Tìm x ( Giải ra nhoa ) ♔ ♔ ♔
a) \(x\) x 2015 = 2015 x 2016
b( \(x\) x 0,25 +2013 ) x 2014 = ( 53 + 2013 ) x 2014
c) 71 + 65 x 4 = \(\frac{x+140}{x}\)+ 260
c ) 71 + 260 = \(\frac{x}{x}\)+\(\frac{140}{x}\)+260
331 = 1 + \(\frac{140}{x}\)+260
331 = \(\frac{140}{x}\)+261
331 = 140 : x + 261
140 : x = 331 - 261
140 : x = 70
x = 140 : 70
x = 2
1, TÌM SỐ CÓ 2 CHỮ SỐ , BIẾT RẰNG SỐ ĐÓ GẤP 8 LẦN TỔNG CÁC CHỮ SỐ CỦA NÓ ?
2, Tìm X, biết :
A, ( X . 0,25 + 2014 ) . 2015 = ( 53 + 2014 ) . 2016
B, 71 + 65 . 4 = X + 140 TRÊN X + 260
Tìm x:
a) (X x 0,25 + 1999) x 2000 = ( 53 + 1999 ) x 2000
b) 71 + 65 x 4 = \(\dfrac{x+140}{x}\) + 260
\(a.\left(x\times0,25+1999\right)\times2000=2052\times2000\\ \left(x\times0,25+1999\right)\times2000=4104000\\ x\times0,25+1999=4104000:2000\\ x\times0,25+1999=2052\\ x\times0,25=2052-1999\\ x\times0,25=53\\ x=53:0,25\\ x=212\)
tìm giá trị nhỏ nhất của biểu thức:
D=/x-2013/+/x-2014/+/x-2015/+/x-2016/
(/x-2013/ là giá trị tuyệt đối của x-2013 nhé ; /x-2014/,/x-2015/,/x-2016/ cũng vậy)
a, x+1/2013+x+1/2014+x+1/2015=x+1/2016+x+1/2017
b,x-1/2013+x-2/2014+x-3/2015=x-4/2016-2
Quản lí giúp hộ e vs !!!
Tìm x:
\(\frac{x-1}{2016}+\frac{x-2}{2015}-\frac{x-3}{2014}=\frac{x-4}{2013}\)
\(\frac{x-1}{2016}+\frac{x-2}{2015}-\frac{x-3}{2014}=\frac{x-4}{2013}\)
\(\left(\frac{x-1}{2016}-1\right)+\left(\frac{x-2}{2015}-1\right)-\left(\frac{x-3}{2014}-1\right)-\left(\frac{x-4}{2013}-1\right)=0\)
\(\frac{x-2017}{2016}+\frac{x-2017}{2015}-\frac{x-2017}{2014}-\frac{x-2017}{2013}=0\)
\(\left(x-2017\right)\left(\frac{1}{2016}+\frac{1}{2015}-\frac{1}{2014}-\frac{1}{2013}\right)=0\)
\(x-2017=0\left(\frac{1}{2016}+\frac{1}{2015}-\frac{1}{2014}-\frac{1}{2013}\ne0\right)\)
\(x=2017\)
x-1/2016+x-2/2015-x-3/2014=x-4/2013
<=> x-1/2016+x-2/2015-x-3/2014-x-4/2013=0
trừ mỗi phân số thêm 1 ta được
x-2017/2016+x-2017/2015-x-2017/2014-x-2017/2013=0
<=>(x-2017).(1/2016+1/2015+1/2014+1/2013)=0
(1/2016+1/2015+1/2014+1/2013) khác 0
=>x-2017=0
<=>x=2017
vậy x = 2017
Bài 1:tìm x:
a) x+5*2-(32+16*3*6-15)= 0
b) (x*0,25+1999)*2000= (53+1999)*2000
c)x*2016=x:2016
d) (x+2)+(x+3)+.....................+ (x+100)= 5750-(x-1)
e) x+x:1/3:2/9+x:2/7= 252
g) 71+65*4=\(\frac{x+140}{x}\) + 260
h) x:0,1: 0,2: 0,3 :0,4 : 0,5 : 0,6 = 100000
tìm x : \(\frac{x+2}{2015}+\frac{x+1}{2016}=\frac{x+3}{2014}+\frac{x+4}{2013}\)
\(\frac{x+2}{2015}+\frac{x+1}{2016}=\frac{x+3}{2014}+\frac{x+4}{2013}\)
=> \(\left(\frac{x+2}{2015}+1\right)+\left(\frac{x+1}{2016}+1\right)=\left(\frac{x+3}{2014}+1\right)+\left(\frac{x+4}{2013}+1\right)\)
=> \(\frac{x+2017}{2015}+\frac{x+2017}{2016}=\frac{x+2017}{2014}+\frac{x+2017}{2013}\)
=> (x + 2017)(1/2015 + 1/2016 - 1/2014 - 1/2013) = 0
=> x + 2017 = 0
=> x = -2017
\(\frac{x+2}{2015}+\frac{x+1}{2016}=\frac{x+3}{2014}+\frac{x+4}{2013}\)
\(\Leftrightarrow\frac{x+2}{2015}+1+\frac{x+1}{2016}+1=\frac{x+3}{2014}+1+\frac{x+4}{2013}+1\)
\(\Leftrightarrow\frac{x+2017}{2015}+\frac{x+2017}{2016}=\frac{x+2017}{2014}+\frac{x+2017}{2013}\)
\(\Leftrightarrow\left(x+2017\right)\left(\frac{1}{2015}+\frac{1}{2016}-\frac{1}{2014}-\frac{1}{2013}\right)=0\)
Dễ thấy cái ngoặc to < 0
=> x=-2017
tìm x
A) (\(\chi\)x 0,25 + 1999) x 2000= (53+ 1999) x 2000
b) 71 + 65 x 4=\(\frac{\chi+140}{\chi}\)+ 260.
Ai biết làm thì giúp mik nhé
a)(x.0,25+1999)x2000=(53+1999)x2000
(x.0,25+1999)=53+1999
x.0,25=53
x=53x4
x=210
a)(x.0,25+1999)x2000=(53+1999)x2000
(x.0,25+1999)=53+1999
x.0,25=53
x=53x4
x=210
k mik đi
(x .0,25 + 1999) . 2000 = (53+1999) .2000
(x . 0,25 +1999 )= (53 +1999)
x. 0,25= 53
x = 53 :0, 25
x = 212
dau cham la dau nhan
