x*12,5 -x +x *2,75=1050

x*12,5 -x*1+x*2,75=`1050

x*(12,5-1+2,75)=1050

x*14,25=1050

        x=1050:14,25

        x= 73,68421053

Bạn chú thích hơi quá lố :) 

Ta có :( 5x - 3y + 4z ) . ( 5x - 3y - 4z ) \(=\left(5x-3y\right)^2-16z^2\)

\(=25x^2-30xy+9y^2-16z^2\)

Mà x^2=y^2 + z^2 nên ( 5x - 3y + 4z ) . ( 5x - 3y - 4z )\(=25x^2-30xy+9y^2-16\left(x^2-y^2\right)\)

\(=9x^2-30xy+25y^2=\left(3x-5y\right)^2\)

Học tốt !

\(\left(5x-3y+4z\right)\left(5x-3y-4z\right)=\left(3x-5y^2\right)\)

\(\Leftrightarrow\left(5x-3y\right)^2-16z^2-\left(3x-5y\right)^2=0\)

\(\Leftrightarrow\left(5x-3y-3x+5y\right)\left(5x-3y+3x-5y\right)-16z^2=0\)

\(\Leftrightarrow16x^2=16y^2+16z^2\)(luôn đúng)

 \(a^2-3ab+2c=0\)

\(\Leftrightarrow\left(x+y\right)^2-3\left(x+y\right)\left(x^2+y^2\right)+2\left(x^3+y^3\right)=0\)

\(\Leftrightarrow x^2+y^2+2xy-3x^3-3xy^2-3yx^2-3y^3+2y^3+2x^3=0\)

\(\Leftrightarrow\left(x+y\right)^2-\left(x+y\right)^3=0\)

Hình như đề hơi sai nếu là a^3 thì ms đúng chứ

mk chỉ góp ý thui tại làm mãi ko ra

hhihihihi

a. 100 - 7 (  x - 5 ) = 58 
<=>      7 ( x - 5 )  = 100 - 58 

<=>     7 ( x - 5 )   = 42 

<=>          x - 5     = 42 : 7 

<=>          x - 5     = 6 

<=>         x           = 6 + 5 

<=>         x           = 11 

Tương tự tiếp. 

a;100-7(x-5)=58

=>7(x-5)=100-58=42

=>x-5=42:7=6

=>x=6+5=11

b;12(x-1):3=72

=>12(x-1)=72.3=216

=>x-1=216:12=18

=>x=18+1=19

c;12-4(x-1)=4

=>4(x-1)=12-4=8

=>x-1=8:4=2

=>x=2+1=3

d;32-12x=8

=>12x=32-8=24

=>x=24:12=2

nho h do nhe viet moi tay lam day biet ko

a) 100 - 7 {x - 5} =58                            b)12 { x -1}:3 = 72                   c) 12 - 4 { x - 1 } =  4

             7 {x - 5 } = 100 - 58                      12 { x - 1} = 72 x 3                          4 {x -1 } = 12-4 

            7 {x - 5} = 42                                  12 { x - 1 } =216                             4 { x - 1} = 8 

                x - 5   = 42:7                                x -1 = 216:12                                x - 1 =8:4

                x - 5 = 6                                    x - 1 = 18                                         x - 1 = 2

              x = 6 +5                                          x = 18 +1                                      x = 2+ 1 

             x  = 11                                              x = 19                                            x = 3

                                                                     Bài giải

a, \(\left(x-5\cdot9\right)\cdot2=0\)

\(x-45=0\)

\(x=45\)

b, \(40\cdot\left(x-2\right)=40\)

\(x-2=1\)

\(x=3\)

c, \(\left(x-4\right)\cdot3+2=101\)

\(\left(x-4\right)\cdot3=99\)

\(x-4=33\)

\(x=37\)

Bài làm :

\(a,\left(x-5.9\right).2=0\)

\(\Rightarrow x-45=0\)

\(\Rightarrow x=0+45\)

\(\Rightarrow x=45\)

\(b,40.\left(x-2\right)=40\)

\(\Rightarrow x-2=40:40\)

\(\Rightarrow x-2=1\)

\(\Rightarrow x=3\)

\(c,\left(x-4\right).3+2=101\)

\(\Rightarrow\left(x-4\right).3=99\)

\(\Rightarrow x-4=99:3\)

\(\Rightarrow x-4=33\)

\(\Rightarrow x=37\)

Học tốt nhé

a) -12.(x - 5) + 7(3 - x) = 5

=> -12x + 60 + 21 - 7x = 5

=> -19x + 81 = 5

=> -19x = 5 - 81

=> -19x = -76

=> x = -76 : (-19)

=> x = 4

b) (x + 1) + (x + 2) + (x + 3) + ... + (x + 20) = 250

=> (x + x + x + ... + x) + (1 + 2 + 3 + ... + 20) = 250

=> 20x + 210 = 250

=> 20x = 250 - 210

=> 20x = 40

= > x = 40 : 20

=> x = 2

\(-12\left(x-5\right)+7\left(3-x\right)=5\)

\(\Leftrightarrow-12x+60+21-7x=5\)

\(\Leftrightarrow-19x+81=5\)

\(\Leftrightarrow81-5=19x\)

\(\Leftrightarrow19x=76\)

\(\Leftrightarrow x=4\)

\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+20\right)=250\)

\(\Leftrightarrow20x+\left(1+2+3+...+20\right)=250\)

\(\Leftrightarrow20x+\frac{20\left(20+1\right)}{2}=250\)

\(\Leftrightarrow20x+210=250\)

\(\Leftrightarrow20x=40\)

\(\Leftrightarrow x=2\)

a) \(215+x=400\)

\(\Rightarrow x=400-215\)

\(\Rightarrow x=185\)

b) \(12,5-2x=\dfrac{1}{5}\)

\(\Rightarrow2x=12,5-\dfrac{1}{5}\)

\(\Rightarrow2x=\dfrac{123}{10}\)

\(\Rightarrow x=\dfrac{123}{10}:2\)

\(\Rightarrow x=\dfrac{123}{20}\)

còn câu c d nhanh cậu ơi

Bạn xem lại đề phần e nha .

\(c)x.0,25-\dfrac{3}{25}:x=2\dfrac{1}{4}\)

\(x.0,25-\dfrac{25}{3}.x=\dfrac{9}{4}\)

\(x.\left(0,25-\dfrac{25}{3}\right)=\dfrac{9}{4}\)

\(x.\dfrac{-97}{12}=\dfrac{9}{4}\)

\(x=\dfrac{-27}{97}\)

\(d)\left(x-\dfrac{1}{3}\right).\left(x-\dfrac{1}{4}\right)=0\)

Do : 2 số đó nhân với nhau bằng 0 nên một trong 2 số là số 0.

Do đó :

\(Th1:x-\dfrac{1}{3}=0\)

\(x=\dfrac{1}{3}\)

\(Th2:x-\dfrac{1}{4}=0\)

\(x=\dfrac{1}{4}\)

\(a,\left(x+\frac{1}{2}\right)+\left(x+\frac{1}{4}\right)+\left(x+\frac{1}{8}\right)+\left(x+\frac{1}{16}\right)=1\)

\(\Leftrightarrow x+\frac{1}{2}+x+\frac{1}{4}+x+\frac{1}{8}+x+\frac{1}{16}=1\)

\(\Leftrightarrow\left(x+x+x+x\right)+\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)=1\)

\(\Leftrightarrow4\times x+\frac{15}{16}=1\)

\(\Leftrightarrow4\times x=1-\frac{15}{16}\)

\(\Leftrightarrow4\times x=\frac{1}{16}\)

\(\Leftrightarrow x=\frac{1}{16}\div4\)

\(\Leftrightarrow x=\frac{1}{64}\)

\(b,x-\frac{20}{11.13}-\frac{20}{13.15}-...-\frac{20}{53.55}=\frac{3}{11}\)

\(\Leftrightarrow x-\left(\frac{20}{11.13}+\frac{20}{13.15}+...+\frac{20}{53.55}\right)=\frac{3}{11}\)

\(\Leftrightarrow x-\left[715\times\left(\frac{1}{11}-\frac{1}{13}-\frac{1}{13}+...+\frac{1}{55}\right)\right]=\frac{3}{11}\)

\(\Leftrightarrow x-\left[715\times\left(\frac{1}{11}-\frac{1}{55}\right)\right]=\frac{3}{11}\)

\(\Leftrightarrow x-\left[715\times\frac{4}{55}\right]=\frac{3}{11}\)

\(\Leftrightarrow x-52=\frac{3}{11}\)

\(\Leftrightarrow x=\frac{3}{11}+52\)

\(\Leftrightarrow x=\frac{575}{11}\)

A) \(2x+12=36\)

\(\Leftrightarrow2x=36-12\)

\(\Leftrightarrow2x=24\)

\(\Leftrightarrow x=12\)

B) \(\left(x+21\right):8+12=20\)

\(\Leftrightarrow\left(x+21\right):8=20-12\)

\(\Leftrightarrow\left(x+21\right):8=8\)

\(\Leftrightarrow x+21=64\)

\(\Leftrightarrow x=43\)

C) \(\frac{1}{2}+\frac{3}{4}x=\frac{3}{2}\)

\(\Leftrightarrow\frac{3}{4}x=\frac{3}{2}-\frac{1}{2}\)

\(\Leftrightarrow\frac{3}{4}x=1\)

\(\Leftrightarrow x=\frac{4}{3}\)

k tớ trc ik tớ lm cho *hỳ hỳ*