4 mu x = 4mu3 × 4mu5
2mux = 8× 128
1.tính
5871:[928-(247-82.5)]
2,tìm x bít
a)128-3.(x+4)=22
b)(12x-4mu3).8mu3=4.8mu4
\(5871:\left[928-\left(247-82.5\right)\right]\)
\(=5871:\left[928-\left(247-460\right)\right]\)
\(=5871:\left[928-\left(-213\right)\right]\)
\(=5871:1141\)
tim x thuoc N:
a) 2 mu x =4 nhan 128
b)2 mu x nhan 3 mu x =4 nhan 9
2^x = 4 . 128 = 512
2^x = 2^9
=> x = 9
b) 2^x . 3^x = 4.9
=> 2^x . 3^x = 36
=> x = 2
2\(^x\)=4.128
2\(^x\)=512
2\(^x\)=2\(^9\)
=> x=9
đúng nha
Cậu ấn vô đây:Giúp tôi giải toán - Hỏi đáp về toán học - Học toán với OnlineMath
1.tim x thuoc n biet:
a)3 mu x .3 b)x mu 20 = x c)2 mu x.16 mu 2=1024 d)64.4 mu x=16 mu 8
2.tim n thuoc n sao:
a)3 mu 2.3 mu n=3 mu 5 b)(2 mu 2:4).2mu n=4 c)32<2 mu n<128 d)2.16>_2 mu n>4
ai giai dung va nhanh minh tick cho
tim so hang thu 50 cua cac day so sau
a,1.6,2.7,3.8,.....
b,3,8,15,24,35,........
c,1.4;4.7;7.10;.....
d3+1 mu 3;3+2mu3;3+3mu3;3+4mu3;.......
tìm n thuộc N sao cho 16 mu x < 128 mũ 4
16x<1284
=> 16x<1632
Vì n\(\in\)N => x<32 => x\(\in\){0;1;2;3;...;31}
x\(\in\)N* 16x < 1284
16x=(24)x=24x
1284=(27)4=24.7
Vì 24x < 24.7
Nên x<7
Vậy x\(\in\){0;1;2;3;4;5;6}
4mu x.4mu3=256 tìm x
\(\Rightarrow4^x=4^4:4^3=4^1\\ \Rightarrow x=1\)
( x - 1 ) mu 2 : 5 mu 21 = 25 mu 30 . 5
2.3 mu x + 1 = 10.3 mu 12 + 8 : 27 mu 4
( 19x + 2 .5 mu 2) : 14 = ( 13 - 8 ) mu 2
1351 - 2 . ( x + 3) = 4 mu 12 : 8 mu 7 + 3
mong m.n giup mk vs !!!!
(x-1)^2:5^21=25^30.5
(x-1)^2=25^30.5.5^21
=(5^2)^30.5^22
= 5^60.5^22
(x-1)^2 =5^82
(x-1)^2=(5^41)^2
x-1=5^41
x=5^41+1
2.3^x+1=10.3^12+8:3^12
2.3^x+1=10+8=18
3^x+1=18/2=9
3^x+1=3^2
x+1=2
x=1
Tìm X biết :
x - 5 = 7 mu 10 :7 mu 8 + 2 mu 2018 nhan ( 2 mu 4 - 4 mu 2)
B1) Tinh
a) 245-4 . [15: 8 +2.(4+3 mu 2 -9)]
b) 375: 5 mu 3 -( 3 mu 8: 3 mu 6 -2 .2 mu 3)
B2: Tim x
a) 2x -2 mu 3 .3 mu 2=138
b) ( 6x- 3 mu 4) . 7 mu 3= 3 . 7 mu 4
c) 1+2+3+..............+x =500500