:Ap dung tinh chat cua day ti so bang nhau ta co :

1+3y/12=1+5y/5x=1+7y/4x=1+7y-1-5y/4x-5x=2y/-x=1+5y-1-3y/5x-12=2y/5x-12

=>2y/-x=2y/5x-12 voi y=0 thay vao ko thoa man

neu y khac 0 

=>-x=5x-12=>x=2 . Thay x bang 2 vao tren ta dc : 

1+3y/12=2y/-2=-y=>1+3y=-12y=>1=-15y=>y=-1/15

Vay x=2,y=-1/15 thoa man de bai

ta xét 

\(\frac{1+3y}{12}\)= \(\frac{1+5y}{5x}\)

=> (1+3y)5x = (1+5y) 12 

=> 5x + 15xy = 12 + 60y 

=> 5x - 12 = 60y - 15xy 

=> 5x = 60y - 15xy + 12 

đén đây bn thay vào biểu thức còn lại rồi tính nhé 

Đấy mk nói là mk làm mà mk đã cho duong thi hong nhung 5 k rồi đó

a)\(-\frac{2}{5}+\frac{2}{3}x+\frac{1}{6}x=-\frac{4}{5}\Leftrightarrow\frac{5}{6}x=-\frac{2}{5}\Leftrightarrow x=-\frac{12}{25}\)
Vậy nghiệm là x = -12/25

b)\(\frac{3}{2}x-\frac{2}{5}-\frac{2}{3}x=-\frac{4}{15}\Leftrightarrow\frac{5}{6}x=\frac{2}{15}\Leftrightarrow x=\frac{4}{25}\)
Vậy nghiệm là x = 4/25

c)\(\frac{x+1}{10}+\frac{x+1}{11}+\frac{x+1}{12}=\frac{x+1}{13}+\frac{x+1}{14}\)\(\Leftrightarrow\left(x+1\right)\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\right)=0\)
\(\Leftrightarrow x+1=0\left(\frac{1}{10}+\frac{1}{11}+\frac{1}{12}-\frac{1}{13}-\frac{1}{14}\ne0\right)\)\(\Leftrightarrow x=-1\)
Vậy nghiệm là x = -1
 

Cảm ơn bạnh nha. Chúc bạn buổi tối ấm =)))) <3

\(\frac{4}{x}\) \(=\frac{1}{5}\)

Ta có :

\(\frac{4}{x}\) \(=\frac{4}{20}\)

=> \(x=20\)

#Ninh Nguyễn

x.1=4.5

x.1=20

x=20:1

x=20

x.1 = 4.5

x.1 = 20

x    = 20

Vậy x = 20

A = 1/2^2 + 1/3^2 + 1/4^2 + ... + 1/100^2

1/2^2 < 1/1*2

1/3^2 < 1/2*3

1/4^2 < 1/3*4

...

1/100^2 < 1/99*100

=> A < 1/1*2 + 1/2*3 + 1/3*4 + ... + 1/99*100

=> A < 1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + ... + 1/99 - 1/100

=> A < 1 - 1/100

=> A < 1

minh deo can ban k dau :((

\(a,\frac{1}{2}x+\frac{3}{5}(x-2)=3\)

\(\Rightarrow\frac{1}{2}x+\frac{3}{5}x-\frac{6}{5}=3\)

\(\Rightarrow\left[\frac{1}{2}+\frac{3}{5}\right]x=3+\frac{6}{5}\)

\(\Rightarrow\left[\frac{5}{10}+\frac{6}{10}\right]x=\frac{21}{5}\)

\(\Rightarrow\frac{11}{10}x=\frac{21}{5}\)

\(\Rightarrow x=\frac{21}{5}:\frac{11}{10}=\frac{21}{5}\cdot\frac{10}{11}=\frac{21}{1}\cdot\frac{2}{11}=\frac{42}{11}\)

Vậy x = 42/11

Ta có: \(\frac{-19}{6}+\frac{-15}{2}+\frac{11}{3}\)

\(=\frac{-19}{6}+\frac{-45}{6}+\frac{22}{6}\)

\(=\frac{-19-45+22}{6}\)

\(=\frac{-42}{6}=-7\);

\(\frac{-5}{4}+\frac{19}{12}+\frac{-10}{3}\)

\(=\frac{-15}{12}+\frac{19}{12}+\frac{-40}{12}\)

\(=\frac{-15-40+19}{12}\)

\(=\frac{-36}{12}=-3\)

\(\Rightarrow-7< x\le-3\)

\(\Rightarrow x=-6;-5;-4;-3\)

Nhớ k

\(\frac{7}{4}-x+\frac{4}{3}=\frac{5}{19}\)

\(\Rightarrow\frac{7}{4}-x=\frac{5}{19}-\frac{4}{3}\)

\(\Rightarrow\frac{7}{4}-x=-\frac{61}{57}\)

\(\Rightarrow x=\frac{7}{4}+\frac{61}{57}\)

\(\Rightarrow x=???\)

tíc mình nha

\(2\frac{1}{2}-x=\frac{5}{7}-\frac{4}{13}+\frac{1}{4}\)

=> \(\frac{5}{2}-x=\frac{260}{364}-\frac{112}{364}+\frac{91}{364}=\frac{260-112+91}{364}\)

=> \(\frac{5}{2}-x=\frac{239}{364}\)

=> \(x=\frac{5}{2}-\frac{239}{364}=\frac{910}{364}-\frac{239}{364}=\frac{671}{364}\)

\(2\frac{1}{2}-x=\frac{5}{7}-\frac{4}{13}+\frac{1}{4}\)

\(\frac{5}{2}-x=\) \(\frac{239}{364}\)

x= \(\frac{5}{2}-\frac{239}{364}\)

x=\(\frac{671}{364}\)

Chúc bạn học tốt

Trả lời:

\(2\frac{1}{2}-x=\frac{5}{7}-\frac{4}{13}+\frac{1}{4}\)

\(\Leftrightarrow\frac{5}{2}-x=\frac{37}{91}+\frac{1}{4}\)

\(\Leftrightarrow\frac{5}{2}-x=\frac{239}{364}\)

\(\Leftrightarrow x=\frac{671}{364}\)

Vậy \(x=\frac{671}{364}\)

\(x\)là dấu nhân hả bạn? Nếu vậy thì mk làm cho nhé

\(A=\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot....\cdot\left(1-\frac{1}{20}\right)\)

\(A=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot.......\cdot\frac{17}{18}\cdot\frac{18}{19}\cdot\frac{19}{20}=\frac{1}{20}\)

Vậy \(A=\frac{1}{20}\)

\(B=1\frac{1}{2}\cdot1\frac{1}{3}\cdot1\frac{1}{4}\cdot........\cdot1\frac{1}{2005}\cdot1\frac{1}{2006}\cdot1\frac{1}{2007}\)

\(B=\frac{3}{2}\cdot\frac{4}{3}\cdot\frac{5}{4}\cdot......\cdot\frac{2006}{2005}\cdot\frac{2007}{2006}\cdot\frac{2008}{2007}=\frac{2008}{2}=1004\)

Vậy \(B=1004\)

DẤU CHẤM LÀ DẤU NHÂN

a, 

\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}....\frac{19}{20}=\frac{1}{20}\)

b, \(1\frac{1}{2}.1\frac{1}{3}....1\frac{1}{2017}=\frac{3}{2}.\frac{4}{3}....\frac{2018}{2017}=\frac{2018}{2}=1009\)