75%xX+3/4xX+X=30
tìm X
TÌM X:75%xX+3/4xX+X=30
\(75\%x+\frac{3}{4}x+x=30\)
\(\Leftrightarrow\left(75\%+\frac{3}{4}+1\right)x=30\)
\(\Leftrightarrow\frac{5}{2}x=30\)
\(\Leftrightarrow x=30:\frac{5}{2}\)
\(\Leftrightarrow x=12\)
Tìm X biết : 75%xX+3/4xX+X=30
đổi 75%=3/4.Ta có:
3/4xX+3/4xX+X=30
(3/4+3/4+1)xX=30
5/2 x X=30
X = 30:5/2
X = 12
\(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)
\(\frac{5}{2}\times x=30\)
\(x=30\div\frac{5}{2}\)
\(x=12\)
giá xăng từ 20 000 đồng lên 21 000 đồng 1 lít . hỏi giá xăng tăng bao nhiêu phần trăm?
75%xX+3/4xX+x=30
toán tìm X
0,75x + 0,75x = 30
0,75 . 2x = 30
2x = 40
x = 20
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(x\cdot\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\cdot\frac{5}{2}=30\)
\(x=30\cdot\frac{2}{5}\)
\(x=12\)
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\frac{3}{4}\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}\right)\cdot x+x=30\)
\(\frac{3}{2}\cdot x+x=30\)
\(\frac{3}{2}\cdot x+\frac{1}{1}\cdot x=30\)
\(\left(\frac{3}{2}+\frac{1}{1}\right)\cdot x=30\)
\(\frac{5}{2}\cdot x=30\)
\(x=30\text{ : }\frac{5}{2}\)
\(x=12\)
75%xx+3/4xx+x=30
= 75% x X + 3/4 x X + X = 30
= X x (3/4 + 3/4 + 1) = 30
= X x 10/4 = 30
= X = 30 : 10/4
X = 12
75%xX+3/4xX+X=30
x+0,25= 18/5+43/4
25%xX+3/4xX+x=35
b)25%xX+3/4xX+X=35
ai làm được cho tích
=0,25 x X +0,75 x X +X x1=35
=X x (0,25 +0,75 +1)=35
=X x 2=35
X = 35:2
X = 17,5
5x(x+3)=5x^2-30
tìm nghiệm
5x(x+3)=5x^2-30
tìm nghiệm của pt
\(5x^2+15x=5x^2-30\)
\(5x^2+15x-5x^2=-30\)
\(15x=-30\)
\(x=-2\)