A=
\(\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
Những câu hỏi liên quan
\(m=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(\frac{7}{3}+\frac{7}{2}\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}:\left(-\frac{43}{42}\right)+\frac{15}{2}\)
\(M=\frac{35}{6}\cdot\left(-\frac{42}{43}\right)+\frac{15}{2}\)
\(M=\frac{35}{1}\cdot\left(-\frac{7}{43}\right)+\frac{15}{2}=-\frac{245}{43}+\frac{15}{2}=\frac{155}{86}\)
\(m=\left(\frac{7}{3}+3,5\right):\left(-\frac{25}{6}+\frac{22}{7}\right)+7,5\)
\(m=\frac{35}{6}:-\frac{25}{6}+7,5\)
\(m=\frac{35}{6}.-\frac{6}{25}+7,5\)
\(m=-\frac{7}{5}+7,5\)
\(m=\frac{61}{10}\)
Tính:
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
Tính: \(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(M=\left(2\frac{1}{3}+3,5\right):\left(-4\frac{1}{6}+3\frac{1}{7}\right)+7,5\)
\(=\left(\frac{7}{3}+\frac{7}{2}\right):\left(\frac{-25}{6}+\frac{22}{7}\right)+\frac{15}{2}\)
\(=\left(\frac{14}{6}+\frac{21}{6}\right):\left(\frac{-175}{42}+\frac{132}{42}\right)+\frac{15}{2}\)
\(=\frac{14+21}{6}:\frac{-175+132}{42}+\frac{15}{2}\)
\(=\frac{35}{6}:\frac{-43}{42}+\frac{15}{2}=\frac{35}{6}.\frac{-42}{43}+\frac{15}{2}\)
\(=\frac{-245}{43}+\frac{15}{2}=\frac{-490}{86}+\frac{645}{86}\)
\(=\frac{-490+645}{86}=\frac{155}{86}\)
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(\(2\frac{1}{3}\)+3,5) :\(\left(-4\frac{1}{6}+3\frac{1}{7}\right)\)+7,5
thực hiện phép tính hợp lí nếu có thể:
a,\(\left(2\frac{1}{3}+3,5\right)\div\left(-4\frac{1}{6}+3\frac{1}{7}\right)+75\%\)
b,\(\left(2\frac{1}{3}+3\frac{1}{2}\right)\div\left(-4\frac{1}{6}+3\frac{1}{7}\right)+2\frac{15}{43}\)
\(\left(2\frac{1}{3}+3,5\right)\div\left(-4\frac{1}{6}+3\frac{1}{7}\right)+75\%\)\(\left(-6\frac{3}{5}\div6-8\times12,5\%-\frac{2}{15}\div0,3\right)\times\left(-0,5\right)+1\)\(\left(2\frac{1}{3}+3\frac{1}{2}\right)\div\left(-4\frac{1}{6}+3\frac{1}{7}\right)+2\frac{15}{43}\)
Thực hiện phép tínha)16frac{2}{7}:left(frac{-3}{5}right)+28frac{2}{7}:frac{3}{5}b)left(2^2:frac{4}{3}-frac{1}{2}right).frac{6}{5}-17c)left(frac{1}{3}right)^{50}.left(-9right)^{25}-frac{2}{3}:4d)frac{3}{5}:left(frac{-1}{15}-frac{1}{6}right)+frac{3}{5}:left(frac{-1}{3}-1frac{1}{15}right)e)left(-6,5right).5,7+5,7.left(-3,5right)
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Thực hiện phép tính
a)\(16\frac{2}{7}:\left(\frac{-3}{5}\right)+28\frac{2}{7}:\frac{3}{5}\)
b)\(\left(2^2:\frac{4}{3}-\frac{1}{2}\right).\frac{6}{5}-17\)
c)\(\left(\frac{1}{3}\right)^{50}.\left(-9\right)^{25}-\frac{2}{3}:4\)
d)\(\frac{3}{5}:\left(\frac{-1}{15}-\frac{1}{6}\right)+\frac{3}{5}:\left(\frac{-1}{3}-1\frac{1}{15}\right)\)
e)\(\left(-6,5\right).5,7+5,7.\left(-3,5\right)\)
a: \(=\dfrac{5}{3}\left(-16-\dfrac{2}{7}+28+\dfrac{2}{7}\right)=\dfrac{5}{3}\cdot12=20\)
b: \(=\left(4\cdot\dfrac{3}{4}-\dfrac{1}{2}\right)\cdot\dfrac{6}{5}-17=\dfrac{1}{2}\cdot\dfrac{6}{5}-17=\dfrac{3}{5}-17=-\dfrac{82}{5}\)
c: \(=-\left(\dfrac{1}{3}\right)^{50}\cdot3^{50}-\dfrac{2}{3}\cdot\dfrac{1}{4}=-1-\dfrac{1}{6}=-\dfrac{7}{6}\)
e: \(=5.7\left(-6.5-3.5\right)=-5.7\cdot10=-57\)
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left(frac{3}{8}+frac{-3}{4}+frac{7}{12}right):frac{5}{6}+frac{1}{2}frac{1}{2}+frac{3}{4}-left(frac{3}{4}-frac{4}{5}right)6frac{5}{12}:2frac{3}{4}+11frac{1}{4}left(frac{1}{3}-frac{1}{5}right)left(frac{7}{8}-frac{3}{4}right)1frac{1}{3}-frac{2}{7}left(3,5right)^2left(frac{3}{5}+0,415-frac{3}{200}right)2frac{2}{3}.0,25Thực hiện các phép tínhcảm ơn
Đọc tiếp
\(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}\left(\frac{1}{3}-\frac{1}{5}\right)\)
\(\left(\frac{7}{8}-\frac{3}{4}\right)1\frac{1}{3}-\frac{2}{7}\left(3,5\right)^2\)
\(\left(\frac{3}{5}+0,415-\frac{3}{200}\right)2\frac{2}{3}.0,25\)
Thực hiện các phép tính
cảm ơn
\(\left(\frac{3}{8}+-\frac{3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\left(\frac{9}{24}+-\frac{18}{24}+\frac{14}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}:\frac{5}{6}+\frac{1}{2}\)
\(=\frac{5}{24}.\frac{6}{5}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{1}{2}\)
\(=\frac{1}{4}+\frac{2}{4}\)
\(=\frac{3}{4}\)
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\(\frac{1}{2}+\frac{3}{4}-\left(\frac{3}{4}-\frac{4}{5}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\left(\frac{15}{20}-\frac{16}{20}\right)\)
\(=\frac{1}{2}+\frac{3}{4}-\frac{-1}{20}\)
\(=\frac{10}{20}+\frac{15}{20}-\frac{-1}{20}\)
\(=\frac{25}{20}-\frac{-1}{20}\)
\(=\frac{26}{20}\)
\(=\frac{13}{10}\)
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1/2+3/4-(3/4-4/5)
1/2+3/4+3/4+4/5
1/2+6/4+4/5
10/20+30/20+16/20
56/20=14/5
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Đọc tiếp
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\(\frac{1}{8}-1\frac{3}{4}+\left(\frac{7}{8}-3\frac{7}{2}+\frac{3}{4}\right)-\left[\frac{7}{4}-\frac{5}{8}\right]\)
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