a)\(\frac{1}{100.99}-\frac{1}{99.98}-\frac{1}{98.97}-.....-\frac{1}{3.2}-\frac{1}{1.2}\) \(\frac{\frac{1}{4}-\frac{1}{7}-\frac{1}{11}}{\frac{4}{4}-\frac{4}{7}-\frac{4}{11}}+\frac{\frac{3}{5}-\frac{3}{25}-\frac{3}{125}-\frac{3}{625}}{\frac{4}{5}-\frac{4}{25}-\frac{4}{125}-\frac{4}{625}}\) \(\frac{\left(1+2+3+.....+100\right).\left(\frac{1}{3}-\frac{1}{5}-\frac{1}{7}-\frac{1}{9}\right).\left(6,3.12-21.3,6\right)}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+....+\frac{1}{100}}\)
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