Giải:

S=3/5.7+3/7.9+...+3/59.61

S=3/2.(2/5.7+2/5.7+...+2/59.61)

S=3/2.(1/5-1/7+1/7-1/9+...+1/59-1/61)

S=3/2.(1/5-1/61)

S=3/2.56/305

S=84/305

Chúc bạn học tốt!

`S=3/(5.7)+3/(7.9)+....+3/(59.61)`

`=>2S=3(2/(5.7)+2/(7.9)+....+2/(59.61))`

`=>2S=3(1/5-1/7+.....+1/59-1/61)`

`=>2S=3(1/5-1/61)=168/305`

`=>S=84/305`

gọi biểu thức trên là A

gọi biểu thức trên là A. ta có: 

3A = 1/5.7+1/7.9+......+ 1/59.61

3A = 1/5-1/7+1/7-1/9+....+1/59-1/61

3A = 1/5 - 1/61

3A = 56/305

A = 56/305 : 3 = 56/915

\(=\frac{1}{5}-\frac{1}{61}=\frac{56}{305}\)

\(S=\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{59.61}\)

\(S=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{59}-\frac{1}{61}\)

\(S=\frac{1}{5}-\frac{1}{61}\)

\(S=\frac{61}{305}-\frac{5}{305}\)

\(S=\frac{56}{305}\)

\(S=\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{59}-\frac{1}{61}\)

\(S=\frac{1}{5}-\frac{1}{61}\)

\(S=\frac{56}{305}\)

.Cho P=3/5.7+3/7.9+...+3/59.61=3/2.(1/5-1/61)=3/2.56/305=84/305 
 

bài này trong sách giáo khoa chương trình Vnen

thanksTuấn Anh Phan Nguyễn

84/305

 cần mk giải ko 

nhớ mk nha

= 3(1/5.7+1/7.9+...+1/59.61)

= 3/2(2/5.7+2/7.9+...+2/59.61)

= 3/2(1-1/5+1/5-1/7+1/7-1/9+...+1/59-1/61)

= 3/2(1-1/61)=3/2.60/61=90/61

Chẳng biết mk làm đúng ko nữa!

\(\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{59.61}=\frac{3}{2}\cdot\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{59.61}\right)=\frac{3}{2}\cdot\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{59}-\frac{1}{61}\right)=\frac{3}{2}\cdot\left(\frac{1}{5}-\frac{1}{61}\right)=\frac{84}{305}\)

Đặt \(A=\frac{3}{5.7}+\frac{3}{7.9}+...+\frac{3}{59.61}\)

\(\Rightarrow A=\frac{3}{2}.\left(\frac{2}{5.7}+\frac{2}{7.9}+...+\frac{2}{59.61}\right)=\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{59}-\frac{1}{61}\right)\)

\(=\frac{3}{2}.\left(\frac{1}{5}-\frac{1}{61}\right)=\frac{3}{2}.\frac{56}{305}=\frac{84}{305}\)

84/305 nha bạn

mk nha có cần giải ra ko