Tính bằng các thuận tiện nhất: A) 6/7 nhân 16/15 nhân 7/6 nhân 21/32, B) 21/17 nhân 13/14 nhân 56 nhân 3/42, C) 7/4 nhân 11/21+ 11/21 nhân 5/4, D) 23/14 nhân 6/13- 9/14 nhân 6/13 đang cần rất rất rất gấp đó nhanh lên
Giúpppp mìnhh vớiiiiiiiiiiiiiiiiiiiiiiiii nhanhhhhhhhhhhh lênnnnnnnnnnnnnnnnn
a: \(\dfrac{6}{7}\cdot\dfrac{16}{15}\cdot\dfrac{7}{6}\cdot\dfrac{21}{32}=\dfrac{16}{32}\cdot\dfrac{21}{15}=\dfrac{1}{2}\cdot\dfrac{7}{5}=\dfrac{7}{10}\)
b: \(\dfrac{21}{17}\cdot\dfrac{13}{14}\cdot56\cdot\dfrac{3}{42}=\dfrac{21}{14}\cdot\dfrac{13}{17}\cdot\dfrac{1}{14}\cdot56=\dfrac{78}{17}\)
c: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)
1,x/7 x 4/9 x 5 = 3x4x5/7x9
2, tích của 2 phân số tối giản có tử số khác 1 = 6/35 . Tìm tổng của 2 phân số ?
3, tính = cách thuận tiện nhất
a, 6/7 x 16/15 x 7/6 x 21/32 =.....................................
b, 21/17 x 13/14 x 56 x 3/42 =.................................
c, 7/4 x 11/21 + 11/21 x 5/4 =...........................
d, 23/14 x 6/13 - 9/14 x 6/13 =.............................
Tính bằng cách thuận tiện nhất :
a, 6/7 x 8/15 x 7/6 x 15/16
b, 19/20 x 13/21 x 19/20 x 8/21
( Lưu ý cach bai lam day du cach giai ai lam duoc se duoc 1 tick )
a, 6/7*8/15*7/6*15/16
=(6/7*7/6)*(8/15*15/16)
=1*1/2
=1/2
b, Đề bài hơi sai
câu b mình sửa lại là 19/20 x 13/21 + 19/20 x 8/21
b, 19/20*13/21+19/20*8/21
=19/20*(13/21+8/21)
=19/20*21/21
=19/20*1
=19/20
TK nha
tính bằng cách thuận tiện nhất:
a,7/4 x 11/21 + 11/21 x 5/4
b,23/14 x 6/13 -9/14 x 6/13
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
dhfwjrfsdkjbskndksjldkfnvkrfghnkjfhwkjfhwk fjghalkuerfgebkrfhjedhksejhlkjrhwejhrbhejrkfljrhebrhfejljrheklruhlwkuiytowhrjeklrjhgs.kjrw3ilvhwiort4jhkw3hr4kjthekjhrtlwejhtlrbvkwytgvkuwehltvgikehrltuiwyhlbiuvyhlitbhlwwncttolwy4twkthnwcjrhtw.ktvjhb q.tilhywcb.wcb.rvyhf.gvniyqt8ot8ot8ot8oy;weniweniweniweniweniweniweniweniweniweniweniwenifh.asklbghsbjkvhagkle/vm sgjfvbklhdfklagh/vekjjjr;klgbjal/bgujrvkll/anwko;tgj/vbal/skjgbkrvjgka.
iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiimmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
TÍNH NHANH
a) 3/16 + 4/15 + 5/16 + 1/15
b) 6/7 x 8/15 x 7/6 x 15/16
c) 19/20 x 13/21 + 9/20 x 8/21
d) (1+ 10/15 ) x (1+ 1/16 ) x ( 1+ 1/17 ) x ( 1+ 1/18 )
MINK ĐANG CẦN GẤP
a) \(\frac{3}{16}+\frac{4}{15}+\frac{5}{16}+\frac{1}{15}\)
\(=\left(\frac{3}{16}+\frac{5}{16}\right)+\left(\frac{4}{15}+\frac{1}{15}\right)\)
\(=\frac{1}{2}+\frac{1}{3}\)
\(=\frac{5}{6}\)
b) \(\frac{6}{7}\times\frac{8}{15}\times\frac{7}{6}\times\frac{15}{16}\)
\(=\left(\frac{6}{7}\times\frac{7}{6}\right)\times\left(\frac{8}{15}\times\frac{15}{16}\right)\)
\(=1\times\frac{1}{2}=\frac{1}{2}\)
c) \(\frac{19}{20}\times\frac{13}{21}+\frac{9}{20}\times\frac{8}{21}\)
\(=\frac{19\times13}{20\times21}+\frac{9\times8}{20\times21}\)
\(=\frac{247}{420}+\frac{72}{420}\)
\(=\frac{319}{420}\)
tích cho chị nha
câu a) = 5/6
câu b = 1/2
câu c = 319/420
tính bằng cách thuận tiện nhất:
a) 21/11 x 22/17 x 68/63=
b) 5/14 x 7/13 x 26/25
ai trả lời nhanh và đầy đủ nhất mk sẽ tick
a) 21/11 x 22/17 x 68/63 = 21 x 22 x 68/11 x 17 x 63 = 1 x 2 x4/1 x 1 x 3= 8/3
b) kết quả là 2/10 = 1/5
phần b làm như phần a
a) = \(\frac{21\cdot22\cdot68}{11\cdot17\cdot63}\)=\(\frac{1\cdot2\cdot4}{2\cdot1\cdot3}\)=\(\frac{4}{3}\)
b) = \(\frac{5\cdot7\cdot26}{14\cdot13\cdot25}\)=\(\frac{1\cdot1\cdot2}{2\cdot1\cdot5}\)=\(\frac{1}{5}\)
\(\frac{21}{11}\times\frac{22}{17}\times\frac{68}{63}\)
\(=\frac{21}{1}\times\frac{2}{1}\times\frac{4}{63}\)
\(=42\times\frac{4}{63}\)
\(=\frac{168}{63}\)
Bài 3. Một hình bình hành có chiều cao là 5/7 m. Độ dài đáy gấp hai lần chiều cao, cạnh bên là 6/7m. Tính chu vi của hình bình hành.
Bài 4. Tính bằng cách thuận tiện nhất
a) 7/4 x 11/21 + 11/21 x 5/4 =
b) 23/14 x 6/13 - 9/14 x 6/13 =
Bài 4:
a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)
b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)
Bài 3. Một hình bình hành có chiều cao là 5/7 m. Độ dài đáy gấp hai lần chiều cao, cạnh bên là 6/7m. Tính chu vi của hình bình hành.
Bài 4. Tính bằng cách thuận tiện nhất
a) 7/4 x 11/21 + 11/21 x 5/4 =
b) 23/14 x 6/13 - 9/14 x 6/13 =
Bài 4:
a: =11/21(7/4+5/4)=11/21x3=11/7
b: =6/13(23/14-9/14)=6/13
tính bằng cách thuận tiện nhất:
a) (3/13 x 17/29 ) x 29/34=
b) 4/21 x 19/33 x 25/42 x 19/33
gấp làm ơn
