-1}{2}\)
\(\frac{23^{10}-23^{11}}{23^{11}+21.23^{10}}\)
\(=\frac{23^{10}.\left(1-23\right)}{23^{10}.\left(23+21\right)}\)
\(=\frac{-22}{44}=\frac{-22}{22.2}=\frac{-1}{2}\)
\(\frac{23^{10}-23^{11}}{23^{11}+21.23^{10}}=\frac{23^{10}-23^{10}.23}{23^{10}.23+21.23^{10}}\)\(=\frac{23^{10}(1-23)}{23^{10}(23+21)}=\frac{-22}{44}=\frac{-1}{2}\)
tính giá trị biểu thức:A=[(11,81+8,19).0,02]:[(-9):11,25]:23^10-23^11/23^11+21.23^10
Câu 1: Thực hiện phép tính
a) A= 1.2.3...9-1.2.3...8-1.2.3...8\(^2\)
Câu 2 : Tính nhanh
[(11,81+8,19).0,02] : [(-9):11.25]:\(\frac{23^{10}-23^{11}}{23^{11}+21.23^{10}}\)
Câu 1 :
A= 1.2.3...9-1.2.3...8-1.2.3...82
= 1.2.3...8. ( 9 - 1 - 8 )
= 1.2.3...8.0
= 0
Tính nhanh:
A=(19-3/11+9/23)-(6+7/11-15/23)-(8-10/11+1/23)
mn giúp mk nha!Thank
1> tính nhanh
a) 2013 . 2014 - 2/ 2012 + 2012 . 2014
b) 1984 . 1985 + 1986 . 20 + 1965/ 1985 . 2000 - 1984 . 1985
c) 23 mũ 10 - 23 mũ 11/ 23 mũ 11 + 21 . 23 mũ 10
nhanh nha mk đang cần gấp
a, 1
b, \(\frac{2005}{16}\)
c, \(\frac{-1}{2}\)
\(\frac{-11}{23}.\frac{10}{-13}+\frac{11}{-13}.\frac{-3}{23}-\left(\frac{-12}{23}\right)\)
110/299+33/299+12/23
143/299+12/23
1
=\(\frac{-11}{23}\)\(\times\)\(\frac{10}{-13}\)\(+\)\(\frac{11}{-13}\)\(\times\)\(\frac{-3}{23}\)\(+\)\(\frac{12}{23}\)
=\(\frac{110}{299}\)\(+\)\(\frac{33}{299}\)\(+\)\(\frac{12}{23}\)
=\(\frac{143}{299}\)\(+\)\(\frac{12}{23}\)
= 1
Điền dấu <, >, = vào ô trống:
23 + 23 – 11.... 22 + 22 – 10
56 + 21 – 15 .... 21 + 56 – 15
44 + 44 – 22 .... 46 + 41 – 26
ai nhanh nhất và đúng mk tick cho người đó nha
Điền dấu <, >, = vào ô trống:
23 + 23 – 11..>.. 22 + 22 – 10
56 + 21 – 15 ..=.. 21 + 56 – 15
44 + 44 – 22 .>... 46 + 41 – 26
~ HOK TỐT ~
23 + 23 – 11...>. 22 + 22 – 10
56 + 21 – 15 ..<.. 21 + 56 – 15
44 + 44 – 22 ..>.. 46 + 41 – 26
\(23+23-11>22+22-10\)
\(56+21-15=21+56-15\)
\(44+44-22>46+41-26\)
Tính nhanh:
a)\(\frac{{13}}{{23}}.\frac{7}{{11}} + \frac{{10}}{{23}}.\frac{7}{{11}};\)
b) \(\frac{5}{9}.\frac{{23}}{{11}} - \frac{1}{{11}}.\frac{5}{9} + \frac{5}{9}\)
c)\(\left[ {\left( { - \frac{4}{9}} \right) + \frac{3}{5}} \right]:\frac{{13}}{{17}} + \left( {\frac{2}{5} - \frac{5}{9}} \right):\frac{{13}}{{17}};\)
d) \(\frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{3}{{11}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{2}{5}} \right)\)
a)
\(\begin{array}{l}\frac{{13}}{{23}}.\frac{7}{{11}} + \frac{{10}}{{23}}.\frac{7}{{11}}\\ = \frac{7}{{11}}.\left( {\frac{{13}}{{23}} + \frac{{10}}{{23}}} \right)\\ = \frac{7}{{11}}.\frac{23}{23}\\ = \frac{7}{{11}}.1\\ = \frac{7}{{11}}\end{array}\)
b)
\(\begin{array}{l}\frac{5}{9}.\frac{{23}}{{11}} - \frac{1}{{11}}.\frac{5}{9} + \frac{5}{9}\\ = \frac{5}{9}.\left( {\frac{{23}}{{11}} - \frac{1}{{11}} + 1} \right)\\ = \frac{5}{9}.\left( {2 + 1} \right)\\ = \frac{5}{9}.3 = \frac{5}{3}\end{array}\)
c)
\(\begin{array}{l}\left[ {\left( { - \frac{4}{9} + \frac{3}{5}} \right):\frac{{13}}{{17}}} \right] + \left( {\frac{2}{5} - \frac{5}{9}} \right):\frac{{13}}{{17}}\\ = \left( { - \frac{4}{9} + \frac{3}{5}} \right).\frac{{17}}{{13}} + \left( {\frac{2}{5} - \frac{5}{9}} \right).\frac{{17}}{{13}}\\ = \frac{{17}}{{13}}.\left( { - \frac{4}{9} + \frac{3}{5} + \frac{2}{5} - \frac{5}{9}} \right)\\ = \frac{{17}}{{13}}.\left[ {\left( { - \frac{4}{9} - \frac{5}{9}} \right) + \left( {\frac{3}{5} + \frac{2}{5}} \right)} \right]\\ =\frac{{17}}{{13}}. (\frac{-9}{9}+\frac{5}{5})\\= \frac{{17}}{{13}}.\left( { - 1 + 1} \right)\\ = \frac{{17}}{{13}}.0 = 0\end{array}\)
d)
\(\begin{array}{l}\frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{3}{{11}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{2}{5}} \right)\\ = \frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{6}{{22}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{4}{{10}}} \right)\\ = \frac{3}{{16}}:\frac{{ - 3}}{{22}} + \frac{3}{{16}}:\frac{{ - 3}}{{10}}\\ = \frac{3}{{16}}.\frac{{ - 22}}{3} + \frac{3}{{16}}.\frac{{ - 10}}{3}\\ = \frac{3}{{16}}.\left( {\frac{{ - 22}}{3} + \frac{{ - 10}}{3}} \right)\\ = \frac{3}{{16}}.\frac{{ - 32}}{3}\\ = - 2\end{array}\)
Tính nhanh :
A= \(\frac{24\cdot43-23}{24+47-23}\cdot\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7}-\frac{9}{11}+9}\)
Giải hộ đúng mk tick
\(\frac{11}{12}.\frac{3.\left(1+\frac{1}{7}-\frac{1}{11}+\frac{1}{1001}-\frac{1}{13}\right)}{9.\left(\frac{1}{1001}-\frac{1}{13}+\frac{1}{7}-\frac{1}{11}+1\right)}=\frac{11}{12}.\frac{1}{3}=\frac{11}{36}\)