99999999+999
9+99+999+9999+99999+999999+....+99999999
=9(1+11+111+1111+....+11111111)
=9.12345678
kết quả ghi re chẳng đc j nên để thế này cho gọn
#Học-tốt
- Đặt \(A=9+99+999+9999+99999+...+99999999\)
- Ta có: \(A=9+99+999+9999+99999+...+99999999\)
\(\Leftrightarrow A=9.\left(1+11+111+1111+11111+...+11111111\right)\)
\(\Leftrightarrow A=9.12345678\)
\(\Leftrightarrow A=111111102\)
Vậy \(A=111111102\)
!!@#!@ ^_^ Bn hok tốt nha ^_^ $!@#@!#
9+99+999+9999+99999+999999+9999999+99999999=?
9+99+999+9999+99999+999999+9999999+99999999+999999999+9999999999 = ?
9 . 1 + 9. 11 + 9.111 + 9.1111 + 9.11111 + 9.111111 + 9.1111111 + 9.11111111 + 9.111111111 + 9.1111111111
9+99+999+9999+99999+999999+9999999+99999999+999999999+9999999999
tính nhanh
= (10-1) + (100 -1) + (1000-1) + (10000-1) + ............+ (10000000000-1)
= ( 10+100+1000+10000+..........+10000000000) - (1+1+1+1+..........+1+1)
=11111111110 - 1.10
=1111111100
= (10-1) + (100 -1) + (1000-1) + (10000-1) + ............+ (10000000000-1)
= ( 10+100+1000+10000+..........+10000000000) - (1+1+1+1+..........+1+1)
=11111111110 - 1.10
=1111111100
99999999+99999999=
Tính tổng các chữ số của A biết:
A = 9 + 99 + 999 + .... + 99999999....
______________
2019 chữ số
Tổng các chữ số của A là:
\(1+2+3+...+2019=\frac{\left(2019+1\right)\times2019}{2}=2039190\)(số)
Đáp số 2039190 số
Rút gọn biểu thức :
(99999999+22222222222222222^2)(99999999-22222222222222222^2)
A=99999999...99999999(n cs 9)
CMR : A chia hết cho 9