(26 + 53 ) +(42 -26-55-53)

=79 + ( 16 -55 - 53 )

=79 + (-39-53)

=79 -39 - 53

=40 - 53 = -13

( 26 + 53 ) + ( 42 -26 - 55 - 53 )

= 79 + ( 16 - 55 - 53 )

= 79 + ( -39 - 53 )

= 79 + ( -92 )

= -13.

\(\left(26+53\right)+\left(42-26-55-53\right)\)

\(=26+53+42-26-55-53\)

\(=\left(26-26\right)+\left(53-53\right)+\left(42-55\right)\)

\(=0+0+\left(-13\right)\)

\(=-13\)

( 200 - 58 ) x 58 + ( 100 + 42) x 42

= 142 x 58 + 142 x 42

= 142 x ( 58 + 42)

= 142 x 100

= 14200

Hok tốt

1000 + ( 6,24 +1,26 ) : 0,75

= 1000 + 7,5 : 0,75

= 1000 + 10

= 1010

1000+(6,24+1,26):0,75=1010

1000+6,24:3/4+1,26:3/4

=1000+6,24x4/3+1,26x4/3

=1000+(6,24+1,26)x4/3

=1000+7,5x4/3

=1000+10

=1010

Số nhỏ nhất là 0

Số lớn nhất là 999

Trung bình cộng là (999+0):2=499,5 nhé

Các cậu ủng hộ cho tớ lên 150 điểm đi

các số đó là 0 ; 1 ; 2 ; .... ; 999

có 1000 số

tổng là (999+0) x 1000 : 2 = 499500

TBC là 499500 : 1000 = 499,5

tích nha

TBC các số tự nhiên nhỏ hơn 1000 là: (999 + 0) : 2 = 499,5 chắc 100000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000%

A=199.201

=199.(200+1)

=199.200+199

B=200.200

=(199+1).200

=199.200+200

Vì 199.200+199<199.200+200 nên A<B

a) 13/12 

b)  7/8

c)  81/4

d) 20/21

\(d,\dfrac{5}{7}+\dfrac{9}{23}+-\dfrac{12}{7}+\dfrac{14}{23}\)

\(=\left(\dfrac{5}{7}+\dfrac{-12}{7}\right)+\left(\dfrac{9}{23}+\dfrac{14}{23}\right)\)

\(=-\dfrac{7}{7}+\dfrac{23}{23}\)

\(=\left(-1\right)+1=0\)

\(e,\dfrac{3}{17}+-\dfrac{5}{13}+-\dfrac{18}{35}+\dfrac{14}{17}+\dfrac{17}{-35}+-\dfrac{8}{13}\)

\(=\left(\dfrac{3}{17}+\dfrac{14}{17}\right)+\left(\dfrac{-5}{13}+\dfrac{-8}{13}\right)+\left(\dfrac{-18}{35}+\dfrac{-17}{35}\right)\)

\(=\dfrac{17}{17}+\dfrac{-13}{13}+-\dfrac{35}{35}\)

\(=1+\left(-1\right)+\left(-1\right)=0+\left(-1\right)=-1\)

\(f,\dfrac{-3}{8}. \dfrac{1}{6}+\dfrac{3}{-8}.\dfrac{5}{6}+\dfrac{-10}{16}\)

\(=\dfrac{-3}{8}.\dfrac{1}{6}+\dfrac{-3}{8}.\dfrac{5}{6}+\dfrac{-10}{16}\)

\(=\dfrac{-3}{8}.\left(\dfrac{1}{6}+\dfrac{5}{6}\right)+-\dfrac{10}{16}\)

=\(\dfrac{-3}{8}.1+\dfrac{-10}{16}\)

\(=\dfrac{-3}{8}+\dfrac{-10}{16}\)

\(=\dfrac{-6}{16}+\dfrac{-10}{16}=\dfrac{-16}{16}=-1\)

\(g,\dfrac{-4}{11}.\dfrac{5}{15}.\dfrac{11}{-4}=\dfrac{-4}{11}.\dfrac{5}{15}.\dfrac{-11}{4}\)

\(=\left(\dfrac{-4}{11}.\dfrac{-11}{4}\right).\dfrac{5}{15}\)

\(=1.\dfrac{5}{15}=1.\dfrac{1}{3}=\dfrac{1}{3}\)

\(h,\dfrac{7}{36}-\dfrac{8}{-9}+\dfrac{-2}{3}=\dfrac{7}{36}-\dfrac{-8}{9}+\dfrac{-2}{3}\)

\(=\dfrac{7}{36}-\dfrac{-32}{36}+\dfrac{-24}{36}=\dfrac{7-\left(-32\right)+\left(-24\right)}{36}\)

\(=\dfrac{15}{56}=\dfrac{5}{12}\)

Tick mình nha ^^

d.\(\dfrac{5}{7}\)+\(\dfrac{9}{23}\)+\(\dfrac{12}{7}\)+\(\dfrac{14}{23}\)=(\(\dfrac{5}{7}\)+\(\dfrac{12}{7}\))+(\(\dfrac{9}{23}\)+\(\dfrac{14}{23}\))

                            =\(\dfrac{17}{7}\)+ 1 = \(\dfrac{24}{7}\)

e.\(\dfrac{3}{17}\)+\(\dfrac{-5}{13}\)+\(\dfrac{-18}{35}\)+\(\dfrac{14}{17}\)+\(\dfrac{17}{-35}\)+\(\dfrac{-8}{13}\)

=(\(\dfrac{3}{17}\)+\(\dfrac{14}{17}\))+(\(\dfrac{-5}{13}\)+\(\dfrac{-8}{13}\))+(\(\dfrac{-18}{35}\)+\(\dfrac{17}{-35}\))

= 1+ (-1) + (-1) = -1

f. \(\dfrac{-3}{8}\).\(\dfrac{1}{6}\)+\(\dfrac{3}{-8}\).\(\dfrac{5}{6}\)+\(\dfrac{-10}{16}\)=\(\dfrac{-3}{8}\)(\(\dfrac{1}{6}\)+\(\dfrac{5}{6}\)) + \(\dfrac{-5}{8}\)

                                   =\(\dfrac{-3}{8}\)+\(\dfrac{-5}{8}\)= -1

g. \(\dfrac{-4}{11}\).\(\dfrac{5}{15}\).\(\dfrac{11}{-4}\)=\(\dfrac{5}{15}\)

h.\(\dfrac{7}{36}\)-\(\dfrac{8}{-9}\)+\(\dfrac{-2}{3}\)= \(\dfrac{7}{36}\)-\(\dfrac{-32}{36}\)+\(\dfrac{-24}{36}\)

                       =\(\dfrac{-49}{36}\)

d: \(\dfrac{5}{7}+\dfrac{9}{23}+\dfrac{-12}{7}+\dfrac{14}{23}=1-1=0\)

e: \(\dfrac{3}{17}+\dfrac{-5}{13}+\dfrac{-18}{35}+\dfrac{14}{17}+\dfrac{17}{-35}+\dfrac{-8}{13}=-1-1+1=-1\)

58 x 42 + 32 x 8 + 5 x16 

= (2x29)(21x2) +(4x8)x8 + 5x(4x4)

= 4 x 609 + 4 x 64 + 4x20

= 4( 609+ 64+ 20)

= 4 x 693

= 2772

58.42+32.8+5.16 = 2436 + 256 + 80 = 2772

58 x 42 + 32 x8 + 5 x 16 = 2772

nhớ t i c k cho mik nhé

kết quả = 0 nha

Ta có: \(\left(812,1.10,5-91.10,5\right).\left(41.11-4100.0,1-410\right)\)

\(=A.\left[41.11-41.100.0,1-41\right]\)

\(=A.\left[41.11-41.10-41\right]\)

\(=A.\left[41.\left(11-10-1\right)\right]\)

\(=A.\left(41.0\right)\)

\(=A.0=0\)

= 10,5 x ( 812,1 - 91 ) x ( 41 x 11 - 4100 x 0,1 - 41 )

= 10,5 x 721.1 x ( 41 x 11 - 4100 x 0,1 - 41 )

= 10,5 x 721,1 x ( 451 - 4100 x 0,1 - 41 )

= 10,5 x 721,1 x ( 451 - 410 - 41 )

= 10,5 x 721,1 x ( 41 - 41 )

= 10,5 x 721,1 x 0

= 0 ( vì mọi số nhân với 0 đều bằng 0 )