9999 x 9999 - 9999 + 9999 * 9999=199950003

8888 x 8888 - 8888 + 8888 * 8888 =78987656

7777 x 7777 - 7777 + 7777 * 7777 =120955681

9999 x 9999 - 9999 + 9999 * 9999=199950003

8888 x 8888 - 8888 + 8888 * 8888 =157984200

7777 x 7777 - 7777 + 7777 * 7777 =120955681

1)199950003

2)78996544

3)120955681

3333*3333:9999

=3333*3333:3333:3

=3333:3=1111

b,2222*9999:3333

=2222*3333*3:3333

=2222*3=6666

c,99999*88888:11111

=99999*11111*8:11111

=99999*8=799992

d, 6666*8+4444*14

=1111*8*6+1111*4*14

=1111*48+1111*56

=1111*(48+56)

=1111*104=115544

ba câu đầu bạn làm đúng rồi shitbo.nhưng câu cuối bạn làm sai.cố lên nha bạn.mình đâu

9999/9999  × 1 = 1×1=1

9999/9999 .1=9999/9999

\(\frac{9999}{9999}\times1=\frac{9999}{9999}\)

Chúc bạn học tốt. Nhớ k cho mk nhé

cảm ơn bạn nha

 đáp án là bằng :99 980 001

Nếu mình chính xác hãy cho mình 1 like đúng nha!!!!!!!!!!!!

(  ) x 9999 x 9999 x 9999 x ... ( có 1000 số 9999 )  x 38 x 45 x 36 x 25 x 58 x 69 x 245 x 246 x 213 x 222 x 546 x 8312 x 999 x 454 x 9999 x 789 x 2563 x 0 x 25 x 24 x 23 x 26 258 x 256 256 x 256 x 24531 x 55 x ( 45 x 1 + 45 x 2 + 45 x 3 + ... + 45 x 1000 +  45 x 1001 + ... + 45 x 9999 ) = 0 nhé

/HT\

(  ) x 9999 x 9999 x 9999 x ... ( có 1000 số 9999 )  x 38 x 45 x 36 x 25 x 58 x 69 x 245 x 246 x 213 x 222 x 546 x 8312 x 999 x 454 x 9999 x 789 x 2563 x 0 x 25 x 24 x 23 x 26 258 x 256 256 x 256 x 24531 x 55 x ( 45 x 1 + 45 x 2 + 45 x 3 + ... + 45 x 1000 +  45 x 1001 + ... + 45 x 9999 ) =  0

HT

@@@@@@@

  ) x 9999 x 9999 x 9999 x ... ( có 1000 số 9999 )  x 38 x 45 x 36 x 25 x 58 x 69 x 245 x 246 x 213 x 222 x 546 x 8312 x 999 x 454 x 9999 x 789 x 2563 x 0 x 25 x 24 x 23 x 26 258 x 256 256 x 256 x 24531 x 55 x ( 45 x 1 + 45 x 2 + 45 x 3 + ... + 45 x 1000 +  45 x 1001 + ... + 45 x 9999 ) = 0 

k cần

1000879902

nhân chia trước cộng trừ sau nha

Trl : 1000879902

9999 x 9999 = 99980001 nhé

9999 x 9999 = 99980001

9999x9999=99980001 nha

HT

\(A=\frac{1}{10}+\frac{1}{40}+\frac{1}{88}+\frac{1}{154}+\frac{1}{238}+\frac{1}{340}\)

\(A=\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\)

\(3A=3.\left(\frac{1}{2.5}+\frac{1}{5.8}+\frac{1}{8.11}+\frac{1}{11.14}+\frac{1}{14.17}+\frac{1}{17.20}\right)\)

\(3A=\frac{3}{2.5}+\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+\frac{3}{14.17}+\frac{3}{17.20}\)

\(3A=\frac{5-2}{2.5}+\frac{8-5}{5.8}+\frac{11-8}{8.11}+\frac{14-11}{11.14}+\frac{17-14}{14.17}+\frac{20-17}{17.20}\)

\(3A=\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{17}+\frac{1}{17}-\frac{1}{20}\)

\(3A=\frac{1}{2}-\frac{1}{20}\)

\(A=\left(\frac{1}{2}-\frac{1}{20}\right)\div3=\frac{9}{20}\div3=\frac{9}{20.3}=\frac{3}{20}\)

Vậy ................

\(B=\frac{3}{4}\cdot\frac{8}{9}\cdot\frac{15}{16}\cdot....\cdot\frac{9999}{10000}\)

\(B=\frac{1.3}{2.2}\cdot\frac{2.4}{3.3}\cdot\frac{3.5}{4.4}\cdot...\cdot\frac{99.101}{100.100}\)

\(B=\frac{\left(1\cdot2\cdot3\cdot...\cdot99\right).\left(3\cdot4\cdot5\cdot...\cdot101\right)}{\left(2\cdot3\cdot4\cdot...\cdot100\right).\left(2\cdot3\cdot4\cdot...\cdot100\right)}\)

\(B=\frac{1\cdot2\cdot3\cdot..\cdot99}{2\cdot3\cdot4\cdot..\cdot100}\cdot\frac{3\cdot4\cdot5\cdot...\cdot101}{2\cdot3\cdot4\cdot...\cdot100}\)

\(B=\frac{1}{100}\cdot\frac{101}{2}=\frac{101}{200}\)

vậy......

A=1/2.5+1/5.8+1/8.11+1/11.14+1/14.17+1/17.20

A=1/3.(3/2.5+3/5.8+3/8.11+3/11.14+3/14.17+3/17.20)

A=1/3.(1/2-1/20)

=3/20

B=1.3/2.2+2.4/3.3+3.5/4.4+...+99.101/100.100

B=(1.2.3...99).(3.4.5...101)/(2.3.4...100).(2.3.4...100)

B=\(\frac{1.2....99}{2.3...100}\).\(\frac{3.4...101}{2.3...100}\)

B=1/100.101/2=101/200