Ta có : (x + 3) + (x + 5) + (x + 7) + ..... + (x + 21) =  335

=> x + x + x + x + (3 + 5 + 7 + ..... + 21) = 335

=> 10x + 120 = 335

=> 10x = 335 - 120

=> 10x = 215

=> x = 21,5 

ta có : (x + 3) + (x + 5) + (x + 7) + ..... + (x + 21) =  335

<=> x + x + x + x + (3 + 5 + 7 + ..... + 21) = 335

<=> 10x + 120 = 335

=> 10x = 335 - 120

=> 10x = 215

vậy x = 21,5 

a) 8x + ( 2+5+7+12+19+31+50+81) = 447

    8x  + 207 = 447 

     8x          = 447 - 207 = 240

      x           = 240 : 8 = 30

b) 10x + [( 21 + 3 ) x 10 : 2 ] = 335

    10x +  120 = 335

     10x           = 335 - 120 = 215

       x            = 215 : 10 

       x             = 21,5

a) ( x+3 ) + ( x+5 ) + ( x+7 ) +...+ ( x+21)= 335

<=> có 10 cặp

( x+x+x+...+x ) + ( 3+5+7+...+21 ) = 335

=> 10x + 120 = 335

10x = 335 - 120

10x = 215

x = 215 : 10

x = 21,5

A= (x+x+x+....+x+x)+(1+2+3+4+...+37)=999

tìm số số hạng (37-1):1+1=37

tìm tổng 1+2+3+..+37=(37+1)x37:2=703

=>A=37x+703=999

=>37x=999-703=296

=>x=296:37=8

Vậy x=8

a){ x+1} +{x+2}+[x+3]+[x+4]+....+[x+37]=999

=>(x+x+...+x)+(1+2+3+...+37)=999

=>37x+703=999

=>37x=296

=>x=8

( x + 2 ) + ( x + 5 ) + ( x + 7 ) + ( x + 12 ) +....+ ( x + 81 ) = 447.

Ta có dãy fibonaxi:

Dãy đầy đủ là:

      ( x + 2 ) + ( x + 5 ) + ( x + 7 ) + ( x + 12 ) + ( x + 19 ) + ( x + 31 ) + ( x + 50 ) + ( x + 81 ) = 447

=>  x + 2 + x + 5 + x + 7 + x + 12 + x + 19 + x + 31 + x + 50 + x + 81 = 447

=> ( x + x + x + x + x + x + x + x ) + ( 2 + 5 + 7 + 12 + 19 + 31 + 50 + 81 ) = 447

=> 8x + 207 = 447

=> x = ( 447 - 207 ) : 8

=> x = 30. 

Tao học lớp 5 làm sao mà giải được hả?

a, x - 96 = ( 443 - x ) - 15

    x - 96 = 443 - x - 15

    x - 96 = 428 - x 

     x + x = 428 + 96

         2x = 524

           x = 262

b, ( x - 12 ) - 15 = ( 20 - 7 ) - ( 18 - x )

        x - 12 - 15 = 13 - 18 + x 

               x - 27 = - 5 + x

                 x - x = - 5 + 27 

                    0x = 22

=> ko có giá trị nào thõa mãn 

c, 353 - x = 46 + ( 3x - 21 )

    353 - x = 46 + 3x - 21

    353 - x = 25 + 3x 

    - x - 3x = 25 - 353

         - 4x = - 328

             x = 82

d, - ( x + 81 ) = ( 2x +12 ) - ( 5 + x )

         - x - 81 = 2x + 12 - 5 - x

         - x - 81 = x + 7 

           - x - x = 7 + 81

              - 2x = 88

                  x = - 44 

e, ( - x + 821 + 534 ) = 499 + ( x - 84 )

               - x + 1355 = 499 + x - 84

                      - x - x = 499 - 84 - 1355

                         - 2x = - 940

                             x = 470

g, x + 53 = ( 400 - 9x ) - 447

    x + 53 = 400 - 9x - 447

    x + 53 = - 47 - 9x

    x + 9x = - 47 - 53

        10x = -100

           x = - 10

dài wá

mk nhé

wa dai nhung nhin cung de

dễ thì các bạn giải giúp mik nha

\(a,353-x=46+\left(3x-21\right)\)

\(353-x=138x-25\)

\(-x-138x=-25-353\)

\(-139x=-378\Leftrightarrow x=\frac{378}{139}\)

giải hết hộ nhé!!

\(b,-\left(x+81\right)=\left(2x+12\right)-\left(5+x\right)\)

\(-x-81=2x+12-5-x\)

\(-x+x-2x=12-5+81\)

\(-2x=88\Leftrightarrow x=-44\)

a)\(\left(\frac{3}{5}\right)^5\times x=\left(\frac{3}{7}\right)^7\)

\(\Leftrightarrow\frac{3^5}{5^5}\times x=\frac{3^7}{7^7}\)

\(\Leftrightarrow x=\frac{3^7}{7^7}:\frac{3^5}{5^5}\)

\(\Leftrightarrow x=\frac{3^7\times5^5}{7^7\times3^5}\)

\(\Leftrightarrow x=\frac{3^2\times5^5}{7^7}\)

b)\(\left(\frac{-1}{3}\right)^3\times x=\frac{1}{81}\)

\(\Leftrightarrow\frac{\left(-1\right)^3}{3^3}\times x=\frac{1}{3^4}\)

\(\Leftrightarrow x=\frac{1}{3^4}:\frac{-1}{3^3}\)

\(\Leftrightarrow x=\frac{1\times3^3}{3^4\times\left(-1\right)}\)

\(\Leftrightarrow x=\frac{1}{-3}\)

c)\(\Leftrightarrow\left(x-\frac{1}{2}\right)^3=\left(\frac{1}{3}\right)^3\)

\(\Leftrightarrow x-\frac{1}{2}=\frac{1}{3}\)

\(\Leftrightarrow x=\frac{1}{3}+\frac{1}{2}\)

\(\Leftrightarrow x=\frac{5}{6}\)

d)\(\Leftrightarrow\left(x+\frac{1}{2}\right)^4=\left(\frac{2}{3}\right)^4\)

\(\Leftrightarrow x+\frac{1}{2}=\frac{2}{3}\)

\(\Leftrightarrow x=\frac{2}{3}-\frac{1}{2}\)

\(\Leftrightarrow x=\frac{1}{6}\)