Tìm x
(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
Tìm x:
x+(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
x *6+ ( 1 + 2 + 3 + 4 + 5 ) = 45
x*6=45-15=30
x=30:6=5
ủng hộ nha các bạn
=> ( x + x + x + x + x + x ) + ( 1 + 2 + 3 + 4 + 5 ) = 45
=> 6x + 15 = 45
=> 6x = 45 - 15 = 30
=> x = 30 : 5 = 5
Vậy x = 5
Tìm x biết (x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
x+1 + x+2 + x+3 + x +4 + x+5 = 45
x + x + x + x + x = 45 -1 -2 -3 -4 -5
5x = 30
x =6
tìm x: (x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
(x + x + x + x + x) + ( 1 + 2 + 3 + 4 + 5) = 45
\(x\times5\)+ 15 = 45
\(x\times5\) = 45 - 15
\(x\times5\) = 30
x = 30 : 5
x = 6.
Hok tốt !
Bài 2:Tìm x,biết:
1, 4/5-x=1/3
2, 2/3+5/3x=5/7
3, -12/13x+5=5 1/13
4, x:(-2 1/4)+1,5=-3/4
5,GTTĐ của x -3/4 - 1/4=0
6, 6-GTTĐ của 1/2-x = 2/3
7, (x-1)2=4/9
1) x = 4/5 - 1/3
x = 7/15
2) 5/3.x=1/21
x=1/35
3) -12/13.x = 1/13
x=-1/12
7) th1: x-1=2/3
x = 5/3
Th2: x - 1 = -2/3
x=1/3
tìm y biết 2/3 x 4/y x 1/5=4/45
3/4 x y/5=5/2 x 9/10
\(\frac{2}{3}x\frac{4}{y}=\frac{4}{45}:\frac{1}{5}\)\(=\frac{4}{15}\)
\(\frac{4}{y}=\frac{4}{15}:\frac{2}{3}\)\(=\frac{2}{5}\)
y=4:\(\frac{2}{5}\) y=10
\(\frac{3}{4}x\frac{y}{5}=\frac{15}{4}\)
\(\frac{y}{5}=\frac{15}{4}:\frac{3}{4}=5\)
y=5x5=25
tìm x biết:
1) 14- (5-8+3-x) = |-7+10|
2) -19 - ?(3+x-5) = |4-15+2|
3) 45- (x+45-3) = |-7+3|
Tìm x
(3x-3)(.5-21x)+(7x +4)(6x-5)=45
(x+1)(x+2)(x+5)-x^2(x+8)=27
Tìm X: ( X + 1) + ( X + 2) + (X+ 3) + ( X + 4 ) + ( X + 5) = 45
(x+1)+(x+2)+(x+3)+(x+4)+(x+5)=45
<=> (x+x+x+x+x)+(1+2+3+4+5)=45
<=> 5x+15=45
<=> 5x=30
<=> x=6
Tìm X: ( X + 1) + ( X + 2) + (X+ 3) + ( X + 4 ) + ( X + 5) = 45
(x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) = 45
x + 1 + x + 2 + x + 3 + x + 4 + x + 5 = 45
(x + x + x + x + x) + (1 + 2 + 3 + 4 + 5) = 45
5x + 15 = 45
5x = 45 - 15
5x = 30
x = 6