Tìm X biết X x 2012 - X = 2012 x 2010 + 2012
x-2012/2008-x-2012/2009=x-2012/2010-x-2012/2011.tìm x
Tìm x biết:
a) |x - 2011| = x - 2012
b) |x - 2010| + |x - 2011| = 2012
suy ra hai truong hop
1 : x-2011=x-2012
suy ra x-x=2011-2012(loai)
2 : x-2011=-(x-2012)
suy ra : x-2011=-x+2012
2x=2011+2012
2x=4023
x=2011.5
kho..................lam............................tich,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,minh..........................troi........................ret............................wa.................ung ho minh.................hu....................hu..............hu................hat..............hat....................s
Cau a biet lam roi de lam cau b cho:
Ta thay:tong 2 so hang do la tong 2 so tu nhien lien tiep nen se la so le (*) ma 2012 la so chan(trai voi "*")
=>Khong ton tai so nguyen x thoa man
Vay khong ton tai so nguyen x thoa man
Tìm x, biết :
\(\frac{x-1}{2012}+\frac{x-2}{2011}+\frac{x-3}{2010}+...+\frac{x-2012}{1}=2012\)
Ta có :
\(\frac{x-1}{2012}+\frac{x-2}{2011}+\frac{x-3}{2010}+...+\frac{x-2012}{1}=2012\)
\(\Leftrightarrow\)\(\left(\frac{x-1}{2012}-1\right)+\left(\frac{x-2}{2011}-1\right)+\left(\frac{x-3}{2010}-1\right)+...+\left(\frac{x-2012}{1}-1\right)=2012-2012\)
\(\Leftrightarrow\)\(\frac{x-2013}{2012}+\frac{x-2013}{2011}+\frac{x-2013}{2010}+...+\frac{x-2013}{1}=0\)
\(\Leftrightarrow\)\(\left(x-2013\right)\left(\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}+...+\frac{1}{1}\right)=0\)
Vì \(\left(\frac{1}{2012}+\frac{1}{2011}+\frac{1}{2010}+...+1\right)\ne0\)
\(\Rightarrow\)\(x-2013=0\)
\(\Rightarrow\)\(x=2013\)
Vậy \(x=2013\)
Chúc bạn học tốt
Tìm x biết:
a. |x - 2011| = x - 2012
b. |x -2010| + |x - 2011| = 2012
Tìm x biết (1/2+1/3+...+1/2012+1/2013).x = 2012/1+2011/2+2010/3+...+2/2011+1/2012
tìm x biết:
(1/2+1/3+...+1/2012+1/2013).x = 2012/1+2111/2+2010/3+...+2/2011+1/2012
tìm X biết : ( 1 / 2 + 1/3 + ........+ 1 /2012 + 1/2013 ) . x = 2012/1 + 2011/2 + 2010 /3 + .....+2/2011+1/2012
Tìm x biết:
a. |x - 2011| = x - 2012
b. |x -2010| + |x - 2011| = 2012
Lm đi, mk tick cho
/x-2011/ = x - 2012
<=> x -2011 = x-2012 (1) hoặc x-2011= - (x-2012) (2)
từ (1) => x-2011 = x-2012
<=> x-x = -2012+2011
<=> 0x = -1 (vô lí)
từ (2) => x-2011 = - ( x-2012)
<=> x-2011 = -x + 2012
<=> x+x = 2012 + 2011
<=> 2x =4023
<=> x =2011,5
Tìm x biết
a) \(|x-2011|=x-2012\)
b) \(|x-2010|+|x-2011|=2012\)
c) \(|x-2010|+|x-2011|=2012\)
a, Đ/k x-2012>=0 suy ra x>=2012
|x-2011|=\(\orbr{\begin{cases}x-2012\\2012-x\end{cases}}\)
TH1:x-2011=x-2012
suy ra 0=4023(loại vì mất x)
TH2: x-2011=2012-x
suy ra 2x=4023
suy ra x=2011,5
Vậy..........
k o b i ế t n h a
Hoàng Khôi Phong ( ɻɛɑm ʙáo cáo ) ko nói linh tinh mk sẽ tặng bạn một vé báo cáo siêu vip nhé=)))