( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x ( 126 x 127127 - 127127 x 126 )

= ( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x [( 126 - 126 ) x 127127 ]

= ( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x ( 0 x 127127 )

= ( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x 0

= 0

Tk nhé !

#tksnhieu

( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x ( 126 x 127127 - 127127 x 126 )

= ( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x [( 126 - 126 ) x 127127 ]

= ( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x ( 0 x 127127 )

= ( 1 + 2 + 3 + 4 + 5 + ... + 2018 ) x 0

= 0

Ta có:

  (1+3+5+...+2005)x(125125x127-127127x125)

=(1+3+5+...+2005)x(125x1001x127-127x1001x125)

=(1+3+5+...+2005)x0

=0

a+b=10

a+c=25

b+c=18

a+b=10

a+c=25

b+c=18

a+b=10

a+c=25

b+c=18

a+b=10

a+c=25

b+c=18

a+b=10

a+c=25

b+c=18

a+b=10

a+c=25

b+c=18

a+b=10

a+c=25

b+c=18

thank you VRCT _gnk_Thùy Linh

( 1 + 3 + 5 +.....+ 2005) * ( 125125 * 127 - 127127 * 125 )

= ( 1+3+5+....+2005) * ( 125 * 1001 * 127 - 127 * 1001 * 125)

= (1 +3+5+....+2005) * 0

= 0

k cho mình nha bạn...!

Ta có:(1+3+5+...+2005)x(125125x127-127127x125)

       =(1+3+5+...+2005)x(125x1001x127-127x1001x125)

       =(1+3+5+...+2005)x0

       =0

   ( 1 + 3 + 5 + ...+ 2005 )  . ( 125125 . 127 - 127127 . 125 )

= ( 1 + 3 + 5 + ... + 2005 ) .  ( 125 . 1001 x 127 - 127 x 1001 x 125 )

= ( 1 + 3 + 5 + .. + 2005 ) .          0

=   0

[1+3+5+7+...+2011] x [125125 x 127-127127 x 125]

=2028096 x0

=0

Vay phep tinh tren co ket qua = 0

Ta có :

1+3+5+7+...+2017

=> Có số số hạng là :

(2017-1):2+=1009 ( số )

Tổng của dãy : 1+3+5+7+...+2017 là :

(2017+1).1009:2=1018081

Dãy  125125 * 127 - 127127 *125 =0

=> 

( 1 + 3 + 5 + ... + 2015 + 2017) * ( 125125 * 127 - 127127 *125 ) = 0

(1+3+5+7+…+2003+2005)×(125125×127-127127×125)=
(1+3+5+7+….+2003+2005)×(125×101×127- 127×101×125)
= (1+3+5+7+…+2003+2005)×0
=0

Xin lỗi

(1+3+5+…+2015+2017)×(125125×127-127127×125)=
(1+3+5+….+2015+2017)×(125×101×127- 127×101×125)
= (1+3+5+…+2015+2017)×0
=0

(1+3+5+....+2011)x(125125x127-127127x125)

Ta có:

=(125125x127-127127x125)

=1001x125x127-1001x127x125

=0

Vậy:(1+3+5+....+2011)x(125125x127-127127x125)=(1+3+5+....+2011)x0=0

Đề bị sai hay sao vậy, phải là : (1+3+5+7+...+2011)*(125125127-127127*125) mới đúng

Đề: Tính

(1 + 3 + 5 + ... + 2007 + 2009 + 2011) x (125125 x 127 - 127127 x 125)

= (1 + 3 + 5 + ... + 2007 + 2009 + 2011) x 0

= 0

(1+3+5+....+2007+2009+2011)×(15890875-15890875)

(1+3+5+.....+2007+2009+2011)×0

(1+3+5+.....+2007+2009+2011)

(1 + 3 + 5 + .... +2007 + 2009 + 2011 ) x (125125 x 127 - 127127 x 125 )

= ( 1 + 3 + 5 +..................+ 2007 + 2009 + 2011 ) x ( 15890875 - 15890875 )

= ( 1 + 3 + 5 +...................+ 2007 + 2009 + 2011 ) x 0

= 0

Chúc bạn học tốt!!!

\(\left(1+3+5+7+...+2007+2009+2011\right)\left(125125\cdot127-127127\cdot125\right)\)

\(=\left(1+3+5+...+2007+2009+2011\right)\left(125\cdot127\cdot1001-127\cdot125\cdot1001\right)\)

\(=\left(1+3+5+...+2007+2009+2011\right)\cdot0\)

\(=0\)

 =( 1 + 3 + 5 + ............. + 2007 + 2009 + 2011 ) x 0 

 = 0 

HỌC TỐT

K VÀ KN NẾU CÓ THỂ

(2+4+6+...+2017+2018)x(125125x127-127127x125)

=(2+4+6+...+2018)x(125x1001x127-127127x125)

=(2+4+6+..+2018)x(125x127127-127127x125)

=(2+4+6+...+2018)x0

=0

k mk nha!!

Chuc bn hok tot

cảm ơn nha

mn k cho mk nha!!!