Q = \(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).203\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
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15 tháng 1 2020 lúc 23:18
tính :
\(Q=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).203\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(A=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Tính:
\(E=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}.\)
Tính A = \(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Đặt : \(A=\frac{\left[13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right]\cdot230\frac{1}{25}+46\frac{3}{4}}{\left[1\frac{3}{10}+\frac{10}{3}\right]:\left[12\frac{1}{3}-14\frac{2}{7}\right]}\)
\(A=\frac{\left[\frac{53}{4}-\frac{59}{27}-\frac{65}{6}\right]\cdot\frac{5751}{25}+\frac{187}{4}}{\left[\frac{13}{10}+\frac{10}{3}\right]:\left[\frac{37}{3}-\frac{100}{7}\right]}\)
\(A=\frac{\left[\frac{1431}{108}-\frac{236}{108}-\frac{1170}{108}\right]\cdot\frac{5751}{25}+\frac{187}{4}}{\left[\frac{39}{30}+\frac{100}{30}\right]:\left[\frac{259}{21}-\frac{300}{21}\right]}\)
\(A=\frac{\frac{25}{108}\cdot\frac{5751}{25}+\frac{187}{4}}{\frac{139}{30}:\left[-\frac{41}{21}\right]}\)
\(A=\frac{\frac{5751}{108}+\frac{187}{4}}{\frac{139}{30}\cdot\left[-\frac{21}{41}\right]}\)
\(A=\frac{\frac{5751}{108}+\frac{5049}{108}}{-\frac{973}{410}}=\frac{100}{-\frac{973}{410}}=-\frac{41000}{973}\)
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\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Đề bài là tính nha !
\(E=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)