CMR so thuc a,b,c thi a^2+b^2+c^2+ab+bc+ca lon hon hoac bang 0
CMR so thuc a,b,c thi a^2+b^2+c^2+ab+bc+ca lon hon hoac bang 0
cho cac so thuc duong thoa man a+b+c=3.cmr:
(a2+ab2/b2+a+b)+(b2+bc2/c2+b+c)+(c2+ca2/a2+c+a) lon hon hoac bang 2
cmr : a^2/b^2 +b^2/c^2+c^2/a^2 luon luon lon hon hoac bang c/b+ b/a+ a/c voi a,b,c lon hon 0
cho ba so duong 0 nho hon hoac bang a nho hon hoac hoa bang b nho hon hoac bang c nho hon hoac bang 1 . chung minh a/bc+1+b/ac+1+c/ab+1nho hon hoac bang 2
Bai 2: cho a,b,c>0.CMR
\(\frac{a^3}{bc}+\frac{b^3}{ac}+\frac{c^3}{ab}\)lon hon hoac bang a+b+c
c/m voi 3 so thuc tuy y ta co
a2 cong b2 cong 1 lon hon hoac bang ab cong a cong b
Ta có: a2+b2+1≥ab+a+b
<=>2a2+2b2+2≥2ab+2a+2b
<=>(a2−2ab+b2)+(a2−2a+1)+(b2−2b+1)≥0
<=>(a−b)2+(a−1)2+(b−1)2≥0 ( Luôn đúng với V a,b)
Vậy a2+b2+1≥ab+a+b
cau 1 ,cho m,n thuoc n va p la so nguyen to thoa man p/m-1=m+n/p
CMRp^2=n+2
cau 2,cho a,b,c thoa man a+b+c=0 CMRab+bc+ca be hon hoac bang 0
cau 3,bay gio la 4 gio 10 phut hoi sau it nhat bao lau thi hai kim dong ho nam doi dien nhau tren mot duong thang
cau 4,so 2^100 viet trong he thap phan tao thanh 1 so hoi so do co bao nhieu chu so
cau 5,cho a,b,c la so do 3 canh cua mot tam giac vuong voi c la so do canh huyen CMRa^2n+b^2n be hon hoac bang c^2n (n la so tu nhien lon hon 0 )
Cho các số a,b,c thỏa mãn 1 lon hon bang a,b,c .
a,b,c lon hon bang 0 . C/m :
a + b2 + c3 - ab - bc - ca , nhỏ hơn bằng 1
Bai 1 : Viet tap hop A cac so tu nhien lon hon 4 va ko vuot qua 7 bang hai cach .
a ) Viet tap hop cac so tu nhien khac 0 va ko vuot qua 12 bang hai cach .
b ) Viet tap hop M cac so tu nhien lon hon hoac bang 11 va ko vuot qua 20 bang hai cach .
c ) Viet tap hop M cac so tu nhien lon hon 9 ,nho hon hoac bang 15 bang 2 cach .
d ) Viet tap hop A cac so tu nhien ko vuot qua 30 bang 2 cach .
e ) Viet tap hop B cac so tu nhien lon hon 5 bang 2 cach .
f ) Viet tap hop C cac so tu nhien lon hon hoac bang 18 va ko vuot qua 100 bang 2 cach .
Ai lam nhanh minh se tick cho nha ,minh can gap .
Bài 1 : Cách 1 : \(A=\left\{5;6;7\right\}\)
Cách 2 : \(A=\left\{x\in N|4< x\le7\right\}\)
Các ý còn lại bạn làm tương tự :>
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