giúp mik vs 4h 30 ) hc rồi

\(\frac{0,1\left(6\right)+0,\left(3\right)}{0,\left(3\right)+1,1\left(6\right)}-x=0,\left(2\right)\)

\(\Rightarrow\frac{\frac{1}{6}+\frac{1}{3}}{\frac{1}{3}+\frac{7}{6}}-x=\frac{2}{9}\)

\(\Rightarrow\frac{\frac{1}{2}}{\frac{3}{2}}-x=\frac{2}{9}\)

\(\Rightarrow\frac{1}{3}-x=\frac{2}{9}\)

\(\Rightarrow x=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)

Vậy \(x=\frac{1}{9}\)

B1      :

\(\frac{0,1\left(6\right)+0,\left(3\right)}{0,\left(3\right)+1,1\left(6\right)}\) . x = 0,(2)

=\(\frac{0,5}{1,5}\).x=0,(2)

x=0,(2):\(\frac{0,5}{1,5}\)

x=0,(6)=\(\frac{2}{3}\)

b2:

 [12,(1) - 2,3(6)] : 4,(21)

=9,7(4):4,(21)

=\(\frac{9,7\left(4\right)}{4,\left(21\right)}\)

di ban

Đặt GTBT là A, ta có:

A=0,5+0,(3)−0,1(6)2,5+1,(6)−0,8(3) 

A=12 +13 −16 52 +53 −56  

A=12 +13 −16 5(12 +13 −16 ) =15 

bạn tự điền mấy cái dấu gach p/s nha

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chúc bạn học tốt

Đặt GTBT là A, ta có:

A=0,5+0,(3)−0,1(6)2,5+1,(6)−0,8(3)

A=12+13−1652+53−56

A=12+13−165(12+13−16)=15

0,5+0,(3)+0,1(6)/2,5+0,1(6)+0,8(3)

=0,5+1/3+1/6/2,5+1/6+5/6

=1/3,5=2/7

k mk nha

Đặt GTBT là A, ta có:

\(A=\frac{0,5+0,\left(3\right)-0,1\left(6\right)}{2,5+1,\left(6\right)-0,8\left(3\right)}\)

\(A=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{\frac{5}{2}+\frac{5}{3}-\frac{5}{6}}\)

\(A=\frac{\frac{1}{2}+\frac{1}{3}-\frac{1}{6}}{5\left(\frac{1}{2}+\frac{1}{3}-\frac{1}{6}\right)}=\frac{1}{5}\)

1 ơi + 2 ơi= mấy ơi

\(\frac{1}{5}\)nhé

hok tốt

\(G=\dfrac{\dfrac{1}{2}+\dfrac{1}{3}-\dfrac{1}{6}}{\dfrac{5}{2}+\dfrac{5}{3}-\dfrac{5}{6}}=\dfrac{1}{5}\)

\(H=\left[\dfrac{32}{99}\cdot\dfrac{14}{9}-\dfrac{25}{99}\right]\cdot\dfrac{11}{83}\)

\(=\dfrac{223}{891}\cdot\dfrac{11}{83}=\dfrac{223}{6723}\)