Tìm x biết :1/3+1/6+1/10+...+2/ x(x+1) =2014/2015
Tìm x biết :1/3+1/6+1/10+...+2/ x(x+1) =2014/2015
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x\left(x+1\right)}=\frac{2014}{2015}\)
\(\Rightarrow2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x\left(x+1\right)}\right)=\frac{2014}{2015}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{1007}{2015}\)
\(\Rightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{1007}{2015}\)
\(\Rightarrow\frac{1}{x+1}=\frac{1}{4030}\)
=>x+1=4030
=>x=4029
vậy x=4029
1/3+1/6+1/10+...+ 2/X(X+1) = 2014/2016
Tìm x biết 1+1/3+1/6+1/10+...+2/x(x+1)=2014/2015
Lời giải:
$1+\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+...+\frac{2}{x(x+1)}=\frac{2014}{2015}$
$\frac{2}{2}+\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+....+\frac{2}{x(x+1)}=\frac{2014}{2015}$
$\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{x(x+1)}=\frac{1007}{2015}$
$1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{1007}{2015}$
$1-\frac{1}{x+1}=\frac{1007}{2015}$
$\frac{1}{x+1}=1-\frac{1007}{2015}=\frac{1008}{2015}$
$\Rightarrow x+1=\frac{2015}{1008}$
$\Rightarrow x=\frac{1007}{1008}$
\frac{2}{1.2}+\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+...+\frac{2}{x(x+1)}=\frac{2014}{2015}$
tìm x biết 1/3+1/6+1/10+.....+2/x.(x+1)=2014/2015
Tìm x,biết:
x+2015/5 + x+2014/6 = x+2017/3 + x+2018/2
Hướng dẫn: x+2015/5+1 + x+2014/6+1 = x+2017/3+1 + x+2018/2+1
=> (x+2020)/5=(x+2020)/6=(x+2020)/3+(x+2020)/2
=>(x+2020)(1/5+1/6)=(x+2020)(1/3+1/2)
Với x+2020=0=>x=-2020
Với x+2020 khác 0=>1/5+1/6=1/3+1/2 ,vô lí
Vậy x=-2020
bài 7:tính
A=1-2+3-4+5-6+......+2015-2016
B=1+2-3-4+5+6+......+2013+2014-2015-2016
C=1-4-7-10-......-100
bài 8:tìm x thuộc z biết:
a,x.(x+2)=0
b,(x+2).(x-4)=0
Tìm x biết 3+5+7+...+2015 / 2+4+6+....+2014 + x=1
\(\frac{3+5+7+...+2015}{2+4+6+...+2014}+x=1\)
\(\frac{\left(3+2015\right).\left[\left(2015-3\right):2+1\right]:2}{\left(2+2014\right).\left[\left(2014-2\right):2+1\right]:2}+x=1\)
\(\frac{1016063}{1015056}+x=1\)
\(x=1-\frac{1016063}{1015056}\)
\(x=-\frac{1}{1008}\)
Tìm x thuộc Z biết:
1) 2016+2015+2014+...+x = 2016
2) 1+2+3+...+x = 1275
3) | x+2015 | + | x+2016| = 1
thiện xạ 5a3 có thể giải chi tiết ra đc k? Mk cần cách lm
2) 1+2+3+...+x=1275
Có SSH là: (x+1):1+1=x(SH)
=> (x+1).x:2=1275
=>(x+1).x=1275.2
=>(x+1).x=2550
=>(x+1).x=51.50
=>x=50
3) |x+2015|+|x+2016|=1
Ta thấy |x+2015| và |x+2016| > hoặc = 0 với mọi x
=> 1= 0+1=1+0
+) x+2015=0=>x=-2015
x+2016=1=>x=-2015
+) x+2015=1=>x=-2014
x+2016=0=> x=-2016
Vậy xE{...}
Tìm x biết
1/3+1/6+1/10+...+2/x(x+1)=2013/2014
1/3 = 2/6 = 2/(2x3) = 2/2 - 2/3
1/6 = 2/12 = 2/(3x4) = 2/3 - 2/4
...
2/x(x + 1) = 2/x - 2/(x +1)
Do đó:
1/3 + 1/6 + ... + 2/x(x+1) = 2/2 - 2/3 + 2/3 - 2/4 + ... +2/x - 2/(x + 1) = 2/2 - 2/(x+1)
suy ra 1 - 2/(x + 1) = 2013/2014
x= 4027
Tìm x biết 1/3+1/6+1/10+...+2/x(x+1)=2013/2014
1/3 = 2/6 = 2/(2x3) = 2/2 - 2/3 1/6 = 2/12 = 2/(3x4) = 2/3 - 2/4 ... 2/x(x + 1) = 2/x - 2/(x +1) Do đó: 1/3 + 1/6 + ... + 2/x(x+1) = 2/2 - 2/3 + 2/3 - 2/4 + ... +2/x - 2/(x + 1) = 2/2 - 2/(x+1) suy ra 1 - 2/(x + 1) = 2013/2014 x= 4027