Find Y such that :
( 1 / 2 x 4 + 1 / 4 x 6 + 1 / 6 x 8 + ... + 1 / 98 x 100 ) : Y = 147 / 50
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( 1/2x4+1/4 x 6+1/6x8+....+1/98 x 100) / y = 147/50 tìm y
\(\frac{\frac{1}{2\times4}+\frac{1}{4\times6}+\frac{1}{6\times8}+...+\frac{1}{98\times100}}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\left(\frac{2}{2\times4}+\frac{2}{4\times6}+\frac{2}{6\times8}+...+\frac{2}{98\times100}\right)}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{98}-\frac{1}{100}\right)}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\left(\frac{1}{2}-\frac{1}{100}\right)}{y}=\frac{147}{50}\)
\(\frac{\frac{1}{2}\times\frac{49}{100}}{y}=\frac{147}{50}\)
\(\frac{49}{200}:y=\frac{147}{50}\)
\(y=\frac{49}{200}:\frac{147}{50}\)
\(y=\frac{1}{12}\)
In the figure below, x = Câu 2 Find the measure of angle J if \widehat{K}=29^o K =29 o and angle J and K are supplementary. Answer: \widehat{J}= J = ^o o . Câu 3 In the figure below, x = Câu 4 In the figure below, x = Câu 5 Solve: |2x-3|-4=3∣2x−3∣−4=3, where xx is a negative number. Answer: x=x= Câu 6 Calculate: 9+|-6|:1^2 =9+∣−6∣:1 2 = Câu 7 Compare: \dfrac{36}{27} 27 36 \dfrac{4}{3} 3 4 Câu 8 Find the negative number yy such that |y+\dfrac{7}{2}|-\dfrac{1}{2}=4∣y+ 2 7 ∣− 2 1 =4. Answer: y=y= Câu 9 Find xx such that \dfrac{32}{2^x}=2 2 x 32 =2. Answer: x=x= Câu 10 Find nn such that \dfrac{(-4)^n}{64}=-16 64 (−4) n =−16. Answer: n=n= Cần gấp nhé
(1/2*4+1/4*6+1/6*8+.....+1/98*100)/y=147/50
tìm y
so sánh 52/17 và 120/41
3/4 + 1/4 : ( 7/12 - 1/6 )
372,463 x 998 + 744,926
2- 4 + 6 - 8+ 10 - 12 +........ + 98 - 100 + 102
( y + 112) - 113=79
3/4 - y = 1/2
(4/5 - 2 x y) + 1/6= 5/6
(Y + 1) + ( Y + 2 ) + ( Y + 3)+........+ (Y + 50 ) = 1750
Gỉai giúp t bài này với ạ mơn các c rất nhiều ạ giải chi tiết giùm t với ạ t mơn nhìu ạ
Gỉai giúp t bai nay vs nhé . Cảm ưn nhìu
so sánh 52/17 và 120/41
3/4 + 1/4 : ( 7/12 - 1/6 )
372,463 x 998 + 744,926
2- 4 + 6 - 8+ 10 - 12 +........ + 98 - 100 + 102
( y + 112) - 113=79
3/4 - y = 1/2
(4/5 - 2 x y) + 1/6= 5/6
(Y + 1) + ( Y + 2 ) + ( Y + 3)+........+ (Y + 50 ) = 1750
x³+y³+z³=8?
x³+y³+z³=42?
Find x, y, and z such that x³+y³+z³=k, for each k from 1 to 100.
A= 1/2 x 4 + 1/4 x 6 + 1/6 x 8 +1/8 x 10 + ... +1/98 x 100
2A=2/2x4+2/4x6+..+2/98x100
=> 2A=1-1/4+1/4-1/6+..+1/98-1/100
=> 2A=1-1/100
=> 2A=99/100
=> A=99/100:2
=> A=99/200
( 1/2*4+1/4*6+1/6*8+....+1/98*1000):y=147/50
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Find the value of m such that x^4– mx^2 + 6 is divisible by x^2 – 1. Answer: m =
x4 - mx2 + 9 = (x2 -1)2
vây m =6 thì x4 -6x2 +9 chia hết cho x2 - 1
( ngâniq106)