Ta có: \(\dfrac{33}{39}\) = \(\dfrac{11}{13}\):\(\dfrac{11}{35}\) 

Vì \(\dfrac{11}{35}\)và\(\dfrac{11}{13}\)có cùng tử số

=> \(\dfrac{11}{35}\)<\(\dfrac{11}{13}\)=> \(\dfrac{11}{35}\)<\(\dfrac{33}{39}\)

\(\dfrac{33}{39}\)

11 phần 35 >  33 phần 39

So sánh $\frac{11}{35}$ và $\frac{33}{39}$

Ta có : $\frac{33}{39}=\frac{11}{13}$

    $\frac{11}{35}=\frac{11\times 13}{35\times 13}=\frac{143}{455}$

    $\frac{11}{13}=\frac{11\times 35}{13\times 35}=\frac{385}{455}$

Vì $143<385$ nên $\frac{143}{455}<\frac{385}{455}$

Vậy $\frac{11}{35}<\frac{33}{39}$

a) Ta có: \(8^{28}=2^{84}=16^{21}\)

Mà \(16>15\Rightarrow16^{21}>15^{21}\Rightarrow8^{28}>15^{21}\)

Vậy...

b) \(5^{91}>5^{90}=125^{30}\)   \(\left(1\right)\)

    \(11^{59}< 11^{60}=121^{30}\)                \(\left(2\right)\)

Lại có: \(125>121\)          \(\left(3\right)\)

Từ (1), (2) và (3) suy ra \(5^{91}>11^{59}\)

a) \(3^{39}\) và \(11^{21}\)

\(\Rightarrow3^{39}=3^{13.3}=1594323^3\)

\(\Rightarrow11^{21}=11^{7.3}=194487171^3\)

Nên \(3^{39}< 11^{21}\)

b) \(199^{20}\) và \(2003^{15}\)

\(\Rightarrow199^{20}=199^{4.5}=1568239201^5\)

\(\Rightarrow2003^{15}=8036054027^5\)

Nên \(199^{20}< 2003^{15}\)

339 và 1121

339< 342; 342=36.7=(36)7=7297

1121= 113.7=(113)7=13317

Vì 7297< 13317=> 342<1121

=>339<1121

CHUC HOK TOT

a/

2020.2021=(2019+1)(2022-1)=

=2019.2022-2019+2022-1=2019.2022+2>2019.2022

b/

\(4^7=\left(2^2\right)^7=2^{14}< 2^{15}\)

c/

\(199^{20}< 200^{20}=\left(8.25\right)^{20}=\left(2^3.5^2\right)^{20}=2^{60}.5^{40}\)

\(2000^{15}=\left(16.125\right)^{15}=\left(2^4.5^3\right)^{15}=2^{60}.5^{45}\)

\(\Rightarrow2000^{15}=2^{60}.5^{45}>2^{60}.5^{40}>199^{20}\)

d/

\(31^{31}< 32^{31}=\left(2^5\right)^{31}=2^{155}\)

\(17^{39}>16^{39}=\left(2^4\right)^{39}=2^{156}\)

\(\Rightarrow17^{39}=2^{156}>2^{155}>31^{31}\)

giúp mình với được ko ạh

giúp mình đi được ko, mình đang cần gấp

Bài 2: So sánh các phân số sau

7/15 > 5/13              11/12 > 7/48        24/35 > 21/7           15/26 > 7/8

ai nhanh nhất mình k cho

Bài 1:

\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)

\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)

\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)

\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)

\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)

\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)

\(A=\frac{9}{11}\)

Bài 2 :

2)  Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17  

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17 

\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)

\(=\frac{11}{17}\)

\(=\frac{1111}{1717}=B\)

Vậy \(A=B\)

mình đâu biết

a) \(\frac{7}{8}=\frac{14}{16}>\frac{11}{16}\)

b) \(\frac{15}{35}=\frac{3}{7}=\frac{24}{56}\)

c) \(\frac{20}{31}>\frac{20}{33}>\frac{19}{33}\)

d) \(\frac{11}{12}