\(\left(\frac{11}{12}+\frac{11}{12\times13}+\frac{11}{23\times24}+...+\frac{11}{89\times100}\right)+x=\frac{5}{3}\)
Tim x biet
ai guips tui với
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Tìm \(x\) biết: \(\left(\frac{11}{12}+\frac{11}{12\cdot23}+\frac{11}{23\cdot34}+...+\frac{11}{89\cdot100}\right)+x=\frac{5}{3}\)
1.(11/12+11/23+11/23+11/24+...+11/89+11/100)+x=5/3
1.(11/12+11/100)+x=5/3
77/75+x=5/3
x=5/3-77/75
x=16/25
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de ot
=> ( 11/12+ 1/12- 1/23+ 1/23- 1/34+...+ 1/89-1/100 ) +x=5/3
=> (11/12+ 1/12-1/100 ) + x=5/3
=> (11/12+ 11/150) + x=5/3
=>99/100 +x = 5/3
=> x = 5/3 - 99/100
=> x= 203 / 300
K dung NHA
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Ta có : (\(\frac{11}{12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\)) + x =\(\frac{5}{3}\)
=> (\(\frac{11}{1\times12}+\frac{11}{12\times23}+\frac{11}{23\times34}+...+\frac{11}{89\times100}\)) + x =\(\frac{5}{3}\)
=> (\(1-\frac{1}{12}+\frac{1}{12}-\frac{1}{23}+\frac{1}{23}-\frac{1}{34}+...+\frac{1}{89}-\frac{1}{100}\)) + x =\(\frac{5}{3}\)
=> (\(1-\frac{1}{100}\)) + x =\(\frac{5}{3}\)
=> \(\frac{99}{100}\)+ x =\(\frac{5}{3}\)
=> x = \(\frac{5}{3}-\frac{99}{100}=\frac{203}{300}\)
Vậy x = \(\frac{203}{300}\)
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Tìm số nguyên âm x, biết:
\(^{x^2}-\left(\frac{3}{5}\right)^2=\frac{1}{1\times2}+\frac{1}{2\times7}+\frac{1}{5\times7}+\frac{1}{5\times13}+\frac{1}{8\times13}+\frac{1}{8\times19}+\frac{1}{11\times19}+\frac{1}{11\times19}+\frac{1}{11\times25}\)
AI NHANH MK TICK CHO NHA!
a,\(\frac{3^{10}\times(-5)^{21}}{\left(-5\right)^{20}\times3^{12}}\)
b,\(\frac{\left(-11\right)^5\times13^7}{11^5\times13^8}\)
c,\(\frac{2^{10}\times3^{10}-2^{10}\times3^9}{2^9\times3^{10}}\)
d,\(\frac{5^{11}\times7^{12}+5^{11}\times7^{11}}{5^{12}\times7^{12}+9\times5^{11}\times7^{11}}\)
Bài trên là bài rút gon phân số
\(a)\frac{3^{10}.\left(-5\right)^{21}}{\left(-5\right)^{20}.3^{12}}=\frac{-5}{3^2}=\frac{-5}{9}\)
\(b)\frac{-11.13^7}{11^5.13^8}=\frac{-1}{11^4.13}\) (Bạn xem thử xem có sai đề không nhé)
\(c)\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3+1\right)}{2^9.3^{10}}=\frac{2.4}{3}=\frac{8}{3}\)
\(d)\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(5.4+9\right)}=\frac{8}{20+9}=\frac{8}{29}\)
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\(a)\frac{3^{10}\cdot\left(-5\right)^{21}}{\left(-5\right)^{20}\cdot3^{12}}=\frac{-5}{3^2}=\frac{-5}{9}\)
\(b)\frac{\left(-11\right)\cdot13^7}{11^5\cdot13^8}=\frac{-1}{11^4\cdot13}=\frac{-1}{14641\cdot13}=\frac{-1}{190333}\)
\(c)\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\left(3^{10}-3^9\right)}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\cdot2}{2^9\cdot3^{10}}=\frac{2\cdot2}{3}=\frac{4}{3}\)
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\(\frac{11}{12}+\frac{11}{12\cdot23}+...+\frac{11}{89\cdot100}+x=\frac{5}{3}\)
Ai trả lời nhanh đúng tick( nhớ giải đầy đủ nha)
=> 11/12 + 1/12 - 1/23 + 1/23 - 1/34 + ..... + 1/89 - 1/100 + x = 5/3
=> 11/12 + 1/12 - 1/100 + x = 5/3
=> 99/100 + x = 5/3
=> x = 5/3 - 99/100 = 203/300
Tk mk nha
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Bài 2 : Tìm x, biết :
\(a.\frac{11}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{11}{13}\right)\)
\(b.\left(\frac{7}{12}+x\right)-\frac{11}{12}=\frac{2}{3}\)
Tính nhanh:a) 2.frac{3}{7}+left(frac{2}{9}-1frac{3}{7}right)-frac{5}{3}:frac{1}{9} b) frac{-11}{23}.frac{6}{7}+frac{8}{7}.frac{-11}{23}-frac{1}{23} c )left(frac{377}{-231}-frac{123}{89}+frac{34}{791}right).left(frac{1}{6}-frac{1}{8}-frac{1}{24}right) d) 19frac{5}{8}:frac{7}{12}-15frac{1}{4}:frac{7}{12} e) frac{2}{5}.frac{1}{3}-frac{2}{15}:frac{1}{5}+frac{3}{5}.frac{1}{3}
Đọc tiếp
Tính nhanh:
a) \(2.\frac{3}{7}+\left(\frac{2}{9}-1\frac{3}{7}\right)-\frac{5}{3}:\frac{1}{9}\)
b) \(\frac{-11}{23}.\frac{6}{7}+\frac{8}{7}.\frac{-11}{23}-\frac{1}{23}\)
c )\(\left(\frac{377}{-231}-\frac{123}{89}+\frac{34}{791}\right).\left(\frac{1}{6}-\frac{1}{8}-\frac{1}{24}\right)\)
d) \(19\frac{5}{8}:\frac{7}{12}-15\frac{1}{4}:\frac{7}{12}\)
e) \(\frac{2}{5}.\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}.\frac{1}{3}\)
a: \(=\dfrac{17}{7}+\dfrac{2}{9}-\dfrac{10}{7}-\dfrac{5}{3}\cdot9=1+\dfrac{2}{9}-15=-14+\dfrac{2}{9}=-\dfrac{126}{9}+\dfrac{2}{9}=-\dfrac{124}{9}\)
b: \(=\dfrac{-11}{23}\left(\dfrac{6}{7}+\dfrac{8}{7}\right)-\dfrac{1}{23}=\dfrac{-22}{23}-\dfrac{1}{23}=-1\)
c: \(=\left(\dfrac{377}{-231}-\dfrac{123}{89}+\dfrac{34}{791}\right)\cdot\dfrac{4-3-1}{24}=0\)
d: \(=\dfrac{12}{7}\left(19+\dfrac{5}{8}-15-\dfrac{1}{4}\right)=\dfrac{12}{7}\cdot\dfrac{35}{8}=\dfrac{15}{2}\)
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Tìm x biết :
\(\left[\frac{6:\frac{3}{5}-1\frac{1}{16}.\frac{6}{7}}{4\frac{1}{5}.\frac{10}{11}+5\frac{2}{11}}-\frac{\left(\frac{3}{20}+\frac{1}{2}-\frac{1}{15}\right).\frac{12}{49}}{3\frac{1}{3}+\frac{2}{9}}\right].x=2\frac{23}{96}\)
\(x=\frac{903}{391}\)
Bài này sử dụng MTCT đó bạn!
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\(x-\left(\frac{20}{11\times13}+\frac{20}{13\times15}+\frac{20}{15\times17}+...+\frac{20}{53\times55}\right)=\frac{3}{11}\)
\(x-\left(\frac{20}{11.13}+\frac{20}{13.15}+\frac{20}{15.17}+...+\frac{20}{53.55}\right)=\frac{3}{11}\)
\(x-10\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{53.55}\right)=\frac{3}{11}\)
\(x-10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)=\frac{3}{11}\)
\(x-10\left(\frac{1}{11}-\frac{1}{55}\right)=\frac{3}{11}\)
\(x-10.\frac{4}{55}=\frac{3}{11}\)
\(x-\frac{40}{55}=\frac{3}{11}\)
\(x=\frac{3}{11}+\frac{40}{55}\)
\(x=\frac{55}{55}=1\)
nha.
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\(\frac{-11}{23}.\frac{10}{-13}+\frac{11}{-13}.\frac{-3}{23}-\left(\frac{-12}{23}\right)\)
110/299+33/299+12/23
143/299+12/23
1
=\(\frac{-11}{23}\)\(\times\)\(\frac{10}{-13}\)\(+\)\(\frac{11}{-13}\)\(\times\)\(\frac{-3}{23}\)\(+\)\(\frac{12}{23}\)
=\(\frac{110}{299}\)\(+\)\(\frac{33}{299}\)\(+\)\(\frac{12}{23}\)
=\(\frac{143}{299}\)\(+\)\(\frac{12}{23}\)
= 1
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