Ta có : 

\(x.8=6.5\)

=> \(x=6.5:8\)

     \(x=30:8=\frac{15}{4}\)

Có cái j sai sai thì phải bạn ak !!!

Bạn xem lại đề nhé.

Ta có: \(\frac{4}{7}< \frac{x}{10}< \frac{5}{7}\)

Ta lại có: \(\frac{8}{14}< \frac{x}{14}< \frac{x}{10}< \frac{10}{14}\)

\(\Rightarrow\frac{8}{14}< \frac{9}{14}< \frac{9}{10}< \frac{10}{14}\)

Vậy giá trị của x là 9.

Ta có:

\(\frac{4}{7}< \frac{x}{10}< \frac{5}{7}\)

\(\Rightarrow\frac{40}{70}< \frac{7x}{70}< \frac{50}{70}\)

\(\Rightarrow40< 7x< 50\)

Vì \(7x⋮7\)

\(\Rightarrow7x\in\left\{42;49\right\}\)

\(\Rightarrow x\in\left\{6;7\right\}\)

Vậy: x = 6 hoặc x = 7

 x = 6 hoặc 7

\(\frac{x}{8}< \frac{3}{5}< \frac{x+1}{8}\Rightarrow\frac{5x}{40}< \frac{24}{40}< \frac{5x+5}{40}\Rightarrow5x< 24< 5x+5\)

+)5x+1=24=>5x=23=>x=23/5 (loại)

+)5x+2=24=>5x=22=>x=22/5 (loại)

+)5x+3=24=>5x=21=>x=21/5 (loại)

+)5x+4=24=>5x=20=>x=4 (nhận)

Vậy x=4

Ta có : \(5\frac{8}{17}\div X+\left(-\frac{1}{17}\right)\div X+3\frac{1}{17}\div17\frac{1}{3}=\frac{4}{17}\)

Nên:    \(\left(5\frac{8}{17}+\left(-\frac{1}{17}\right)\right)\div X+\frac{52}{17}\div\frac{52}{3}=\frac{4}{17}\)

           \(5\frac{7}{17}\div X+\frac{52}{17}\times\frac{3}{52}=\frac{4}{17}\)

           \(\frac{92}{17}\div X+\frac{3}{17}=\frac{4}{17}\)

           \(\frac{92}{17}\div X=\frac{4}{17}-\frac{3}{17}\)

           \(\frac{92}{17}\div X=\frac{1}{17}\)

           \(X=\frac{92}{17}\div\frac{1}{17}\)

            \(X=92\)

Vậy \(X=92\)

\(5\frac{8}{17}:x+\left(-\frac{1}{17}\right):x=\frac{52}{51}\)

\(\left(5\frac{8}{17}+-\frac{1}{17}\right):x=\frac{52}{51}\)

\(\frac{92}{17}:x=\frac{52}{51}\)

\(X=\frac{92}{17}:\frac{52}{51}=\frac{69}{13}\)

\(\frac{93}{17}:x+\left(-\frac{1}{17}\right):x+\frac{52}{17}:\frac{52}{3}=\frac{4}{7}\)

\(\frac{93}{17x}+\frac{-1}{17x}+\frac{3}{17}=\frac{4}{7}\)

\(\frac{93+\left(-1\right)}{17x}=\frac{47}{119}\)

\(\frac{92}{17x}=\frac{47}{119}\Rightarrow92\times119=47\left(17x\right)\)

=>10948=799x

=>x=\(\frac{644}{47}\)

Bài 1:

\(A=\left(\frac{-5}{11}+\frac{7}{22}-\frac{4}{33}-\frac{5}{44}\right):\left(38\frac{1}{122}-39\frac{7}{22}\right)\)

\(=\frac{-49}{132}:\left(-\frac{879}{671}\right)=\frac{2989}{105408}\)

Bài 2:

\(\frac{4}{5}-\left(\frac{-1}{8}\right)=\frac{7}{8}-x\)

<=>  \(\frac{7}{8}-x=\frac{27}{40}\)

<=>  \(x=\frac{7}{8}-\frac{27}{40}=\frac{1}{5}\)

Vậy...

bài 2 mình tính sai, sửa

.......

<=>  \(\frac{7}{8}-x=\frac{37}{40}\)

<=>  \(x=\frac{7}{8}-\frac{37}{40}=\frac{-1}{20}\)

Vậy....

\(\frac{4}{5}-\frac{-1}{8}=\frac{7}{8}-x\)

\(\Leftrightarrow x=\frac{7}{8}-\frac{4}{5}-\frac{1}{8}\)

\(\Leftrightarrow x=\frac{-1}{20}\)