Câu a sai đề (sửa đề lại rồi làm tương tự câu b

Câu b 

\(\frac{5932+6001\times5931}{5932\times6001-69}=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}=\frac{5932+6001\times5931}{5931\times6001+6001-69}=\frac{5932+6001\times5931}{5932\times6001+5932}=1\)

\(254.399-\frac{145}{254+399.255}=101346-\frac{145}{101999}=1012031170\)

\(5932+6001.\frac{5931}{35597863}=1\)

      \(\frac{254.399-145}{254+399.253}=\frac{\left(253+1\right).399-145}{254+399.253}\)

                                    \(=\frac{253.399+1.399-145}{254+399.253}\)

                                    \(=\frac{253.399+254}{254+399.253}\)

                                    \(=1.\)

\(\frac{5932+6001.5931}{5932.6001-69}=\frac{5932+6001.5931}{\left(5931+1\right).6001-69}\)

                                    \(=\frac{5932+6001.5931}{5931.6001+1.6001-69}\)

                                    \(=\frac{5932+6001.5931}{5931.6001+5932}\)

                                    \(=1.\)

Câu thứ nhất là: 202292,4291.       ;       Câu thứ hai là: 36011793,2.

a, \(\dfrac{254\times399-145}{254+399\times253}\)

= \(\dfrac{\left(253+1\right)\times399-`45}{254+399\times253}\)

= \(\dfrac{253\times399+399-145}{253\times399+254}\)

= \(\dfrac{253\times399+254}{253\times399+254}\)

= 1

b, \(\dfrac{5932+6001\times5931}{5932\times6001-69}\)

= \(\dfrac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)

= \(\dfrac{5932+6001\times5931}{5931\times6001+6001-69}\)

= \(\dfrac{5932+6001\times5931}{5931\times6001+5932}\)

= 1

\(\frac{5932+6001x5931}{5932x6001-69}=\frac{6001x5931+5932}{5931x6001+6001-69}=\frac{6001x5931+5932}{6001x5931+5932}=1\)

a) \(\frac{254.399-145}{254+399.253}\)

\(=\frac{253.399+399-145}{254+399.253}\)

\(=\frac{253.399+254}{254+399.253}\)

\(=1\)

b) tự làm

A)\(\frac{254\cdot399-145}{254+399\cdot253}\)

\(=\frac{\left(253+1\right)\cdot399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+1\cdot399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+399-145}{254+399\cdot253}\)

\(=\frac{253\cdot399+254}{254+399\cdot253}\Rightarrow=1\)

B) X x X - 1/6 = 5/18

x² = 5/18 + 1/6

x² = 8/18 = 4/9

x= \(\sqrt{\frac{4}{9}}\) \(=\frac{2}{3}\)

tim x

5/18

tính nhanh

b, 1

còn phần a thì chịu

đúng không

\(1-\left(5\frac{4}{9}+x-7\frac{7}{18}\right):15\frac{3}{4}=0\)

\(\Rightarrow\left(\frac{49}{9}+x-\frac{133}{18}\right):\frac{63}{4}=1-0\)

\(\Rightarrow\left(\frac{49}{9}+x-\frac{133}{18}\right):\frac{63}{4}=1\)

\(\Rightarrow\frac{49}{9}+x-\frac{133}{18}=1.\frac{63}{4}\)

\(\Rightarrow\frac{49}{9}+x-\frac{133}{18}=\frac{63}{4}\)

\(\Rightarrow\frac{49}{9}+x=\frac{63}{4}+\frac{133}{18}\)

\(\Rightarrow\frac{49}{9}+x=\frac{833}{36}\)

\(\Rightarrow x=\frac{833}{36}-\frac{49}{9}=\frac{637}{36}\)

\(\frac{5932+6001x5931}{5932x6001-69}\)

\(=\frac{6001+6001x5931-69}{5932x6001-69}\)

\(=\frac{6001x\left(1+5931\right)-69}{5932x6001-69}\)

\(=\frac{6001x5932-69}{5932x6001-69}\)

\(=1\)

\(\frac{5932+6001\times5931}{5932\times6001-69}\)

\(=\frac{5932+6001\times5931}{\left(5931+1\right)\times6001-69}\)

\(=\frac{5932+6001\times5931}{5931\times6001+6001-69}\)

\(=\frac{5932+6001\times5931}{5931\times6001+5932}\)

\(=1\)

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