đặt A=.....

=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{x-1}-\frac{1}{x}+\frac{1}{x}-\frac{1}{x+1}\)=\(\frac{2016}{2017}\)

=\(1-\frac{1}{x+1}=\frac{2016}{2017}\)

=\(\frac{x}{x+1}=\frac{2016}{2017}\)

=>x=2016

vậy..............

1/1-1/2+1.2-1/3+1/3-1/4+..+1/x-1/x+1=2018/2019

1-1/x+1=2018/2019

1-2018/2019=1/x+1

1/2019=1/x+1

=>x+1=2019

=>x=2018

vậy...

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x\left(x+1\right)}=\frac{2018}{2019}.\)

\(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{2018}{2019}.\)

\(\frac{1}{1}-\frac{1}{x+1}=\frac{2018}{2019}\)

\(\frac{1}{1}-\frac{2018}{2019}=\frac{1}{x+1}\)

\(\frac{1}{2019}=\frac{1}{x+1}\)

=> \(2019=x+1\)

\(x+1=2019\)

\(x=2019-1\)

\(x=2018\)

Vậy x = 2018

Do mỗi số hạng ở vế trái nằm trong dấu giá trị tuyệt đối mà vế phải 100 là số dương nên x cũng phải dương.

Do x dương và trong mỗi dấu giá trị tuyệt đối đều dương nên ta lập được kết quả sau:

x+1/1.2+x+1/2.3+1/3.4+....+x+1/99.100=100x

Dãy trên có 99 số x nên:

99x+(1-1/2+1/2-1/3+1/3-1/4+....+1/99-1/100)=100x

1-1/100=x

x=99/100

Vậy x=99/100

Chúc em học tốt^^

123

=>\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{10}{11}\)

=>\(1-\frac{1}{x+1}=\frac{10}{11}\)

=>\(\frac{1}{x+1}=1-\frac{10}{11}\)

=>\(\frac{1}{x+1}=\frac{1}{11}\)

=>x+1=11

=>x=10

\(\Rightarrow\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{x}-\dfrac{1}{x+1}\)

\(\Rightarrow1-\dfrac{1}{x+1}=\dfrac{2016}{2017}\)

\(\Rightarrow\dfrac{1}{x+1}=1-\dfrac{2016}{2017}\)

\(\Rightarrow\dfrac{1}{x+1}=\dfrac{1}{2017}\)

\(\Rightarrow x+1=2017\)

\(\Rightarrow x=2017-1=2016\)

Vậy x = 2016

\(\dfrac{1}{1.2}\)+\(\dfrac{1}{2.3}\)+\(\dfrac{1}{3.4}\)+\(\dfrac{1}{x\left(x+1\right)}\) = \(\dfrac{2016}{2017}\)

1 - \(\dfrac{1}{2}\) + \(\dfrac{1}{2}\)- \(\dfrac{1}{3}\)+\(\dfrac{1}{3}\)- \(\dfrac{1}{4}\)+ \(\dfrac{1}{x\left(x+1\right)}\)=\(\dfrac{2016}{2017}\)

\(\dfrac{3}{4}\)+\(\dfrac{1}{x\left(x+1\right)}\)=\(\dfrac{2016}{2017}\)

\(\dfrac{1}{x\left(x+1\right)}\)= \(\dfrac{2013}{8068}\)

Bn tự lm tiếp nhé!!! Sorry mk đang vội

A =  1 + 2 + 3 + ... + 2018 (có 2018 số )

   = (2018 + 1) . 2018 : 2 = 2037171

B = 1 + 3 + 5 + ... + 2017(có  1009 số )

   = (2017 + 1) . 1009 : 2 = 1018081

C = 2 + 4 + 6 + ... + 2018 (Có 1009 số )

   = (2018 + 2) x 1009 : 2 = 1019090

D = 72 . 153 + 27.153 + 153

    = (72 + 27 + 1) . 153

    = 100 . 153 = 15300