ta co (2x-1)(3x+1)+(3x+4)(3-2x)=5

     (=)6x²-3x+2x-1+6x-6x²+12-8x=5

     (=)-4x+11=5

     (=)-4x=-6

     (=)x=3/2

(2x-1)(3x+1)+(3x-4)(3-2x)=5

<=> 6x²+2x-3x-1+9x-6x²-12+8x=5

<=> 16x-13=5

<=> 16x = 18

<=> x=9/8

3/4x + 5-(2/3x-4)-(1/6+1)=(1/3x+4)-(1/3x-3)

=3/4x+5-2/3x-4-1/6x+1=1/3x+4-1/3x-3

=-1/12=7

x=84

Đ/S...

\(\left(\dfrac{3x}{4}+5\right)-\left(\dfrac{2x}{3}-4\right)-\left(\dfrac{x}{6}+1\right)=\left(\dfrac{1}{3}+4\right)-\left(\dfrac{1}{3}x-3\right)\)

\(\Leftrightarrow\dfrac{3x}{4}-\dfrac{2x}{3}-\dfrac{x}{6}+5+4-1=\dfrac{13}{3}-\dfrac{1}{3}x+9\)

\(\Leftrightarrow\dfrac{9x-8x-2x}{12}+8=\dfrac{13-x}{3}+\dfrac{27}{3}\)

\(\Leftrightarrow\dfrac{-x}{12}+\dfrac{96}{12}=\dfrac{40-x}{3}\Leftrightarrow\dfrac{96-x}{12}=\dfrac{160-4x}{12}\)

\(\Rightarrow96-160=-4x+x\Leftrightarrow-64=-3x\Leftrightarrow x=\dfrac{64}{3}\)

Áp dung... ta có

3x-2y/5=3x-1/4=(3x-2y+3x-1)/4+5=2y-1/9

=>2y-1/9=2y+5/7

=>(2y-1).7=(2y+5).9

=>14y-7=18y+45

=>y=-13

Thay vào,tìm x

Ko chac dung ko

\(\frac{1}{4}+\frac{1}{3}:3x=-5\)

\(\Rightarrow\frac{1}{9x}=\frac{-21}{4}\)

\(\Rightarrow-189x=4\)

\(\Rightarrow x=-\frac{4}{189}\)

1/4 + 1/3 :3x= -5

=> 1/3 : 3x= (-5) - 1/4 = -21/4

=> 3x = -4/63

=> x = -4/189

nhớ cho mk nha

\(\frac{1}{4}+\frac{1}{3}:3x=-5\)

\(=\frac{1}{4}+\frac{1}{\frac{3}{3}}x=-5\)

\(=\frac{1}{4}+\frac{1}{9}x=-5\)

\(=\frac{1}{9}x=\left(-5\right)-\frac{1}{4}\)

\(=\frac{1}{9}x=-\frac{21}{4}\)

\(=x=9.\left(-\frac{21}{4}\right)\)

\(=x=-\frac{189}{4}\)

\(\Rightarrow x=-\frac{189}{4}\)