\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}=\frac{2+8y}{6\left(3+x\right)}=\frac{1+4y}{3\left(3+x\right)}\)

\(\Rightarrow3\left(3+x\right)=24\)\(\Rightarrow3+x=8\)\(\Rightarrow x=5\)

Vậy \(x=5\)

Ta có: \(\frac{1+2y}{18}=\frac{1+4y}{24}\)

\(\Leftrightarrow24\left(1+2y\right)=18\left(1+4y\right)\)

\(\Leftrightarrow24+48y=18+72y\)

\(\Leftrightarrow24y-6=0\Leftrightarrow y=\frac{1}{4}\)

\(\Rightarrow\frac{1+2y}{18}=\frac{1+6y}{6x}\Leftrightarrow\frac{1+\frac{1}{2}}{18}=\frac{1+\frac{3}{2}}{6x}\)

\(\Leftrightarrow x=5\)

Vậy x = 5 và \(y=\frac{1}{4}\)

\(\Rightarrow\)\(\frac{1+2y+1+4y+1+6y}{18+24+6x}\)=\(\frac{\left(1+1+1\right)+2y+4y+6y}{6\left(3+4+x\right)}=\frac{y\left(2+4+6\right)+3}{6\left(3+4+x\right)}=\frac{3+y.12}{6\left(7+x\right)}\)

=\(\frac{3\left(1+4y\right)}{3.2\left(7+x\right)}=\frac{1+4y}{14+2x}\)

\(\Rightarrow\)\(\frac{1}{14}=\frac{2y}{x}\Rightarrow x=14.2y=28y\)

\(\frac{x}{y}=28\)

Ta có: \(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}=\frac{2\left(1+4y\right)}{6\left(x+3\right)}=\frac{1+4y}{3x+9}\)

\(=>\frac{1+4y}{24}=\frac{1+4y}{3x+9}\)\(=>3x+9=24\)

<=>3x=15

<=>x=5

Vậy x có giá trị bằng 5

Chúc bạn học tốt!

Áp dụng tính chất của dãy tỉ số bằng nhau, ta có:

\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}\)

                                                       \(=\frac{2\left(1+4y\right)}{2\left(3x+9\right)}=\frac{1+4y}{3x+9}\)

\(\Rightarrow\frac{1+4y}{24}=\frac{1+4y}{3x+9}\)

\(\Rightarrow3x+9=24\)

\(\Rightarrow x+3=24:3=8\)

\(\Rightarrow x=5\)

\(\frac{1+2y}{18}=\frac{2+4y}{36}=\frac{1+4y}{24}=\frac{2+4y-\left(1+4y\right)}{36-24}=\frac{1}{12}\)

\(\Rightarrow\frac{1+4y}{24}=\frac{1}{12}\Rightarrow4y+1=2\Rightarrow y=\frac{1}{4}\)

\(\Rightarrow\frac{1+6y}{6x}=\frac{1}{12}\Rightarrow x=2\cdot\left(1+6y\right)=2+12y=2+12\cdot\frac{1}{4}=5\)

Vậy x = 5.

Áp dụng tính chất dãy tỉ số bằng nhau:

\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{1+6y-\left(1+2y\right)-\left(1+4y\right)}{6x-18-14}=-\frac{1}{6x-42}\)\(=\frac{1+4y-2\left(1+2y\right)}{24-2.18}=\frac{1}{12}\)

\(\Rightarrow-\frac{1}{6x-42}=\frac{1}{12}\Rightarrow6x-42=-12\Rightarrow6x=30\)

\(\Rightarrow x=5\)

clink vào câu hỏi tương tự      

\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+2y+1+4y}{18+24}=\frac{6y+2}{42}=\frac{1+6y}{6x}\) ghi sai de

Giúp mình giải lẹ lên nha mina mình sẽ kb cho

bạn nhân chéo 2 phân số đầu là tìm được y

\(y=\frac{1+2y}{18}=\frac{1+2y+1+6y}{18+6x}=\frac{2+8y}{18+6x}\Rightarrow\frac{1+4y}{24}=\frac{2+8y}{18+6x}\)

         \(\Rightarrow\frac{1+4y}{2\left(1+4y\right)}=\frac{24}{18+6x}=\frac{1}{2}\)

\(\Rightarrow18+6x=24.2\)

\(\Rightarrow6\left(3+x\right)=6.4.2\)

\(\Rightarrow3+x=8\Rightarrow x=5\)

y thì bạn tự tìm nhé! Dễ lắm!

tik nhé