Ta có : 1.3.5.7. ... .59

       = \(\frac{1.2.3.4.5.....58.59.60}{2.4.6.8.....58.60}\) 

       = \(\frac{\left(1.2.3.....30\right).\left(31.32.....60\right)}{\left(1.2.3.....30\right).2.2.....2}\)

       = \(\frac{31.32.....60}{2.2.....2}\)

       = \(\frac{31}{2}.\frac{32}{2}.....\frac{58}{2}.\frac{60}{2}\) ( đpcm )

Ta có:

31/2.32/2.33/2....60/2=31.32......60/2^30

=(31.32.33....60)(1.2.3....30)/2^30(1.2.3...30)

=(1.3.5...59)(2.4.6...60)/(2.4.6...60)=1.3.5...59

=>P=Q

nhớ ****

cái dòng 3, 4 mk ko hiểu sao 2^30.(1.2.3....30) lại bằng 2.4.6...60

ak hểu r

         \(\frac{31}{2}\)\(.\)\(\frac{32}{2}\)\(.\)\(\frac{33}{2}\)\(....\)\(\frac{60}{2}\)

\(=\)\(\left[\left(31.32.33....60\right)\right]\)\(.\)\(\left(\frac{1.2.3....30}{2^{30}}\right)\)\(.\)\(\left(1.2.3....30\right)\)

\(=\)\(\left[\frac{\left(1.3.5....59\right).\left(2.4.6....60\right)}{2.4.6....60}\right]\)\(=\)\(1.3.5....59\)

Vậy \(\frac{31}{2}\)\(.\)\(\frac{32}{2}\)\(.\)\(\frac{33}{2}\)\(....\)\(\frac{60}{2}\)\(=\)\(1.3.5....59\)

ta có:Đặt A= \(1.3.5.....59=\frac{1.2.3.4.....59.60}{2.4.6.....60}\)

=\(\frac{1.2.3.....59.60}{2^{30}.\left(1.2.3.....30\right)}=\frac{31.32.....59.60}{2^{30}}\)

= \(\frac{31}{2}.\frac{32}{2}.....\frac{59}{2}.\frac{60}{2}\)

vì \(\frac{31}{2}.\frac{32}{2}.....\frac{59}{2}.\frac{60}{2}\) = \(\frac{31}{2}.\frac{32}{2}.....\frac{59}{2}.\frac{60}{2}\)    

\(\Rightarrow\)A= \(\frac{31}{2}.\frac{32}{2}.....\frac{59}{2}.\frac{60}{2}\)

                                          ( Điều phải chứng minh)

toán nâng cao lớp 6 đấy bạn nha

sửu nhi

:>

Ta có :

\(\dfrac{31}{2}.\dfrac{32}{2}.\dfrac{33}{2}.....\dfrac{60}{2}=31.32.33.....\dfrac{60}{2^{30}}\)

(31.32.33....60)(1.2.3....30)/2³⁰(1.2.3....30)

= (1.3.5.....59)(2.4.6.....60 )/( 2.4.6....60 ) = 1.3.5....59

\(\Rightarrow P=Q\)

Sai đề,phải là 31/2.32/2..60/2 chứ

31/2.32/2.33/2....60/2=(31.32.33...60)/2³⁰

=[(31.32.33...60).(1.2.3...30)]/2³⁰.(1.2.3...30)

=[(1.3.5...59).(2.4.6....60)]/(2.4.6...60)=1.3.5...59