Tim x:
118,24-( x÷ 5+ x ×3)=27,12×2
Viet ro loi giai nhe!
118,24 - (X : 5 + X x 3) = 27,12 x 2
118,24-(x/5+x*3)=27,12*2
118,24-(x/5+x*3)=27,12*2
Tìm X:
118,24-(X:5 +x nhân 3) =27,12 nhân 2
118,24 - (x:5+x.3)= 54,24
x:5 + x.3 = 118,24 - 54,24 = 64
1/5 x + 15/5 x = 64
16/5 x = 64
x = 64 : 16/5 = 20
118,24 - ( x : 5 - x x 3 ) = 27,12 x 2
118,24 - ( x : 5 - x x 3 ) = 54,24
x : 5 - x x 3 = 118,24 - 54,24
x : 5 - x x 3 = 64
1/5x + 15/5x = 64
16/5x = 64
x = 64 : 16/5 = 20 = > x = 20
tìm x
118,24 - ( x : 5 + x . 3 ) = 27,12 . 2
1,Tìm x
118,24 - ( x : 5 + x . 3 ) = 27,12 . 2
\(118,24-\left(x:5+x.3\right)=27,12.2\)
\(\Leftrightarrow118,24-\left(x:5+x.3\right)=54,24\)
\(\Leftrightarrow x:5+x.3=118,24-54,24\)
\(\Leftrightarrow x.\frac{1}{5}+x.3=64\)
\(\Leftrightarrow x.\left(\frac{1}{5}+3\right)=64\)
\(\Leftrightarrow x.\frac{16}{5}=64\)
\(\Leftrightarrow x=64:\frac{16}{5}\)
\(\Leftrightarrow x=20\)
Tìm x, biết:
118,24 - ( x : 5 + x nhân 3 ) = 27,12 x 2\
Mình sửa từ bài vừa nãy mình ghi sai!
Sorry các bạn!
118,24 - ( X : 5 + X x 3 ) = 27.12 x 2
=> X : 5 + X x 3 = 118,24 - 54,24
=> X x 1/5 + X x 3 = 64
=> X x ( 1 / 5 + 3 ) = 64
=> X x 16/5 = 64
=> X = 20
vậy X = 20
118,24 - ( X : 5 + X x 3 ) = 27,12 x 2
118,24 - ( x : 5 + X x 3 ) = 54,24
X : 5 + X x 3 = 118,24 - 54,24
X : 5 + X x 3 = 64
X x 1/5 + X x 3 = 64
X x ( 1/5 + 3 ) = 64
X x 3,2 = 64
X = 64 : 3,2
X = 20
~Hok tốt~
K nhoa ~~
Bai 1: tim x€N biet:
A,2x+1-2x=32
Bai2:
A,tap hop B={x€N*/x_<5} co phai la con cua tap hop A khong ? Vi sao ?
Ghi ro loi giai ra nhe!!!!
Bài 1:
a) 2x + 1 - 2x = 32
2x + 1 - 2x = 25
=> x + 1 - x = 5
=> x = 5
a) 2x+1 - 2x = 32
2x . 2 - 2x . 1 = 32
2x . (2 - 1) = 32
2x . 1 = 32
2x = 32 : 1
2x = 32
2x = 25
Suy ra : x = 5
20 x 25 x 7 x 8
____________
75 x 8 x 12 x 14
cho minh xin loi giai chi tiet va ro rang nhe, minh se tick
\(\dfrac{20\times25\times7\times8}{75\times8\times12\times14}\)
= \(\dfrac{4\times5\times25\times7\times8}{3\times25\times8\times3\times4\times2\times7}\)
= \(\dfrac{25\times7\times8\times4\times5}{25\times7\times8\times4\times2\times3\times3}\)
= \(\dfrac{25\times7\times8\times4}{25\times7\times8\times4}\) x \(\dfrac{5}{2\times3\times3}\)
= 1 x \(\dfrac{5}{18}\)
= \(\dfrac{5}{18}\)
\(=\dfrac{5.4.5.5.7.8}{5.3.5.8.7.4}\)
Triệt tiêu những phần giống nhau của cả tử và mẫu ta có:
\(=\dfrac{5}{3}\)