Tìm x :

a) \(\frac{3}{2}x-\frac{2}{3}=\frac{2}{3}:\frac{3}{2}\)

b) \(\left(\frac{9}{11}-x\right):\left(\frac{-10}{11}\right)=1-\frac{4}{5}\)

c) \(\frac{-11}{12}.x+\frac{3}{4}=\frac{-1}{6}\)

d) \(\frac{-5}{4}-\left(1\frac{1}{2}+x\right)=4,5\)

đ) \(\left(\frac{3}{4}-x:\frac{2}{15}\right).\frac{1}{5}=-2,6\)

e) \(3-\left(\frac{1}{6}-x\right).\frac{2}{3}=\frac{2}{3}\)

f) \(\left(1-2x\right).\frac{4}{5}=\left(-2\right)^3\)

g) \(\frac{1}{6}-\left|\frac{1}{2}.x-\frac{1}{3}\right|=\frac{1}{8}\)

1. tinh` giá trị biểu thức ( tính nhanh nếu có thế )

\(a)\frac{-6}{11}.\frac{5}{13}+\frac{-6}{11}.\frac{8}{13}-\left(\frac{-2}{5}\right)^0\) \(b)\left(2\frac{2}{3}+3\frac{1}{2}\right);\left(4\frac{3}{4}-2\frac{1}{6}\right)+\frac{19}{31}\) \(c)2,4:\left(-2\right)^3+\left(3-\frac{9}{11}\right).1\frac{3}{8}\)

\(d)\left(-\frac{3}{4}\right)^2:\frac{-3}{8}+\frac{1}{2}-\frac{3}{4}-\left(\frac{-78}{57}\right)^0\)

2. tìm x

\(a)x+\frac{-1}{5}=\left(-\frac{3}{4^{ }}\right)^2\) \(b)\left|\frac{5}{2}x+\frac{2}{3}\right|-\frac{1}{4}=0\) \(c)\frac{2}{3}x-\frac{1}{2}=\frac{5}{12}+\frac{1}{2}x\) \(d)\left(x-\frac{1}{4}\right)^4=\frac{1}{81}\)

\(e)4x+3\frac{1}{4}=x-\frac{1}{4}\) \(g)\left(x-\frac{1}{3}\right)^3=\frac{1}{27}\)

Bài 1 thực hiện phép tính 

a)\(\frac{45}{19}-\left(\frac{1}{2}+\left(\frac{1}{3}+\left(\frac{1}{4}\right)^{-1}\right)^{-1}\right)^{-1}.\)

b) \(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^{10}.6^{19}-7.2^{29}.27^6}.\)

Bài 2. tìm x, biết:

 a) 2(x-1) - 3(2x+2) - 4(2x+3) =16

 b) \(3\frac{1}{2}:\left|2x-1\right|=\frac{21}{22}\)

 c)  |x²+|x-1|| = x²+2

Bài 3. Chứng minh rằng số có dạng abcabc luôn chia hết cho 11

Bài 4.tính:

a)   A = \(\left(\frac{0,4-\frac{2}{9}+\frac{2}{11}}{1,4-\frac{7}{9}+\frac{7}{11}}-\frac{\frac{1}{3}-0,25+\frac{1}{5}}{1\frac{1}{6}-0,875+0,7}\right):\frac{2012}{2013}\)

b)   B =\(4.\left(-\frac{1}{2}\right)^2-2.\left(-\frac{1}{2}\right)^2+3.\left(-\frac{1}{2}\right)+1\)

c)   C =\(\frac{1}{2}:\left(-1\frac{1}{2}\right):1\frac{1}{3}:\left(-1\frac{1}{4}\right):1\frac{1}{5}:\left(-1\frac{1}{6}\right):...:\left(-1\frac{1}{100}\right)\)

d)   D =\(\frac{4^6.9^5+6^9.120}{-8^4.3^{12}+6^{11}}\)

\(\frac{4}{9}:\frac{-1}{7}+6\frac{5}{9}.\frac{2}{3}\)

\(\left(\frac{-1}{3}\right)^4.\frac{4}{11}+\frac{7}{11}.\left(\frac{-1}{3}\right)^2\)

\(\left(\frac{-1}{7}\right)^0-2\frac{4}{9}:\left(\frac{2}{3}\right)^2\)

\(\left(\frac{1}{3}-\frac{5}{6}\right)^2+\frac{5}{6}:2\)

Tìm x

\(\left(\frac{3}{5}-\frac{1}{2}x\right)^2+8=12\)

\(\frac{7}{12}-\left|\frac{1}{3}-\frac{1}{2}x\right|=\frac{1}{3}\)

\(\frac{13}{12}-\frac{1}{3}.\left|\frac{1}{5}-\frac{1}{3}x\right|=\frac{1}{2}\)

Nhanh hộ mình nha

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