Tính:
23×10+(1+9)
Tính nhanh:
a)\(\frac{{13}}{{23}}.\frac{7}{{11}} + \frac{{10}}{{23}}.\frac{7}{{11}};\)
b) \(\frac{5}{9}.\frac{{23}}{{11}} - \frac{1}{{11}}.\frac{5}{9} + \frac{5}{9}\)
c)\(\left[ {\left( { - \frac{4}{9}} \right) + \frac{3}{5}} \right]:\frac{{13}}{{17}} + \left( {\frac{2}{5} - \frac{5}{9}} \right):\frac{{13}}{{17}};\)
d) \(\frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{3}{{11}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{2}{5}} \right)\)
a)
\(\begin{array}{l}\frac{{13}}{{23}}.\frac{7}{{11}} + \frac{{10}}{{23}}.\frac{7}{{11}}\\ = \frac{7}{{11}}.\left( {\frac{{13}}{{23}} + \frac{{10}}{{23}}} \right)\\ = \frac{7}{{11}}.\frac{23}{23}\\ = \frac{7}{{11}}.1\\ = \frac{7}{{11}}\end{array}\)
b)
\(\begin{array}{l}\frac{5}{9}.\frac{{23}}{{11}} - \frac{1}{{11}}.\frac{5}{9} + \frac{5}{9}\\ = \frac{5}{9}.\left( {\frac{{23}}{{11}} - \frac{1}{{11}} + 1} \right)\\ = \frac{5}{9}.\left( {2 + 1} \right)\\ = \frac{5}{9}.3 = \frac{5}{3}\end{array}\)
c)
\(\begin{array}{l}\left[ {\left( { - \frac{4}{9} + \frac{3}{5}} \right):\frac{{13}}{{17}}} \right] + \left( {\frac{2}{5} - \frac{5}{9}} \right):\frac{{13}}{{17}}\\ = \left( { - \frac{4}{9} + \frac{3}{5}} \right).\frac{{17}}{{13}} + \left( {\frac{2}{5} - \frac{5}{9}} \right).\frac{{17}}{{13}}\\ = \frac{{17}}{{13}}.\left( { - \frac{4}{9} + \frac{3}{5} + \frac{2}{5} - \frac{5}{9}} \right)\\ = \frac{{17}}{{13}}.\left[ {\left( { - \frac{4}{9} - \frac{5}{9}} \right) + \left( {\frac{3}{5} + \frac{2}{5}} \right)} \right]\\ =\frac{{17}}{{13}}. (\frac{-9}{9}+\frac{5}{5})\\= \frac{{17}}{{13}}.\left( { - 1 + 1} \right)\\ = \frac{{17}}{{13}}.0 = 0\end{array}\)
d)
\(\begin{array}{l}\frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{3}{{11}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{2}{5}} \right)\\ = \frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{6}{{22}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{4}{{10}}} \right)\\ = \frac{3}{{16}}:\frac{{ - 3}}{{22}} + \frac{3}{{16}}:\frac{{ - 3}}{{10}}\\ = \frac{3}{{16}}.\frac{{ - 22}}{3} + \frac{3}{{16}}.\frac{{ - 10}}{3}\\ = \frac{3}{{16}}.\left( {\frac{{ - 22}}{3} + \frac{{ - 10}}{3}} \right)\\ = \frac{3}{{16}}.\frac{{ - 32}}{3}\\ = - 2\end{array}\)
Tính bằng cách thuân tiện nhất
A. 14/15 * 23/21 * 15/23
B. 1/2 * 9/10 + 1/2 * 8/10 - 1/2 * 7/10
A. = 14/15 * 15/23 * 23/21
= 14/23 * 23/21
= 14/21
B. = 1/2 * (9/10 + 8/10 - 7/10)
= 1/2 * 10/10
= 1/2 * 1
= 1/2
a) \(\frac{14}{15}\cdot\frac{23}{21}\cdot\frac{15}{23}=\frac{14}{21}=\frac{2}{3}\)
b)\(\frac{1}{2}\cdot\frac{9}{10}+\frac{1}{2}\cdot\frac{8}{10}-\frac{1}{2}\cdot\frac{7}{10}=\frac{1}{2}\cdot\left(\frac{9}{10}+\frac{8}{10}-\frac{7}{10}\right)=\frac{1}{2}\cdot1=\frac{1}{2}\)
Câu 1: Thực hiện phép tính
a) A= 1.2.3...9-1.2.3...8-1.2.3...8\(^2\)
Câu 2 : Tính nhanh
[(11,81+8,19).0,02] : [(-9):11.25]:\(\frac{23^{10}-23^{11}}{23^{11}+21.23^{10}}\)
Câu 1 :
A= 1.2.3...9-1.2.3...8-1.2.3...82
= 1.2.3...8. ( 9 - 1 - 8 )
= 1.2.3...8.0
= 0
tính giá trị biểu thức:A=[(11,81+8,19).0,02]:[(-9):11,25]:23^10-23^11/23^11+21.23^10
Tính nhanh:
A=(19-3/11+9/23)-(6+7/11-15/23)-(8-10/11+1/23)
mn giúp mk nha!Thank
tính giá trị của biểu thức :A =4^20.25^20/10^40-9/11.17/23+9/11.-6/23
help me!
B1: Tính A=(1/7+1/23-1/1009) : (1/7+1/23-1/1009+1/7.1/23.1/9) +1:(30.1009-160)
B=(151515/161616+17^9/17^10)-(1500/1600+1616/1717)
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tính số tự nhiên x,( 1/1*2*3 + 1/2*3*4 + ... + 1/8*9*10) * x = 23/45