giải chi tiết giúp mình nha mình cần gấp lắm mình cảm ơn nhìu
\(\frac{4}{5\cdot7}+\frac{4}{7\cdot9}+\frac{4}{9\cdot11}+...+\frac{4}{59\cdot61}\)
\(\frac{4}{1\cdot3\cdot5}+\frac{4}{3\cdot5\cdot7}+\frac{4}{5\cdot7\cdot9}+\frac{4}{7\cdot9\cdot11}+\frac{4}{9\cdot11\cdot13}\)
giúp mk nha các bn
\(\frac{4}{1\cdot3\cdot5}+\frac{4}{3\cdot5\cdot7}+\frac{4}{5\cdot7\cdot9}+\frac{4}{7\cdot9\cdot11}+\frac{4}{9\cdot11\cdot13}\)
\(=\frac{1}{1.3}-\frac{1}{3.5}+\frac{1}{3.5}-\frac{1}{5.7}+...+\frac{1}{9.11}-\frac{1}{11.13}\)
\(=\frac{1}{1.3}-\frac{1}{11.13}\)
\(=\frac{1}{3}-\frac{1}{143}\)
\(=\frac{140}{429}\)
giúp mình hen nhớ giải chi tiết nha mình cảm ơn nhìu mình đang cần gấp các bạn tính xong nhớ thử lại nhé
\(\frac{2}{5}+x=\frac{4}{10}\)
Đáp án là 0 bạn nhá !
Thử quy đồng số 2/5 ra mẫu số là 10 rồi trừ y như trừ số tự nhiên đó !
Vậy thôi hà !
Ta có:
\(\frac{2}{5}+x=\frac{4}{10}=\frac{2}{5}\)
\(\Rightarrow x=\frac{2}{5}-\frac{2}{5}=0\)
chứng minh :
\(\frac{4}{3\cdot5}-\frac{6}{5\cdot7}+\frac{8}{7\cdot9}-\frac{10}{9\cdot11}+.......+\frac{2016}{2015\cdot2017}>\frac{1}{6}\)
các bạn giúp nhanh mình cái muộn rồi
chứng minh :
\(\frac{4}{3\cdot5}-\frac{6}{5\cdot7}+\frac{8}{7\cdot9}-\frac{10}{9\cdot11}+.......+\frac{2016}{2015\cdot2017}>\frac{1}{6}\)
các bạn giúp nhanh mình cái muộn rồi
\(\frac{4}{3.5}-\frac{6}{5.7}+\frac{8}{7.9}+\frac{10}{9.11}+...+\frac{2016}{2015.2017}\)
\(=2.\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{2015}-\frac{1}{2017}\right)\)
\(=2.\left(\frac{1}{3}-\frac{1}{2017}\right)\)
\(=2.\frac{2014}{6051}\)
\(=\frac{4028}{6051}\)
\(\Rightarrow BT>\frac{1}{6}\)
A = \(\frac{4}{3\cdot5}+\frac{4}{5\cdot7}+\frac{4}{7\cdot9}+\frac{4}{9\cdot11}\)
\(A=\frac{4}{3\cdot5}+\frac{4}{5\cdot7}+\frac{4}{7\cdot9}+\frac{4}{9\cdot11}\)
\(A=\frac{2\cdot2}{3\cdot5}+\frac{2\cdot2}{5\cdot7}+\frac{2\cdot2}{7\cdot9}+\frac{2\cdot2}{9\cdot11}\)
\(A=2\cdot\left(\frac{2}{3\cdot5}+\frac{2}{5\cdot7}+\frac{2}{7\cdot9}+\frac{2}{9\cdot11}\right)\)
\(A=2\cdot\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(A=2\cdot\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(A=2\cdot\frac{8}{33}\)
\(A=\frac{16}{33}\)
Ta có:
\(A=\frac{4}{3.5}+\frac{4}{5.7}+\frac{4}{7.9}+\frac{4}{9.11}\)
\(A=2\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}\right)\)
\(A=2\left(\frac{1}{3}-\frac{1}{11}\right)\)
\(A=2\cdot\frac{8}{33}\)
\(A=\frac{16}{33}\)
\(\frac{3}{5\cdot7}+\frac{3}{7\cdot9}+\frac{3}{9\cdot11}+...+\frac{3}{197\cdot199}\)
Ai biết thì giúp mình nha
Hì Hì
2/3(2/5.7 + 2/7.9 + 2/9.11 +.....+2/197.199)
2/3(1/5 - 1/7 + 1/7 - 1/9 + 1/9 - 1/11 +......+ 1/197 - 1/199)
2/3(1/5 - 1/199)
............Còn lại tự làm nhé!
\(\frac{3}{5.7}+\frac{3}{7.9}+\frac{3}{9,11}+...+\frac{3}{197.199}\)
\(=\frac{3}{5}-\frac{3}{7}+\frac{3}{7}-\frac{3}{9}+\frac{3}{9}-\frac{3}{11}+...+\frac{3}{197}-\frac{3}{199}\)
\(=\frac{3}{5}-\frac{3}{199}=\)
Tới đây tự tính
Thuận Quốc làm sai đừng nghe theo
Như thế này nè:
=\(\frac{3}{2}\left(\frac{2}{5.7}+\frac{2}{7.9}+\frac{2}{9.11}+...+\frac{2}{197.199}\right)\)
=\(\frac{3}{2}\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+\frac{1}{9}-\frac{1}{11}+...+\frac{1}{197}-\frac{1}{199}\right)\)
=\(\frac{3}{2}\left(\frac{1}{5}-\frac{1}{199}\right)\)
=\(\frac{3}{2}.\frac{194}{995}\)=\(\frac{291}{995}\)
\(\frac{3}{5\cdot7}+\frac{3}{7\cdot9}+........+\frac{3}{59\cdot61}\)
\(=\frac{3}{2}\left(\frac{2}{5.7}+\frac{2}{7.9}+.....+\frac{2}{59.61}\right)\)
\(=\frac{3}{2}\left(\frac{1}{5}-\frac{1}{61}\right)\)
\(=\frac{3}{2}.\frac{56}{305}\)
\(=\frac{84}{305}\)
tk cho minh nhe >.<
Ta có: \(\frac{2}{3}\times\left(\frac{3}{5.7}+\frac{3}{7.9}+.....+\frac{3}{59.61}\right):\frac{2}{3}\)
\(\Rightarrow\left(\frac{2}{5.7}+\frac{2}{7.9}+.....+\frac{2}{59.61}\right):\frac{2}{3}\)
\(=\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+....+\frac{1}{59}-\frac{1}{61}\right):\frac{2}{3}\)
\(\Rightarrow\left(\frac{1}{5}-\frac{1}{61}\right):\frac{2}{3}=\frac{56}{305}:\frac{2}{3}=\frac{84}{305}\)
= \(\frac{3}{2}\). ( \(\frac{2}{5.7}\)+ \(\frac{2}{7.9}\)+ ...... + \(\frac{2}{59.61}\))
= \(\frac{3}{2}\). ( \(\frac{1}{5}\)- \(\frac{1}{7}\)+ \(\frac{1}{7}\)- \(\frac{1}{9}\)+ ...... + \(\frac{1}{59}\)- \(\frac{1}{61}\))
= \(\frac{3}{2}\). ( \(\frac{1}{5}\)- \(\frac{1}{61}\)) = \(\frac{3}{2}\). \(\frac{61-5}{305}\)= \(\frac{3}{2}\). \(\frac{56}{305}\)
= \(\frac{3.28}{1.305}\)= \(\frac{82}{305}\)
Tính tổng
\(\frac{5}{5\cdot7}+\frac{5}{7\cdot9}+...+\frac{5}{59\cdot61}\)
\(\frac{5}{5.7}+\frac{5}{7.9}+...+\frac{5}{59.61}\)
\(=\frac{5}{2}\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{59.61}\right)\)
\(=\frac{5}{2}\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{59}-\frac{1}{61}\right)\)
\(=\frac{5}{2}\left(\frac{1}{5}-\frac{1}{61}\right)=\frac{5}{2}.\frac{56}{305}=\frac{28}{61}\)
Thực hiện phép tính( tính hợp lí nếu có thể )
\(M=\)\(\frac{\frac{7}{2012}+\frac{7}{9}-\frac{1}{4}}{\frac{5}{9}-\frac{3}{2012}-\frac{1}{2}}\)
GIÚP MÌNH VỚI, MÌNH CẦN GẤP, MÌNH ĐỘI ƠN NHÌU