5^2x—3–2.5²=5².3( đề vầy phải ko bạn)

5^2x—3–2.25=25.3

5^2x—3–2.25=75

5^2x—3–2=75:25

5^2x—3–2=3

5^2x—3=3+2

5^2x—3=5¹

==> 2x—3=1

==> 2x=1+3

==> 2x=4

x=4:2

x=2

|2x—7| =20+5.(—3)

|2x—7| = 20+(—15)

|2x—7| = 5

==> 2x—7=—5 hoặc 2x—7=5

==> 2x=—5+7 hoặc 2x= 5+7

==> 2x= 2 hoặc 2x=12

==> x=2:2 hoặc x=12:2

==> x=1 hoặc x=6

a) (9x+2).3=60

      9x+2    = 60:3

      9x+2    = 20

      9x        = 20-2

      9x        = 18

        x        = 2

c) \(44-7x=3^4:3^2\)

    \(44-7x=9\)

                \(7x=44-9\)

                \(7x=35\)

                   \(x=5\)

Hok tốt nha^^

thanks chúc bạn học tốt

1) \(7.4^x=7.4^3\Leftrightarrow4^x=4^3;x=3\)

2) \(\frac{3}{2.5^x}=\frac{3}{2.5^{12}}\Leftrightarrow5^x=5^{12};x=12\)

\(2^x=2.2^8=2^9;x=9\)

4) \(5.3^x=7.3^5-2.3^5\Leftrightarrow5.3^x=3^5.\left(7-2\right)\)

\(\Leftrightarrow3^5.x=3^5.5;x=5\)

e) 96-5(2x-1)=41

5(2x-1)= 96-41

5(2x-1)=55

2x-1=55:5

2x-1=11

2x=11+1

2x=12

x=12:2

x=6

2\(^x\)- 15 = 17

\(\Rightarrow\)2\(^x\) =  32

\(\Rightarrow\)x  = 5

2^x-15=17

=>2^x=17+15

=2^x=32

=>2^x=2^5

=>x=5

`#3107`

b)

`2.3^x = 162`

`\Rightarrow 3^x = 162 \div 2`

`\Rightarrow 3^x = 81`

`\Rightarrow 3^x = 3^4`

`\Rightarrow x = 4`

Vậy, `x = 4`

c)

`(2x - 15)^5 = (2 - 15)^3`

\(\Rightarrow \)`(2x - 15)^5 - (2x - 15)^3 = 0`

\(\Rightarrow \)`(2x - 15)^3 . [ (2x - 15)^2 - 1] = 0`

\(\Rightarrow\left[{}\begin{matrix}\left(2x-15\right)^3=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}2x=15\\\left(2x-15\right)^2=\left(\pm1\right)^2\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x-15=1\\2x-15=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\2x=16\\2x=-14\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=-7\end{matrix}\right.\)

Vậy, `x \in`\(\left\{-7;8;\dfrac{15}{2}\right\}.\)

`d)`

\(3^{x+2}-5.3^x=?\) Bạn ghi tiếp đề nhé!

`e)`

\(7\cdot4^{x-1}+4^{x-1}=23?\)

\(4^{x-1}\cdot\left(7+1\right)=23\\ \Rightarrow4^{x-1}\cdot8=23\\ \Rightarrow4^{x-1}=\dfrac{23}{8}\)

Bạn xem lại đề!

`f)`

\(2\cdot2^{2x}+4^3\cdot4^x=1056\)

\(\Rightarrow2\cdot2^{2x}+\left(2^2\right)^3\cdot\left(2^2\right)^x=1056\\ \Rightarrow2\cdot2^{2x}+2^6\cdot2^{2x}=1056\\ \Rightarrow2^{2x}\cdot\left(2+2^6\right)=1056\\ \Rightarrow2^{2x}\cdot66=1056\\ \Rightarrow2^{2x}=1056\div66\\ \Rightarrow2^{2x}=16\\ \Rightarrow2^{2x}=2^4\\ \Rightarrow2x=4\\ \Rightarrow x=2\)

Vậy, `x = 2`

_____

\(10 -{[(x \div 3+17) \div 10+3.2^4] \div 10}=5\)

\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=10-5\)

\(\Rightarrow\left[\left(x\div3+17\right)\div10+48\right]\div10=5\)

\(\Rightarrow\left(x\div3+17\right)\div10+48=50\)

\(\Rightarrow\left(x\div3+17\right)\div10=2\)

\(\Rightarrow x\div3+17=20\)

\(\Rightarrow x\div3=3\\ \Rightarrow x=9\)

Vậy, `x = 9.`

(2x - 6)⁵ = (2x - 6)²

=> (2x - 6)⁵ - (2x - 6)² = 0

=> (2x - 6)².[(2x - 6)³ - 1] = 0

=> \(\orbr{\begin{cases}\left(2x-6\right)^2=0\\\left(2x-6\right)^3-1=0\end{cases}}\)

=> \(\orbr{\begin{cases}2x-6=0\\\left(2x-6\right)^3=1\end{cases}}\)

=> \(\orbr{\begin{cases}2x=6\\2x-6=1\end{cases}}\)

=> \(\orbr{\begin{cases}x=3\\2x=7\end{cases}}\)

=> \(\orbr{\begin{cases}x=3\\x=\frac{7}{2}\left(ktm\right)\end{cases}}\)

3^{3x - 4} - x⁰ = 8

=> 3^{3x - 4} - 1 = 8

=> 3^{3x - 4} = 8 +1 

=> 3^{3x - 4} = 9

=> 3^{3x - 4}= 3²

=> 3x - 4 = 2

=> 3x = 2 + 4

=> 3x = 6

=> x = 6 : 3 = 2

câu thứ 2 đề bài là 3^2x-4 - x⁰=8

\(\left(7-x\right)^2=16\)

\(7-x=\sqrt{16}\)

\(7-x=4\)

\(x=7-4\)

\(x=3\)

\(5^2x-3-2.5^2=5^2.3\)

\(5^2-3=5^2.3+5^2.2\)

\(5^2-3=5^2\left(3+2\right)\)

\(5^2-3=5^2.5\)

\(25-3=25.5\)

bn xem lại đề nhé

Cái kí hiệu bên trái của số 16 là gì vậy....

\(\text{Là căn bậc hai nhé}\)