a) 23 + 25 + 27 + 29 + 31 + 33 + 35

= 23 + ( 25 + 35 ) + ( 27 + 33 ) + ( 29 + 31 )

= 23 +        60      +      60         +      60

= 23 + 60 x 3

= 23 +    180

= 203

b) 4 . 36 . 25 . 50

=  4 . 4 .9 . 25 . 25 . 2

= 4 . 25 . 4 . 25 . 9 . 2

=   100 . 100     . 9 . 2

= 10 000           . 18

= 180 000

c) 32 . 125 . 3 

= 4 . 8 . 5 . 25 . 3

= 4 . 25 . 8 . 5 . 3

=  100    . 8 . 5 . 3

=      800 . 5 . 3

= 4000 . 3

= 12000

d, 36 . 19 + 36 . 81

= 36 . ( 19 + 81 )

= 36 . 100

= 3600

e, 78 . 31 + 78 . 24 + 78 . 17 + 22 x 72

= 78 . ( 31 + 24  + 17 ) + 22 x 72

= 78 . 72 + 22 . 72

= 72 . ( 78 + 22 )

= 72 . 100

= 7200

A)23+25+27+29+31+33+35

= (33+27)+(25+35)+(29+31)+23

=60+60+60+23

=60x3+23

=180+23

=203

B)4.36.25.50=(36.25).(4.50)

=(4.9.25).(2.2.50)

=(4.25).9 .(2.50).2

=100.9.100.2

=100.(9+2)

=100 .11

=1100

C)32.125.3=(4.8).125.3

=(125.8).(4.3)

=1000.12

=12000

D)36.19.36.81=36.(19+81)

 = 36.100

=3600

E)78.31.+78.24+78.17+22x72=78.31+78.24+78.17+ (16+6).72

=78.31+78.24+78.17+78.16

=78.(31+24+17+16)

=78.88

=6864

9766921

36²+25⁵=1296+9765625

             =9766921

= 61

NHa ban!!!

\(3+\frac{3}{5}+\frac{3}{25}+\frac{3}{125}+\frac{3}{625}\)

\(\Rightarrow\frac{3}{1}\cdot\frac{1}{625}+\frac{3}{5}\cdot\frac{1}{125}+\frac{3}{125}\cdot\frac{1}{5}+\frac{3}{625}\)

\(\Rightarrow\frac{3}{625}+\frac{3}{625}+\frac{3}{625}+\frac{3}{625}\)

\(\Rightarrow\frac{3}{625}\cdot4\)

\(\Rightarrow\frac{12}{625}\)

\ =: phai ko ban

à hiểu rồi

a) 3/7 + 4/9 + 4/7 + 5/9

= ( 3/7 + 4/7 ) + ( 4/9 + 5/9 )

= 7/7 + 9/9

= 1  + 1 

= 2

b)1/5 + 4/10 + 9/15 + 16/20 + 25/25 + 36/30 + 49/35 + 64/40 + 81/45

= 1/5 + 2/5 + 3/5 + 4/5 + 5/5 + 6/5 + 7/5 + 8/5 + 9/5

= ( 1/5 + 9/5 ) + ( 2/5 + 8/5 ) + (7/5 + 3/5 ) + ( 4/5 + 6/5  ) + 5/5

= 2 + 2 + 2 + 2 + 1

= 2  x 4 + 1

= 8  +1 

= 9

c)  1/8 + 1/12 + 3/8 + 5/12

= ( 1/8 + 3/8 ) + ( 1/12 + 5/12)

= 4/8 + 6/12

= 1/2 + 1/2

= 2/4 = 1/2

mỏi tay rồi

d; (1 - \(\dfrac{1}{2}\)) x (1 - \(\dfrac{1}{3}\)) x (1 - \(\dfrac{1}{4}\)) x ... x ( 1 - \(\dfrac{1}{100}\))

 = \(\dfrac{1}{2}\) x \(\dfrac{2}{3}\)  x \(\dfrac{3}{4}\) x \(\dfrac{3}{4}\) x ... x \(\dfrac{99}{100}\)

= \(\dfrac{1}{100}\)

e; \(\dfrac{9}{5}\) : \(\dfrac{17}{15}\) + \(\dfrac{8}{5}\) : \(\dfrac{17}{15}\)

=  \(\dfrac{9}{5}\) x \(\dfrac{15}{17}\) + \(\dfrac{8}{5}\) x \(\dfrac{15}{17}\)

=  \(\dfrac{27}{17}\) + \(\dfrac{24}{17}\)

=  \(\dfrac{51}{17}\)

=   3

a,...48,96,192,384,768.

b,21,25,29,33,37

c,47,60,75,92,111

T i c k cho mk nka

a)48,96,192,384,768

b)21,25,29,33,37
c)49,64,81,100,121

a 1;2;3;6;12;24;48;96;192;384;768.         b1;5;9;13;17;21;25;29;33;37.       c1;4;9;16;25;36;49;64;81;100;121

\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)

\(=\frac{1\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}{4.\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}+\frac{3.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}{4.\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}\)

\(=\frac{1}{4}+\frac{3}{4}=1\)

\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\)

\(=\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{4\left(\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right)}+\frac{3\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}{4\left(\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right)}\)

\(=\frac{1}{4}+\frac{3}{4}\)

=1

Ta có:

\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}=\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{4\left[\frac{1}{9}-\frac{1}{7}-\frac{1}{11}\right]}=\frac{1}{4}\)

Lại có:

\(\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}=\frac{3\left[\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right]}{4\left[\frac{1}{5}-\frac{1}{25}-\frac{1}{125}-\frac{1}{625}\right]}=\frac{3}{4}\)

Vậy: 

\(\frac{\frac{1}{9}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{9}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}=\frac{1}{4}+\frac{3}{4}=1\)

= 698673,6611

= 698673,6611

698673,6611